Plsql Program using control statements - oracle

Question

I have a table like "Emp_Info", For the below output i have used "two" SELECT Statements, I want work that using ONE SELECT STATEMENT.
select count(*) into cnt
from emp_info t
where upper(trim(t.email)) = upper(trim(field1value))
and t.company_id = companyId;
select
(case when cnt1 > 0 then 'YES' else 'NO' end) into val_acc
from (
select count(*) cnt1 from
emp_info t
where upper(trim(t.email)) = upper(trim(field1value))
and (t.account_expiry_dt is null or t.account_expiry_dt >= sysdate)
and t.company_id = companyId
);
if cnt = 0 then
raise_application_error(-20002, 'User does not exist');
elsif cnt > 1 then
raise_application_error(-20003, 'Duplicate records found');
elsif val_acc = 'NO' then
raise_application_error(-20004, 'Account has expired');
else
/* some logic */
end if;
end;

Answer 1

may be this help you
select count(*),
CASE WHEN
sum( CASE when t.account_expiry_dt is null or t.account_expiry_dt >= sysdate then 1 else 0 end) > 0 then 'YES'
else 'NO'
END
into cnt, val_acc
from emp_info t
where upper(trim(t.email)) = upper(trim(field1value))
and t.company_id = companyId;
simple demo:
with emp_info(login,username) as (select 'test', 'test' from dual union
select 'TEst', 'TEst' from dual )
select count(*) emp_count,
CASE when sum( CASE WHEN login like '%st%' then 1 else 0 end) > 0 then 'Y' else 'N' end emp_flag,
sum( CASE WHEN login like '%st%' then 1 else 0 end) emp_flag_count,
CASE when sum( CASE WHEN login like '%te%' then 1 else 0 end) > 0 then 'Y' else 'N' end emp_flag1,
sum( CASE WHEN login like '%te%' then 1 else 0 end) emp_flag_count1,
CASE when sum( CASE WHEN login like '%TE%' then 1 else 0 end) > 0 then 'Y' else 'N' end emp_flag2,
sum( CASE WHEN login like '%TE%' then 1 else 0 end) emp_flag_count2
from emp_info
answer if it helped you