I have category and article tables, they are in a many to many relationship. i have the relationships set up on the models.
How can I get all articles where a category id is = 1?
I've tried:
Article::whereHas('category', function ($query) use ($id) {
$query->where('category_id', $id);
})->get();
The above works, but seems clunky, is there a more efficient way in eloquent to do this?
You can use eager loading technique.
Article::with(['category', function ($query) use ($id) {
$query->where('category_id', $id);
}])->get();
The following groupBy code is assuming that Category::find($id)->articles is not an option for whatever reason.
What about groupBy?
Article::groupBy('category')
->having('category', $id)
->get();
whereHas will return articles that match that condition, but won’t filter articles then fetched by the same conditions. You could therefore create an anonymous function that contains the constraints, and pass it to both the whereHas and with methods:
$filter = function ($query) use ($categoryId) {
$query->where('category_id', '=', $categoryId);
};
Article::whereHas('category', $filter)
->with(['category' => $filter])
->get();
Related
My Code
$videos = ExamVideo::with([
'user' => function ($query) use ($request) {
$query->where('user_name', 'like', '%'.$request->search.'%');
}
])->where('is_marked','=', 0)->get();
return $videos;
I want to get only those videos where is_marked is zero & it's relation user_name match my search result.
But I get all the videos which marked is zero.
The with method is only for eager loading and not used to filter your records.
You can accomplish what you want with the whereHas method which will perform a query on the relation:
$videos = ExamVideo::whereHas('user', function ($query) use ($request) {
$query->where('user_name', 'like', "%{$request->search}%");
})->where('is_marked', false)->get();
For more information about whereHas: https://laravel.com/docs/6.x/eloquent-relationships#querying-relationship-existence
I want to page the relation articles. The correct number is displayed but not in the collection, for example "first page" or "to last".
$articles = Categories::where('slug', $categorie)->with(['articles' => function ($query) use ($default_count, $default_sort) {
$query->orderBy('price', $default_sort)
->with('contents')
->paginate(2);
}])->first();
What am I missing here?
Try flipping it around so that Article is the top level:
$articles = Article::with('contents')
->whereHas('category', function ($query) use ($categorie) {
$query->where('slug', $categorie);
})
->orderBy('price', $default_sort)
->paginate(2);
This assumes that you have the category relationship set up on Article as well.
i think you want result some like that
Article::whereHas('category', function ($query) use ($categories) {
$query->where('slug', $categories);
})
->with('contents')
->orderBy('price', $default_sort)
->paginate(2);
I have two tables with belongsToMany relation: message_topics and users
The pivot table is message_topics_users and contains 2 columns: message_id and user_id.
In table message_topics, I have a field called sender_id
I'm trying to write the correct eloquent syntax to get all the records:
where message_topics.sender_id = $user_id
OR Message_topics_users.receiver_id = $user_id
I tried many things, like for instance:
$topics = MessageTopic::where('sender_id', $user_id)
->wherePivot('receiver_id', $user_id)->orderBy('sent_at','desc')->get();
Any idea?
You can use the whereHas method (or in this case the orWhereHas method):
$topics = MessageTopic::where('sender_id', $user_id)
->orWhereHas('users', function ($query) use ($user_id) {
$query->where('id', $user_id);
})
->orderBy('sent_at', 'desc')
->get();
I'm assuming you have two relationships from the topics? Since it's too arbitrary to use both columns and the same relationship... Like this
//On your MessageTopic model
public function sender(){
return $this->belongsToMany('App\User', 'message_topics_users', 'message_id', 'sender_id');
}
public function receiver(){
return $this->belongsToMany('App\User', 'message_topics_users', 'message_id', 'receiver_id'));
}
Then you can use whereHas and orWhereHas like this:
//Again assuming you have your User model loaded as $user
$topics = App\Topic::whereHas('sender', function($q) use($user){
$q->where('sender_id', '=', $user->id);
})
->orWhereHas('receiver', function($q) use($user){
$q->where('receiver_id', '=', $user->id
})
->orderByDesc('sent_at')
->get();
whereHas and orWhereHas both query the model (MessageTopic in this case) checking for the existence of the specified relationship (App\Topic::whereHas('sender')...). They also allow you to pass the constraint that you're looking for (function($q) use($user){ $q->... })
So it is basically saying "Give me ONLY the MessageTopics that have a Sender or Receiver with the id $user->id"
I have two models Teacher and Category. These two have Many to Many relationship.
I want to get those teachers who have one category equal to "OLevels". Which method of eloquent is used for it or is there any other way I can get it?
Is there anyway to get it as:
$teachers = Teacher::where('category', '=', 'OLevels')->get();
You can use whereHas for that:
$category = 'OLevels';
$teachers = Teacher::whereHas('category', function($q) use ($category){
$q->where('name', $category);
})->get();
You could make use of eager loading with constraints
$teachers = Teacher::with(['category' => function($query)
{
$query->where('category', '=', 'OLevels');
}])->get();
Further info in the documentation.
here is link to my database schema:
How can I get all topics from the blogs to which the user is subscribed using his id? I use Eloquent ORM.
I have added the following lines to my User model:
public function blogs()
{
return $this->belongsToMany('Blog', 'blog_subscriptions');
}
And then requested in the controller
User::find(1)->blogs; // User id is hardcoded
With that I got all blogs to which the user is subscribed.
And now I am stuck on how to get the topics of those blogs.
Assuming relations:
// User
belongsToMany('Blog', 'user_subscriptions')
// Blog
belongsToMany('User', 'user_subscriptions')
hasMany('Topic')
// Topic
belongsTo('Blog')
1 My way, that will work with any relation, no matter how deeply nested:
User::with(['blogs.topics' => function ($q) use (&$topics) {
$topics = $q->get()->unique();
}])->find($userId);
2 Eloquent standard methods:
$topics = Topic::whereHas('blog', function ($q) use ($userId) {
$q->whereHas('users', function ($q) use ($userId) {
$q->where('users.id', $userId);
});
})->get();
// or
$user = User::find($userId);
foreach ($user->blogs as $blog)
{
$blog->topics; // collection of topics for every single blog
}
3 Joins:
$topics = Topic::join('blogs', 'topics.blog_id', '=', 'blogs.id')
->join('user_subscriptions as us', function ($j) use ($userId) {
$j->on('us.blog_id', '=', 'blogs.id')
->where('us.user_id', '=', $userId);
})->get(['topics.*']);
Mind that last solution will rely on your pivot data consistency. That said, if you can't be sure, that there are no redundant entries in user_subscriptions (eg. blog or user has been deleted but the pivot entry remains), then you need to further join users as well.
I am new to laravel and I don't have the possibility of test this, but I had a similar need and solved it with something like this:
DB::Query('topics')->join('blogs', 'blogs.id', '=', 'topics.blog_id')
->join('blog_subscriptions', 'blogs.id', '=', 'blog_subscriptions.blog_id')
->select('name.id','table.email')
->where('blog_subscriptions.user_id', '=', $user_id);