Adding quotes automatically on input - python-2.x

So if I want an user to input his Path he has to add quotes manually.
So it would look like that:
Path = input('Enter Path:\n')
And how can I add quotes now so the user can write his path in between them?
Like that: " " <---- and in between the quotes the user can enter his path.

Assuming Python 2 (as this question shouldn't come up in Python 3) --
Use raw_input() instead, and literal quotes aren't needed.

Related

Is there a way I can print a statement with an exclamation mark and a quotation mark?

I'm trying to print a statement that looks like this: "Oh no!",
but I keep getting: Oh no! without the quotes.
This is the code I've been using:
print(exclamation.capitalize() + ("!") , "I yelled" + ".")
Please what am I missing?
In Python 3.6+, you can use f-strings to embed statements directly in the string.
Also, if you use single quotes to capture the string, you can use double-quotes in the string and they will print without needing to be escaped.
print(f'"{exclamation.capitalize()}"! I yelled.')

Search string for trailing quote character and trim it?

I'm trying to search a string (entered by the user when prompted for a path) for a trailing quote and delete it if found.
The problem: I have a bat file that prompts the user to enter a filename and path (the first is typically done via drag/drop.) If the user enters a destination path enclosed in quotes because it contains spaces, my resulting command will look like this: compress.exe "c:\source path\"destination.zip"
That extra quote in the middle needs to go. I've found plenty of ways to search a file for a string, and I found this post here on StackOverflow that seems to apply, but doesn't seem to work in my situation.
I tried the command at the above linked path, telling it to search for \" instead of bcd, but the code expects the string it's searching to have been passed to it (as a switch) upon execution, and when I try to modify the command to search srcpath instead, the bat fails. I also tried this:
if "!srcpath:~-1"=="\"" set srcpath=!srcpath:~0,-1!
This results in: "The syntax of the command is incorrect."
How can I search a string for a trailing quote and trim it? Every method I can find doesn't seem to work when the character being searched for is the quote (slash quote: \").
I use a SLOPPY batch trick when working with paths just for this reason.
There are more elegant ways but this works just as well and I don't ever have to remember how I pulled it off.
First of all, 90% of the time.. we just want ALL quotes stripped.. that would just be:
set srcpath=%srcpath:"=%
Then tack quotes on to the front and back of your new concatenated path string.
But if you REALLY only want the trailing one.. here is my stupid bash trick..
1. Add a "? to the end of your string
2. Then delete ""? from that string
3. Then delete "? from that string
Wella! Never fails!
The trick here is that a question mark isn't a valid path char.
:: SAMPLE -- Just a trailing quote removed
set srcpath="c:\source path\"
set srcpath=%srcpath%"?
set srcpath=%srcpath:""?=%
set srcpath=%srcpath:"?=%
echo srcpath=%srcpath%
::You can use the SAME TRICK to remove a trailing backslash
Would this work for you?
SET /P "%SRCPATH=Enter the source path "
ECHO %SRCPATH%
ECHO %SRCPATH:"=%

change file extension with a ruby script

I'm trying to change the exstension of a file passing the arguments by console
system = "rename" , "'s/\#{ARGV[0]}$/\#{ARGV[1]}'", "*#{ARGV[1]}"
The code is correct because it works on console but when I put it in a script I have trouble with
s/\#
because it appears in pink and the console does not get it.
you don't want to send literal single quotes, so remove them.
you want to remove the backslashes so you let Ruby evaluate those expressions.
you're missing the trailing slash.
what's that equal sign doing?
did you want ARGV[0] in the last argument to rename, instead of ARGV[1]?
you want to use * wildcard, which requires a shell to expand into a list of files, which means you can't use the list form of system
Try
system "/usr/bin/rename -n 's/#{ARGV[0]}$/#{ARGV[1]}/' *#{ARGV[0]}"
Remove the -n option if it looks like you're going to rename the way you want.
And, of course, you don't need to call out to the shell for this:
Dir.glob("*#{ARGV[0]}").each {|fname|
newname = fname.sub(/#{ARGV[0]}$/, ARGV[1])
File.rename(fname, newname)
}

Bash variable character replacement ends up to an empty string or a command not valid

I am working on a shell script to retrieve variable content from a JSON file via JQ. The JSON file is in string format (no matter whether this is a real string or a number) and to retrieve the variable in my bash script I did something like this
my_domain=$(cat /vagrant/data_bags/config.json | jq ."app"[0]."domain")
The above code once echoed results in "mydomain" with a beginning and a trailing quote sign. I though this was a normal behaviour of the echo command. However, while concatenating my variable with another shell command the system raise an error. For instance, the following command
cp /vagrant/public_html/index.php "/var/www/"+$my_domain+"/index.php"
fails with the following error
cp: cannot create regular file `/var/www/+"mydomain"+/index.php': No such file or directory
At this stage, I wasn't able to identify whether it's me doing the wrong concatenation with the plus sign or the variable is effectively including the quotes that in any case will end up generating an error.
I have tried to replace the quotes in my variable, but I ended up getting the system raising a "Command not found" error.
Can somebody suggest what am I doing wrong?
+ is not used for string concatenation in bash (or perl, or php). Just:
cp /vagrant/public_html/index.php "/var/www/$my_domain/index.php"
Embedding a variable inside a double-quoted text string is known as interpolation, and is one of the reasons why we need the $ prefix, to indicate that this is a variable. Interpolation is specifically not done inside single quoted strings.
Braces ${my_domain} are not required because the / directory separators are not valid characters in a variable name, so there is no ambiguity.
For example:
var='thing'
echo "Give me your ${var}s" # Correct, appends an 's' after 'thing'
echo "Give me your $vars" # incorrect, looks for a variable called vars.
If a variable (like 'vars') does not exist then (by default) it will not complain, it will just give an empty string. Braces (graph brackets) are required more in c-shell (csh or tcsh) because of additional syntax for modifying variables, which involves special trailing characters.
You don't need to use + to concatenate string in bash, change your command to
cp /vagrant/public_html/index.php "/var/www/"${my_domain}"/index.php"
My problem was not related only to the wrong concatenation, but also to the JQ library that after parsing the value from the JSon file was returning text between quotes.
In order to avoid JQ doing this, just add the -rawoutput parameter when calling JQ.

Shell script input containing asterisk

How do I write a shell script (bash on HPUX) that receives a string as an argument containing an asterisk?
e.g. myscript my_db_name "SELECT * FROM table;"
The asterisk gets expanded to all the file names in the current directory, also if I assign a variable like this.
DB_QUERY="$2"
echo $DB_QUERY
The asterisk "*" is not the only character you have to watch out for, there's lots of other shell meta-charaters that can cause problems, like < > $ | ; &
The simple answer is always to put your arguments in quotes (that's the double-quote, " ) when you don't know what they might contain.
For your example, you should write:
DB_QUERY="$2"
echo "$DB_QUERY"
It starts getting awkward when you want your argument to be used as multiple parameters or you start using eval, but you can ask about that separately.
You always need to put double quotes around a variable reference if you want to prevent it from triggering filename expansion. So, in your example, use:
DB_QUERY="$2"
echo "$DB_QUERY"
In the first example, use single quotes:
myscript my_db_name 'SELECT * FROM table;'
In the second example, use double quotes:
echo "$DB_QUERY"

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