how can we merge two styles blocks of different classes which are having same properties except "Padding" as shown in below code in to one block.
Here i am using SASS(Syntactically Awesome Style Sheets).Any help would be appreciable. Thank you.
.bookstyle {
color: $alt-dark-blue;
padding-left:82.1px;
cursor: pointer;
clear: both;
font-size: 10px;
}
.pagestyle {
color: $alt-dark-blue;
clear : both;
cursor: pointer;
font-size: 10px;
}
One way of doing this is to have one extend the other. Here's an example of it
.bookstyle {
#extend .pagestyle;
padding-left:82.1px;
}
.pagestyle {
color: red;
clear : both;
cursor: pointer;
font-size: 10px;
}
Alternatively you could use mixins to add the required rules.
I'm assuming you're using the SCSS syntax for Sass by the way
You can use #extend rule
%pagestyle {
color: $alt-dark-blue;
clear : both;
cursor: pointer;
font-size: 10px;
}
.bookstyle {
#extend %pagestyle;
padding-left:82.1px;
}
Related
I want to use one CSS style for two classes with mixin, but when I use mixin the final result will be 2 classes with the same CSS.
I have shared my code example below:
#mixin btnhover {
background-color: $bg-cl-blc;
color: $txt-cl-ff;
}
.btn-base {
font-size: 15px;
&:hover {
#include btnhover;
}
}
.btn-otln {
font-size: 15px;
&:hover {
#include btnhover;
}
}
**OUTPUT CSS**
.btn-base:hover {
background-color: #000;
color: #fff;
}
.btn-otln:hover {
background-color: #000;
color: #fff;
}
This is how Sass works - it allows for better organisation of the code, but this code is then compiled, retaining functionality and not caring about other aspects.
If you really care about how the output code is structured, I would suggest to create a separate style for the classes with the hover effect:
#mixin btnhover {
background-color: #000;
color: #fff;
}
.btn-base {
font-size: 15px;
}
.btn-otln {
font-size: 15px;
}
.btn-base:hover,
.btn-otln:hover {
#include btnhover;
}
But in this approach, the use of mixin (and Sass) is questionable (in this exact case).
Generally, when you use Sass (or any other compiled language), you don't really care about the output CSS.
This won't be your answer, but I want to show you another way to make a mixin
#mixin btnhover($back, $color) {
background: $back;
color: $color;
}
When you use it, you can plug in the values
#include mixin btnhover($bg-cl-blc, $txt-cl-ff)
That way you can use the mixin over and over in different places with different values
Just discovered this recently myself, it's a concept called 'placeholders' in SASS syntax (see example below). I've done my best to apply it to your situation below....
Put this in your .scss file:
$bg-cl-blc: #ff211a;
$txt-cl-ff: #fff;
$btn-base-size: 15px;
%btnhover {
background-color: $bg-cl-blc;
color: $txt-cl-ff;
}
%btn-common {
font-size: $btn-base-size;
}
.btn-base {
#extend %btn-common;
&:hover {
#extend %btnhover;
}
}
.btn-otln {
#extend %btn-common;
&:hover {
#extend %btnhover;
}
}
CSS output will look like this
.btn-otln:hover, .btn-base:hover {
background-color: #ff211a;
color: #fff;
}
.btn-otln, .btn-base {
font-size: 15px;
}
Great article written up on this here:
https://dev.to/kemotiadev/are-sass-mixins-really-that-lightweight-and-what-are-placeholders-119i
I have a #mixin for paragraphs that looks like this:
#mixin paragraph {
color: $dark-700;
font-size: 14px;
line-height: 20px;
}
But I was wondering if it's possible to create a $paragraph variable with all those styles in an array or object to call it every time.
I'm not sure I understand your question correctly, but maybe placeholder selectors are what you are looking for:
%paragraph {
color: $dark-700;
font-size: 14px;
line-height: 20px;
}
.section-description {
#extend %paragraph;
}
.banner-text {
#extend %paragraph;
}
More info: https://sass-lang.com/documentation/style-rules/placeholder-selectors
Is it possible in SASS to generate a CSS file, where only selectors with a color property are stored?
e.g.
This SASS file
class-1 {
display: flex;
align-items: center;
padding: 0 1rem 1rem;
color: #000;
}
class-2 {
display: flex;
align-items: center;
padding: 0 1rem 1rem;
}
class-3 {
display: flex;
color: #000;
}
should be outputted as:
class-1 {
color: #000;
}
class-3 {
color: #000;
}
It is not possible with Sass itself, but you can filter out unwanted properties by using PostCSS.
I'm not aware about any plugin that does exactly this, but it should not be hard to write one by yourself. You can refer postcss-select plugin as a starting point for your implementation as it filters out CSS based on selectors.
In SASS's class selecter, I want to select parent's sibling.
.bw-textarea {
height: 150px;
padding: 10px;
overflow-y: auto;
background: white;
text-align: left;
width: 100%;
border: 1px solid #eeeeee;
font-size: 12px !important;
color: #666666;
// textarea:disabled & {
// background: #efefef;
// }
}
Compiled above sass code,
.bw-textarea textarea:disabled {
background: #efefef;
}
But I want to show result like this css code...
How to select like this in sass?
textarea.bw-textarea:disabled {
background: #efefef;
}
You gotta use #root in this case. It's pretty simple
This link will give a clear idea about this selector
.bw-textarea {
#at-root textarea#{&}:disabled{
background: cyan;
}
}
This will compile to
textarea.bw-textarea:disabled {
background: cyan;
}
See this PEN
This is what your looking for:
.bw-textarea {
height: 150px;
padding: 10px;
overflow-y: auto;
background: white;
text-align: left;
width: 100%;
border: 1px solid #eeeeee;
font-size: 12px !important;
color: #666666;
&:disabled {
background: #efefef;
}
}
Check out this SO answer for a lil more idea on the nested pseudo selectors
Sass parent selector and hover?
And of course check the sass docs
https://sass-lang.com/documentation/file.SASS_REFERENCE.html
After converting a lot of redundant crappy css files into scss files, I have a bunch of scss files. I'm pretty sure there is a lot of common css repeated among these files and I would like to extract this code.
As an example, let's say I have this block of scss code (let's call it block A) :
.test {
color: white;
.toto {
background: red;
font-size: 12px;
}
}
And another block (that we'll call block B) :
.test {
color: black;
.toto {
background: blue;
font-size: 12px;
text-align: center;
}
}
I want to be able to extract the following common scss code from block A and B :
.test {
.toto {
font-size: 12px;
}
}
It seems like a simple task to do, but with a large list of long scss files, it's really painful to do it manually. After searching for a while I didn't find any tool for that.
An intermediary solution could be to convert sass code to a multi-dimensionnal associative array and to process arrays to find intersections, but I could not find any simple solution to do that either, so any help would be appreciated.
There are a few approaches but in this instance, I would opt for a variable:
$base-font-size: 12px;
.test {
color: white;
.toto {
background: red;
font-size: $base-font-size;
}
}
.test {
color: black;
.toto {
background: blue;
font-size: $base-font-size;
text-align: center;
}
}
Or you could add a toto mixin with some defaults and use that:
#mixin toto($background: red, $text-align: left, $font-size: 12px) {
.toto {
background: $background;
text-align: $text-align;
font-size: $font-size;
}
}
.test {
color: white;
#include toto();
}
.test {
color: black;
#include toto(blue, center);
}
EDIT: or use extend:
.font-size-12 {
font-size: 12px;
}
.test {
color: white;
.toto {
#extend .font-size-12;
background: red;
}
}
.test {
color: black;
.toto {
#extend .font-size-12;
background: blue;
text-align: center;
}
}