Getting “./a.out” terminated by signal SIGSEGV (Address boundary error) - c++11

Question

I'm writing a program that splits any two numbers. The problem is whenever I run the program I get an error that says:
“./a.out” terminated by signal SIGSEGV (Address boundary error)
And that error occurs at the lines:
a = std::stoi(temp_vec.front());
b = std::stoi(temp_vec.back());
and
c = std::stoi(temp_vec.front());
d = std::stoi(temp_vec.back());
Here's my program:
#include <iostream>
#include <string>
#include <vector>
void split_number(std::vector<std::string> vect, int x);
int main()
{
int x = 0, y = 0, a = 0, b = 0, c = 0, d = 0;
std::vector<std::string> temp_vec;
std::cout << "Enter x: ";
std::cin >> x;
std::cout << "Enter y: ";
std::cin >> y;
split_number(temp_vec, x);
a = std::stoi(temp_vec.front());
b = std::stoi(temp_vec.back());
split_number(temp_vec, y);
c = std::stoi(temp_vec.front());
d = std::stoi(temp_vec.back());
return 0;
}
void split_number(std::vector<std::string> vect, int x)
{
vect.clear();
//1. convert x to string
std::string temp_str = std::to_string(x);
//2. calculate length
std::size_t len = temp_str.length();
std::size_t delm = 0;
if(len % 2 == 0) {
delm = len / 2;
} else {
delm = (len + 1) / 2;
}
//3. populate vector
vect.push_back(temp_str.substr(0, delm));
vect.push_back(temp_str.substr(delm + 1));
}
Any help would be appreciated.

Answer 1

You get the segmentation fault because your vector is empty. Your vector is empty because you pass a copy of your initial vector to split_number(). The copy is passed because the signature of split_number() says it requires a copy. Change it to:
void split_number(std::vector<std::string> & vect, int x)
The ampersand makes the vect parameter a reference parameter, and modifications will show in the calling code.