get the script path with whitespaces in Bash - bash

Question

I'm running it under MacOS El Capitan 10.10.6
among all commands to get my current dir (path I'm running my script from) only this works for me:
FILES="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
But it's not going to work if the folder has whitespace in it's name (aka: "folder name")
How to fix this?
Thank you! )
Update: added a script:
#!/bin/bash
function check ()
{
oldsize=`wc -c <"$1"`
sleep 1
newsize=`wc -c <"$1"`
while [ "$oldsize" -lt "$newsize" ]
do
echo "Not yet..."
oldsize=`wc -c <"$1"`
sleep 1
newsize=`wc -c <"$1"`
done
if [ "$oldsize" -eq "$newsize" ]
then
echo "The file has been copied completely."
fi
}
FILES="$(dirname "${BASH_SOURCE[0]}")/*"
function main
{
for f in $FILES
do
if [[ "$f" =~ \.mkv$ ]];
then
#/////////////////////////////////////////////////////////////////////
check "$f"
(( count = count + 1 ))
g="${f/mkv/avi}"
#LOG_FILE="${g/avi/log}"
#exec > >(tee -a "${LOG_FILE}" )
#exec 2> >(tee -a "${LOG_FILE}" >&2)
now="$(date)"
printf "Current date and time %s\n" "$now"
echo "Processing $f file..."
#avconv -i "${f}" -map 0:0 -map 0:1 -codec copy -sn "${g}"
avconv -i "$f" -map 0 -codec copy "$g"
if [ $? -eq 0 ]; then
echo OK
rm "$f"
else
echo FAIL
rm "$g"
#rm "$LOG_FILE"
return
fi
fi
#/////////////////////////////////////////////////////////////////////
done
}
############
count=0
############
main
if (($count > 0)); then
open "$(dirname "${BASH_SOURCE[0]}")"
fi
exit

Answer 1

I am using Mac OS X 10.11.6, and I have a directory $HOME/tmp. From there, I executed:
$ cd $HOME/tmp
$ pwd
/Users/jleffler/tmp
$ mkdir -p "Spaced Out Directory "/bin
$ export PATH="$PATH:$PWD/$_"
$ cat <<'EOF' > Spaced\ Out\ \ Directory\ \ \ /bin/gorblinsky.sh
> #!/bin/bash
>
> echo "PWD=$PWD"
> DIR="$(dirname "${BASH_SOURCE[0]}")"
> echo "DIR=$DIR"
> cd "$DIR"
> pwd
> echo "PWD=$PWD"
> EOF
$ chmod +x Spaced\ Out\ \ Directory\ \ \ /bin/gorblinsky.sh
$ gorblinsky.sh
PWD=/Users/jleffler/tmp
DIR=/Users/jleffler/tmp/Spaced Out Directory /bin
/Users/jleffler/tmp/Spaced Out Directory /bin
PWD=/Users/jleffler/tmp/Spaced Out Directory /bin
$
This shows that the command $(dirname "${BASH_SOURCE[0]}") can determine the name of the directory where the source for the command is stored.
If the script was going to use the variable $DIR to specify file names, you'd need to be careful (very careful) to ensure it is always properly quoted.
For example:
cp "$DIR/gorblinksky.h" "$HOME/tmp/cobbled together name"
Modern style is to always (double) quote all variable references, even when there's nothing in them that needs protecting (see shellcheck.net for example — and Google Shell Style Guide). I'm old-school enough not to put quotes around names that can't contain spaces or metacharacters, but I guess that is just old-fashioned. For example, I shell-checked a script for playing with RCS version numbers, and it doesn't quote variables containing dotted strings of digits (9.19.2.24 — could be an IBM IPv4 address too) and I was told off for not quoting them, though the file names were already protected with quotes.