This question already has an answer here:
Ruby, no implicit conversion of Symbol into Integer
(1 answer)
Closed 6 years ago.
I am new to ruby, and have no idea, how to fix this error. when i run my script containing the code below, i always get the error: 'no implicit conversion of Symbol into Integer. I think the Problem is in the lines #killProc..., #Name=..., and #working_directory.
Can you tell me whats wrong?
Thanks for your help
class RubyCommand
include Patir::Command
attr_reader :cmd,:working_directory,:killProc
def initialize params,&block
#killProc=params[:killProc]
#name=params[:name]
#working_directory=params[working_directory]||"."
if block_given?
#cmd=block
else
raise "You Need to provide a block"
end
end
end
Pretty sure you're passing an array instead of a hash. You should call it like this:
RubyCommand.new({killProc:1,name:"test"})
Related
This question already has answers here:
Ruby Print Inject Do Syntax
(3 answers)
Closed 7 years ago.
Let's say I have the following (working) pseudo-code:
puts results.fields.inject('') { |string, key|
lengths[key] = calculate_length(key)
string << format(key)
}
Following the ruby-style-guide I should
Omit parentheses for 'keyword methods', i.e. puts, (which would create }) or end) anyway)
Use do...end for multi-line blocks
However, when replacing {...} with do...end it raises
undefined method `' for :title:Symbol (NoMethodError)
Therefore, is it possible to refactor this code without violenting the guideline?
There is a difference in precedence between {} and do end
If you use do end the block is associated with the puts statement, whereas the braces are associated with the results.field.inject('')
If you want to use do end then you have to remove the ambiguity of association by parentheses. It's one of those "gotchas" where the guidelines are recognized as guidelines, not absolute rules.
See also this answer...
In Ruby, why is a method invocation not able to be treated as a unit when "do" and "end" is used?
This question already has answers here:
Can you supply arguments to the map(&:method) syntax in Ruby?
(9 answers)
Closed 8 years ago.
I wonder, isn't it possible to call a method using & operator with parameters?
items.each &:my_proc # ok
items.each &:my_proc(123, "456") # ops!
No, it's not possible. Use full form.
items.each{|i| i.my_proc(123, '456')}
Look at the source of Symbol#to_proc for the "why".
You can use a bit of trickery and acheive something similar:
class Symbol
def [](*args)
proc{|obj| obj.send(self, *args) }
end
end
[123.456, 234.567].map(&:round[2])
#=> [123.46, 234.57]
I highly discourage the use in production code though, since gems etc may rely on Symbol#[]. This is just a fun thing to play around with ;-)
This question already has an answer here:
naked asterisk as parameter in method definition: def f(*)
(1 answer)
Closed 8 years ago.
In the rails code I came across following method definition def initialize(*)
I understand what def foo(*a) means but can't figure out significance of omitting identifier name after *. How do you access any arguments passed to this method?
Here's my guess.
It works because of second line:
def initialize(*)
super
...
end
So the method receives arbitrary number of arguments and passes all of them to super(as you know, super without arguments means take all arguments from original method).
And then in this case the names for arguments are not required.
This question already has an answer here:
Closed 10 years ago.
Possible Duplicate:
What do you call the &: operator in Ruby?
I see '.map(&:chomp)' all the time
I know what chomp and map do, but I want to know what &: does and I'd like to know why I can't find it on the web after 30 minutes of googling.....
It's Symbol#to_proc, and it turns the symbol into a proc which attempts to invoke the given method on its argument, returning the result.
x = :reverse.to_proc
x.call("asdf") # "fdsa", like calling "asdf".reverse
In your case, .map(&:chomp) is equivalent to .map { |x| x.chomp }.
If you can't find it by Googling, it's because you're Googling the wrong thing. It's a well-known Ruby idiom.
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
What does map(&:name) mean in Ruby?
I was watching a railscast and saw this code.
[Category, Product].(&:delete_all)
In regards to clearing a database.
I asked about the line in IRC and was told
(&:delete_all)
was a shortcut for
{|model| model.delete_all}
I tested this with the following
class ClassOne
def class_method
puts 1
end
end
class ClassTwo
def class_method
puts 2
end
end
[ClassOne, ClassTwo].each(&:class_method)
I received an error saying
Wrong Argument type Symbol (expected Proc)
I also tried
one = ClassOne.new
two = ClassTwo.new
[one, two].each(&:class_method)
But that still failed.
If I modified it to read
[one, two].each{|model| model.class_method}
Everything worked as expected.
So, what does &:delete_all actually do? The docs say delete_all is a method, so I am confused as to what is going on here.
This relies upon a Ruby 1.9 extension that can be done in 1.8 by including the following:
class Symbol
def to_proc
proc { |obj, *args| obj.send(self, *args) }
end
end
I believe Rails defines this in ActiveSupport.
It's some Rails specific patching of Ruby, symbol to proc.