I'm using spring boot with spring data, specifically the class PagingAndSortingRepository that extends CrudRepository.
I need a query which returns all entries of a table if matches either of the four lists ignoring it when it is null (or empty).
If I use findByTypeInAndLocaleInAndCategoryInAndTagIn and one of the lists is empty, the result is empty as well. So I ended up writing several finders and depending on which lists are empty using a different one. Is it possible to combine this in one finder?
So e.g. if I use findByTypeAndLocale I'd like to match all values of type if the list type is empty.
Happy about any hints.
#Repository
public interface FeedRepository extends PagingAndSortingRepository<FeedEntry, Long>, JpaSpecificationExecutor<FeedEntry> {
public List<FeedEntry> findByGuid(String guid);
public Page<FeedEntry> findAll(Pageable pageable);
public Page<FeedEntry> findByLocale(List<LocaleEnum> type, Pageable pageable);
public Page<FeedEntry> findByType(List<FeedTypeEnum> type, Pageable pageable);
public Page<FeedEntry> findByTypeAndLocale(FeedTypeEnum type, LocaleEnum locale, Pageable pageable);
public Page<FeedEntry> findByTypeInAndLocaleIn(List<FeedTypeEnum> type,List<LocaleEnum> locale, Pageable pageable);
public Page<FeedEntry> findByTypeInAndLocaleInAndCategoryIn(List<FeedTypeEnum> type,List<LocaleEnum> locale, List<String> category, Pageable pageable);
public Page<FeedEntry> findByTypeInAndLocaleInAndTagIn(List<FeedTypeEnum> type,List<LocaleEnum> locale, List<String> tag, Pageable pageable);
public Page<FeedEntry> findByTypeInAndLocaleInAndCategoryInAndTagIn(List<FeedTypeEnum> type,List<LocaleEnum> locale, List<String> category, List<String> tag, Pageable pageable);
}
You cannot do it as you are doing. If the list is empty means there isn't any value which matches with your condition query.
To do what you are looking for you need to do it with QBE (Query By example) which is compatible with CrudRepository
QBE doc
Why? You need a dynamic query and as the doc says:
Query by Example (QBE) is a user-friendly querying technique with a
simple interface. It allows dynamic query creation and does not
require to write queries containing field names. In fact, Query by
Example does not require to write queries using store-specific query
languages at all.
An example of the doc:
public interface PersonRepository extends JpaRepository<Person, String> { … }
public class PersonService {
#Autowired PersonRepository personRepository;
public List<Person> findPeople(Person probe) {
return personRepository.findAll(Example.of(probe));
}
}
**Making example for your case...
I'm affraid it is not possible at the moment.
IMHO the best way you can achieve your goal is to use Spring Data JPA Specifications (http://docs.spring.io/spring-data/jpa/docs/1.10.2.RELEASE/reference/html/#specifications) and manually check every parameter for not null value...
Related
I am using Spring Framework as my back end
I have define know as Entity class The Entity class know contain 5 Fields
Below is the class , The code below dose not have setter getter part to make shorter and cleaner
#Entity
#Table(name="TblKnow")
public class Know {
#Id
private Double idKnow;
private String SubjectKnow;
private String BodyKnow;
private String ImgKnow;
private double CountView;
In JpaRepository interface i want to only query two column not all of columns.
public interface KnowRepository extends JpaRepository<Know,Double> {
#Query("SELECT idKnow,SubjectKnow FROM Know")
public Page<Know> findCByOrderByIdKnowDesc(Pageable pageable);
Problem: i try to run but i get below exception
java.lang.IllegalArgumentException: Cannot create TypedQuery for query with more than one return using requested result type [java.lang.Long]
But if i use without below query it is fine
public Page<Know> findAllByOrderByIdKnowDesc(Pageable pageable);
You can create a custom constructor and use that to select only some fields in JPA query.
public Know(Double idKnow, String SubjectKnow) {
this.idKnow = idKnow;
this.SubjectKnow = SubjectKnow;
}
And the use this constructor in JPA query. Make sure you use complete path of class with package.
#Query("SELECT NEW packagePath.Know(idKnow,SubjectKnow) FROM Know")
query :
public Page<Know> findAllByOrderByIdKnowDesc(Pageable pageable);
works dut to you select Know objects with fields that are mapped correct into Know class (and after wrapped into Page).
with query :
#Query("SELECT idKnow,SubjectKnow FROM Know")
public Page<Know> findCByOrderByIdKnowDesc(Pageable pageable);
returns some custome bean/object that spring data can't map in correct way into Know class (as you declared it as expected return class wrapped into Page). add counstructor into Know with idKnow,SubjectKnow fields , or you can wrap it into some DTO with idKnow,SubjectKnow fields.
I am trying to use pagination with QueryDSL - using the com.mysema.querydsl package.
All my Querydsl query types look like this -
#Generated("com.mysema.query.codegen.EntitySerializer")
public class QCountry extends EntityPathBase<Country> {...}
Currently, my repository implementation class looks something like this -
#Override
public Page<Country> findPaginatedCountries(String country, Optional<String> status, Pageable pageable) {
QCountry qCountry= QCountry.someObject;
QActiveCountry qActiveCountry = QActiveCountry.activeCountry;
JPAQuery jpaQuery = new JPAQuery(entityManager);
QueryBase queryBase = jpaQuery.from(qCountry).innerJoin(qActiveCountry).fetch()
.where(qCountry.codeLeft.country.upper().eq(country.toUpperCase()))
.where(qCountry.codeRight.country.upper().eq(country.toUpperCase()));
if(status.isPresent()){
queryBase = queryBase.where(qActiveCountry.id(qCountry.active.id))
.where(qActiveCountry.status.upper().eq(status.get().toUpperCase()));
}
.......}
Now, I want this dynamic query to return a paginated response. I want to use Spring's pagination to do that and not manually set offset, size etc.
I know I can use QueryDslRepositorySupport class - as implemented here - https://github.com/keke77/spring-data-jpa-sample/blob/master/spring-data-jpa/src/main/java/com/gmind7/bakery/employee/EmployeeRepositoryImpl.java
Sample code from the above link -
#Override
public Page<Employees> QFindByOfficeCode(long officeCode, Pageable pageable) {
//JPAQuery query = new JPAQuery(em);
JPQLQuery query = from(QEmployees.employees).where(QEmployees.employees.officeCode.eq(officeCode));
query = super.getQuerydsl().applyPagination(pageable, query);
SearchResults<Employees> entitys = query.listResults(QEmployees.employees);
return new PageImpl<Employees>(entitys.getResults(), pageable, entitys.getTotal());
}
However, to do that -
I need to pass JPQLQuery object to the applyPagination method. How can I do that without changing my code (Ofcourse, the repository class will extend QueryDslRepositorySupport class). Currently, I am using JPAQuery as you can see.
OR
I probably need to change my QueryDSL types by having them extend EntityPath instead of EntityPathBase so that I can use JPQLQuery.from() to generate the query and then use the applyPagination method, which requires a JPQLQuery object. However, my Q classes are extending EntityPathBase class instead. Should I be use com.querydsl package instead of com.mysemsa.querydsl package to generate query types?
OR
Other option is to use the following - http://docs.spring.io/spring-data/commons/docs/current/api/org/springframework/data/querydsl/QueryDslPredicateExecutor.html#findAll-com.querydsl.core.types.Predicate-org.springframework.data.domain.Pageable-
Code snippet below -
Page<T> page = QueryDslPredicateExecutor.findAll(org.springframework.data.querydsl.Predicate predicate, Pageable pageable)
However, I am making joins between two tables and then filtering results with a where clause (as you can see above in my code). How can I pass a predicate object in the findAll method above? Not sure how to include a join in it.
Please let me know if the problem is not clear, I can add more details.
EDIT: There is a many to one relationship between Country and ActiveCountry.
Country class has an ActiveCountry reference. And we have to do a join between both ids. Is is possible that Country can have null ActiveCountry. Therefore, we want an inner join - only non null values for active country
#ManyToOne
#JoinColumn(name="id")
ActiveCountry active;
Step 1: Annotate the entity class with #QueryEntity
#Entity
#QueryEntity
public class Country {}
This seems to have been addressed already since the question shows Q classes.
Step 2: Have the repository interface extend QueryDslPredicateExecutor
public interface CountryRepository
extends PagingAndSortingRepository<Country, Long>
, QueryDslPredicateExecutor<Country> {
}
Step 3: Invoke the Page<T> findAll(Predicate query, Pageable page) method provided by QueryDslPredicateExecutor
public Page<Country> getCountries(String country, Optional<String> status, Pageable page) {
QCountry root = QCountry.country;
BooleanExpression query = root.codeLeft.country.equalsIgnoreCase(country);
query = query.and(root.codeRight.country.equalsIgnoreCase(country));
if (status.isPresent()) {
query = query.and(root.active.status.equalsIgnoreCase(status));
}
return countryRepository.findAll(query, page);
}
I am using ElasticsearchRepository and want to query on boolean property.
Sample snippet here:
class TempBean
{
private boolean isActive;
}
interface MyEntityRepository implements CrudRepository<MyEntity, Long>
{
TempBean findByIsActiveTrue();
}
How to query on the active property without passing it as param to the abstract method?
This is possible if I would have JpaRepository as per this answer how-to-query-for-boolean-property-with-spring-crudrepository
It is possible, as can be seen in the docs. Just remove "Is" from your function:
interface MyEntityRepository implements CrudRepository<MyEntity, Long>
{
TempBean findByActiveTrue();
}
As a side note, I don't know about your schema but I would suggest you use Page<TempBean> as your return type, which would require PageRequest as an argument. This is in case more than one TempBean docs have "active":"true" and your function is likely to return more than one records.
I'm trying to get a page of a partial entity (NetworkSimple) using the new feature of spring data, projections
I've checked the documentation and if I request only:
Collection<NetworkSimple> findAllProjectedBy();
It works, but if I'm using pageable:
Page<NetworkSimple> findAllProjectedBy(Pageable pageable);
It throws an error:
org.hibernate.jpa.criteria.expression.function.AggregationFunction$COUNT cannot be cast to org.hibernate.jpa.criteria.expression.CompoundSelectionImpl
Any one has already work with this ?
My NetworkSimple class is the following:
public interface NetworkSimple {
Long getId();
String getNetworkName();
Boolean getIsActive();
}
Note: This feature should work in the way described by the original poster but due to this bug it didn't. The bug has been fixed for the Hopper SR2 release, if you're stuck on an earlier version then the workaround below will work.
It is possible to use Pageable with the new query projection features introduced in Spring Data JPA 1.10 (Hopper). You will need to use the #Query annotation and manually write a query for the fields you require, they must also be aliased using AS to allow Spring Data to figure out how to project the results. There is a good example in spring-boot-samples part of the spring boot repository.
In your example it would be quite simple:
#Query("SELECT n.id AS id, n.name AS networkName, n.active AS isActive FROM Network n")
Page<NetworkSimple> findAllProjectedBy(Pageable pageable);
I have made the assumption that your entity looks something like this:
#Entity
public class Network
{
#Id
#GeneratedValue
private Long id;
#Column
private String name;
#Column
private boolean active;
...
}
Spring Data will derive a count query automatically for the paging information. It is also possible to make use of joins in the query to fetch associations and then summarise them in the projection.
I think you need create findAllProjectedBy() as specification.Then you can use findAll() method like this.
example :findAll(findAllProjectedBy(),pageable)
Following link may be help to find how to create specification in spring.
https://spring.io/blog/2011/04/26/advanced-spring-data-jpa-specifications-and-querydsl/
The issue may come from the method name. The by keyword means that you ae filterig data by a specific property: findByName for example. Its called query creation from method name:
http://docs.spring.io/spring-data/jpa/docs/1.10.1.RELEASE/reference/html/#repositories.query-methods.query-creation
So try with Page<NetworkSimple> findAll(Pageable pageable);
Even with spring-data-jpa 1.11.4, something like
public interface NetworkRepository extends JpaRepository<Network, String> {
Page<NetworkSimple> findAll(Pageable pageable);
}
would not compile; reporting
findAll(org.springframework.data.domain.Pageable) in NetworkRepository clashes with findAll(org.springframework.data.domain.Pageable) in org.springframework.data.repository.PagingAndSortingRepository
return type org.springframework.data.domain.Page<NetworkSimple> is not compatible with org.springframework.data.domain.Page<Network>
The workaround we found was to rename findAll to findAllBy, e.g.
public interface NetworkRepository extends JpaRepository<Network, String> {
Page<NetworkSimple> findAllBy(Pageable pageable);
}
You can use interface projection with Pageable like this :
Page<NetworkSimple> findPagedProjectedBy(Pageable pageable);
with some parameter :
Page<NetworkSimple> findPagedProjectedByName(String name, Pageable pageable);
Implementing interface projection with pagination
1. Our ResourceEntity.java class
#Getter
#Setter
#NoArgsConstructor
#Entity
public class ResourceEntity{
private Long id;
private String name;
}
2. Creating projection Interface name ProjectedResource.java, which maps data collected by the SQL query from repository layer method
public interface ProjectedResource {
Long getId();
String getName();
String getAnotherProperty();
}
3. Creating Repository layer method: getProjectedResources()
We are considering the database table name is resource.
We are only fetching id and name here.
#Query(name="select id, name, anotherProperty from resource", countQuery="select count(*) from resource", nativeQuery=true)
Page<ProjectedResource> getProjectedResources(Pageable page);
Hope the issue will be resolved!
You can use:
#Query("SELECT n FROM Network n")
Page<? extends NetworkSimple> findAllProjectedBy(Pageable pageable);
I need to use two or more conditions on different fields in a Repository that extends PagingAndSortingRepository.
For example:
public interface PersonRepository extends PagingAndSortingRepository<Person,String> {
Page<Person> findByCreatedUser(String createdUserId, Pageable pageable);
}
This method should filter by createdUserId=Person.createdUserId or createdUserId=Person.userId.
How can this be done?
Never mind. I found the answer.
Page findByCreatedUserIdOrUserId(String createdUserId, String userId, Pageable pageable);
Just define a method and add the #Query annotation as outlined in the documentation:
public interface PersonRepository extends PagingAndSortingRepository<Person,String> {
#Query("......")
Page<Person> findByCreatedUser(String createdUserId, String userId, Pageable pageable);
}
http://docs.spring.io/spring-data/jpa/docs/current/reference/html/#jpa.query-methods.at-query