How import custom class in controller Laravel? - laravel

Question

I have created a new directory Library in root of Laravel.
Inside I put the file with class:
class My {
//
}
So, in controller Laravel I try to get access to this class:
App\Library\My
But Laravel does not determine this path.
This is my code:
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Requests;
use View;
use App\Library\My;
class HomeController extends Controller
{
//
}

Answer 1

A complete and functional example based on the posts here:
1 - Folder and file - Create a folder under app/, in this example we will create a folder called Library.
We will also inside the folder create a file with the name of your class, here we will create a class called My.
So we will have app/Library/My.php
2 - Class and method - Now, for testing, inside the class create a static method called myMethod
<?php
namespace App\Library;
class My
{
public static function myMethod()
{
return 'it\'s work!';
}
}
3 - Controller - Now at the beginning of the Controller, we will declare the namespace of your Class with use:
<?php
namespace App\Http\Controllers;
use App\Library\My;
//rest of the controller code
Finally, to create an instance of the My class, in Controller, a new statement must be used:
//rest of the controller code
public function index()
{
$whatever = new My;
return $whatever::myMethod();
}

Answer 2

As above, make sure it is placed in the App directory and make sure it is properly namespaced e.g.
<?php
$fOne = new \App\library\functions;
$isOk = ($fOne->isOk());
?>

Answer 3

You should create Library folder inside app folder
namespace App\Library\My
app folder is alrdy used psr-4
In your controller
use App\Library\My as My
It's work for me. Hope this answer is helpful

Answer 4

You have to properly namespace your every class.
So you can import your class with use keyword, like so
use App\Library\My;
....
$my = new My();
Or if you've conflicting class name then you can use as keyword to alias the classname while importing
use App\Library\My as MySecond;
....
$my = new MySecond();
And if you want to directly access your class within the method then you can access it like so.
$my = new \App\Library\My();
Note: The leading \ means App was declared in the global scope.