So I'm working on a little web application in which you can manage your database.
Now I can use the following function to retrieve all databases
DB::select('SHOW DATABASES')
But I now want to be able to get the tables for each of those databases and eventually do more with those databases, but I figured if I get this working that wouldn't be a problem.
Normally you'd have the different database in your config, but since I want my application work with "any" database and make sure I don't have to manually add all the databases etc since that's the kind of work I want my web app done for me.
I've tried tricking around it a bit without success for example.
DB:select('USE dbName; SHOW TABLES');
DB::select('SELECT dbName(); SHOW TABLES');
Obviously this didn't work, but is there any "proper" solution to this? I thought editing the .env variable on the fly might've been an option, but I can't seem to find a "legit" way to do that either.
You don't need this.
I thought editing the .env variable on the fly might've been an
option, but I can't seem to find a "legit" way to do that either.
What you need is this
DB::purge('mysql');//IMP
Config::set('database.connections.mysql.host', $host);
Config::set('database.connections.mysql.database', $database);
Config::set('database.connections.mysql.username', $username);
Config::set('database.connections.mysql.password', $password);
You just need to figure out a way to get the values for $host, $database, $username, and $password dynamically.
One way to do that is have a database which stores all these values and point the default database connection (say mysql in config/database.php) to it. Then read values from it on the fly and set the connections accordingly.
Related
Just trying to understand how Capsule works in laravel. Everything works correctly where it is defined, however, as soon as a new page is opened it again take backs the old connection information instead of the new connection which is defined.
I believed setAsGlobal() basically makes it available for that particular session atleast, however, I guess I am conceptually wrong here.
It would be really nice if someone can guide through the right way to make the new database connection available globally VIA CAPSULE, there are various other ways, however this seems more promising.
It would be really nice if someone could explain the following commands in more simpler way (the comments are written as per in the documentation, however, something above that would be really nice):
// Set the event dispatcher used by Eloquent models... (optional)
$capsule->setEventDispatcher(new Dispatcher(new Container));
// Set the cache manager instance used by connections... (optional)
$capsule->setCacheManager(...);
// Make this Capsule instance available globally via static methods... (optional)
$capsule->setAsGlobal();
// Setup the Eloquent ORM... (optional; unless you've used setEventDispatcher())
$capsule->bootEloquent();
Any help would really be appreciated. Thank you.
Check my answer at https://stackoverflow.com/a/34837068/1216285 to use Capsule out of Laravel scope in your app. Since all the laravel components are decoupled and served as independent components in laravel project, you can use them in your app easily.
I am not a superb developer, so I guess the problem I did run into is just to big for me.
I have a project where I have different subdomains for the current language. When I login a user it is logged only for the current subdomain. So when I login at "en.Aproject.com", and then go to "de.Aproject.com", the user will not be logged in. They don't share the session. I already tried to modify the 'domain' => null, in app/sessions.php. But when I change the value here the Login doesn't work at all. Then everytime a new Session-row is created in the DB and Laravel seems not to recognize them.
Is the current domain saved somehow in the session identifier? Is it possible to use one session for different domains? I found some stuff about OAuth and Single sign-on but I can not handle it by myself.
I was thinking about (when logging in and the credentials are correct) calling a script via Ajax, which should log in the user for all needed domains. But I would have to do the same for logging out.. And I will probably have a lot of domains. The project will have one base page and several subprojects (all with the different languages). Like this
mainproject.com
en.mainproject.com
de.mainproject.com
...
Aproject.com
en.Aproject.com
de.Aproject.com
...
Bproject.com
en.Bproject.com
de.Bproject.com
...
So it would just feel wrong to log in the user to like 20 different pages and create 20 sessions... It would feel better to just use one session for all of them.
Okay, I hope you understand the problem and someone already had the same problem and found a solution. Thanks!!!!!!!! greets. gerti
Background info.. I am using Laravel 4.2
Now I just tried something, maybe it helps someone. Actually point 2 is weird to me (see below)
I display these 3 things:
Session::getId()
Auth::getName()
var_dump(Session::all())
I display them on "de.Aproject.com". Here I am logged in.
And i display them on "en.Aproject.com"... Where I am still logged out (which I want to fix :D )
The value of Session::getId() is different on both sides. Thats the problem I guess, they should share the same.
The value of Auth::getName() is the same on both sides (login_82e5d2c56bdd0811318f0cf078b78bfc). Which I don't understand. Why does the second page have this value when i am not logged in?
The value of Session::all() is ["login_82e5d2c56bdd0811318f0cf078b78bfc"] => string(17) "test#test.de" on the first site, on the second its empty. Thats correct.
Since the default Laravel authentication system uses cookies to manage the session, you actually need to login the user on each subdomain you're going to use. To avoid that, you can use another session driver like database.
I'm a bit lost how I should get the entity framework to work with automatic migration. I want:
The database to be created automatically when it doesnt exist
The database to be updated automatically when the model changed
For the latter I'm using DbMigrator. It is rather slow so I don't want to run it every request, and also I have multiple databases in the same application so it cant go in Application_Start which is why I put it in Session_Start like this:
if (Session["started"] == null)
{
// this takes care of any database updates that might be necessary.
MigrationConfiguration configuration = new MigrationConfiguration();
DbMigrator migrator = new DbMigrator(configuration);
List<string> pm = migrator.GetPendingMigrations().ToList();
if (pm.Count > 0)
{
migrator.Update();
}
}
else
{
Session["started"] = "started";
}
Not sure if this is the right way to do it but it seems to work, however it doesnt actually generate the database when it doesnt exist. It gives me a "Cannot open database "db" requested by the login"
I had this working before with the following:
Database.SetInitializer<DbContext>(new InitializerIfModelChange());
This drops the database and generates seed data which is fine for when the database doesnt exist but it also is triggers when the database is changed (in which case I would like DbMigrator to handle it) This was in Application_Start before but I'm not sure what to do with it. I'm afraid that it will conflict with the DbMigrator. How would I set this all up in order to achieve the two things described earlier?
I manually run the Update-Database in the package manager whenever the database needs to be changed. Initially I used the Database.SetInitializer like you did to create the database but have it commented out now.
Checkout Entity Framework 4.3 Automatic Migrations Walkthrough for more advanced help.
This should work for what you want, then if you need to create a new database just add Database.SetInitializer<NewDBContext>(new NewDBInitializer()); like you had, build and run. Then comment it out so it doesn't run in the future on a model change and instead use the Update-Database command in the package manager.
I thought this would be simple but I guess there's a catch somewhere...
I'm developing a custom part of code for a Joomla installation and I need to unset some session variables before executing my code. So, naturally, I have
$session->clear('var1');
$session->clear('var2');
$session->clear('var3');
$session->clear('var4');
but the page appears totally blank and nothing happens. Any suggestions?
Assuming that you got the $session variable like this:
$session = JFactory::getSession();
If you are getting a blank page, you probably some error in your code. Do you have access to some kind of error log? If not, you can try to force displaying errors from your code if it's not a production environment (although it's not the best way to do it) or enable debug mode from the joomla administrator.
You can also try to run the php file in your browser, and if everything is ok and there are no parse errors in the file, you should see a message like 'Restricted access' or similar.
Besides, if the script is not crashing, you can check what value is returning each call to $session->clear( 'xxx' ) (It should return the value you just cleared.
The last thing that comes to my mind is that the vars you have stored in session are in a different "context". When you get/set data to session, you can pass a "namespace" as an additional parameter, so these vars are stored in that "namespace" (in fact, it's stored inside another index inside the session. So if possible, you should check if these variables are stored in session using a different "namespace":
$session->set( 'var1', $value, 'another_namespace' );
If so, you should clear it like this:
$session->clear( 'var1', 'another_namespace' );
P.S.: I said "namespace" because it's the parameter name that Joomla uses in these session methods, but don't get confused with PHP namespaces.
I hope it helped!
How can you edit Joomla's articles in terminal?
Problem: to know the location where Joomla stores its articles
I tried to find articles unsuccessfully by
locate Masi | xargs -0 grep great
The articles are stored in the database in a table called jos_content. If you wanted to do a find and replace across them all, open a connection to the database (or use something like phpMyAdmin) and run something like this:
UPDATE `jos_content`
SET `introtext` = REPLACE(`introtext`, 'great', 'awesome'),
`fulltext` = REPLACE(`fulltext`, 'great', 'awesome')
Edit to help you debug the problem:
You won't be able to find "jos_content" in your codebase, because of a feature of Joomla which allows you to specify different table prefixes: "jos" is the default prefix. In the code, it's always written like this: #__content, and the DBO object converts that to "jos_content" behind the scenes.
However, you don't need to be looking in your code at all, just the database. You should be able to connect to the database - all the details you need will be in your configuration.php file.
If you're using Joomla 1.5, the variables you need are called $host, $user, $password and $db.
In Joomla 1.0, the variables are named $mosConfig_host, $mosConfig_user, $mosConfig_password and $mosConfig_db
There are a number of ways that you can connect to the database (check with your hosting company if you have phpMyAdmin available: it's quite easy to use), but to do it from the terminal (substitute in your own variables from above):
$ mysql -h $host -u $user -p$password -D $db
note that there's no space between the -p and the password. From there you should be able to run your own SQL, but I would highly recommend making a backup before you do any manual changes.
Joomla stores articles in a MySQL database. If you want to read/modify/delete articles you'll have to use SQL queries.
If you're determined to do this from a terminal, you could always start the mysql client from the command line and execute your queries from there.