What is the best way to do this listing?
I would not want to do it that way "ugly".
/**
* Get user indicateds
* #return array|null
*/
static public function indicateds()
{
$users = ModelUser::all();
foreach( $users as $user ) {
if( $user->financial->status_payment ) {
$newArray[] = $user;
}
}
return (isset($newArray) ? $newArray : null);
}
Thanks
You can use the collection's filter method:
return ModelUser::with('financial')
->get()
->filter(function($user) {
return $user->financial->status_payment;
});
I'm supposing you have defined the financial relation and you should eager load it as I did to improve the performance.
One of the benefits to relationships is that you can use them to modify your queries, as well. So, instead of getting all users into a Collection, and then filtering that Collection, you can use the relationship to modify the query so that you only get the desired records in the first place. This will reduce the number of records returned from the database, as well as the number of model instances that get created. This will save you time and memory.
$users = ModelUser::with('financial')
->whereHas('financial', function($q) {
// $q is the query for the financial relationship;
return $q->where('status_payment', true);
}
->get();
The with() is not required, but if you'll be accessing the financial relationship on the returned users, it is a good idea to eager load it.
The whereHas() is where the magic happens. It modifies the query so that it will only return users that have a related financial record that matches the conditions added by the closure used in the second parameter.
You can read more about it in the documentation here.
Related
I'm new to Laravel. I am developing a project. and in this project I have 4 tables related to each other
-Users
-Orders
-OrderParcels
-Situations
When listing the parcels of an order, I want to get the information of that order only once, the user information of that order once again, and list the parcels as a table under it. so far everything ok. but I also want to display the status of the parcels listed in the table as names. I couldn't add the 4th table to the query. do you have a suggestion? I'm putting pictures that explain the structure below.
My current working code is
$orderParcels = Orders::whereId($id)
->with('parcels')
->with('users:id,name')
->first();
and my 'orders' model has method
public function parcels(){
return $this->hasMany(OrderParcels::class);
}
public function users(){
return $this->hasOne(User::class,'id','affixer_id');
}
Note[edit]: I already know how to connect like this
$orderParcels = DB::table('order_parcels as op')
->leftjoin('orders as o','op.orders_id','o.id')
->leftjoin('users as u','o.affixer_id','u.id')
->leftjoin('situations as s','op.status','s.id')
->select('op.*','o.*','u.name','s.situations_name')
->where('op.orders_id',$id)->get();
but this is not working for me, for each parcels record it returns me orders and user info. I want once orders info and once user info.
Laravel provides an elegant way to manage relations between models. In your situation, the first step is to create all relations described in your schema :
1. Model Order
class User extends Model {
public function parcels()
{
return $this->hasMany(OrderParcels::class);
}
public function users()
{
return $this->hasOne(User::class,'id','affixer_id');
}
}
2. Model Parcel
class Parcel extends Model {
public function situations()
{
return $this->hasOne(Situation::class, ...);
}
}
Then, you can retrieve all desired informations simply like this :
// Retrieve all users of an order
$users = $order->users; // You get a Collection of User instances
// Retrieve all parcels of an order
$parcels = $order->parcels; // You get a Collection of User instances
// Retrieve the situation for a parcel
$situations = $parcel->situations // You get Situation instance
How it works ?
When you add a relation on your model, you can retrieve the result of this relation by using the property with the same name of the method. Laravel will automatically provide you those properties ! (e.g: parcels() method in your Order Model will generate $order->parcels property.
To finish, in this situation where you have nested relations (as describe in your schema), you should use with() method of your model to eager load all the nested relation of order model like this :
$orders = Orders::with(['users', 'parcels', 'parcels.situations'])->find($id)
I encourage you to read those stubs of Laravel documentation :
Define model relations
Eager loading
Laravel Collection
Good luck !
Use join to make a perfect relations between tables.
$output = Orders::join('users', 'users.id', '=', 'orders.user_id')
->join('order_parcels', 'order_parcels.id', '=', 'orders.parcel_id')
->join('situations', 'situation.id', '=', 'order_parcels.situation_id')
->select([
'orders.id AS order_id',
'users.id AS user_id',
'order.parcels.id AS parcel_id',
'and so on'
])
->where('some row', '=', 'some row or variable')->get();
I have an issue where a profile can have many campaigns and also many locations.
The campaigns are linked via a pivot table but my goal is just to return all of the location ids.
Profile:
public function campaigns() {
return $this->hasMany('App\Models\Campaign', 'profile_id', 'id');
}
Campaign:
public function locations() {
return $this->belongsToMany('App\Models\Location')->withPivot('campaign_id', 'location_id');
}
Currently I am solving this by doing
$campaigns = $profile->campaigns;
[Doing a nested foreach loop and placing each ID into the array]
How would I get this via a query?
I've tried
$campaigns = $profile->campaigns()
->with('locations')
->get()
->pluck('location.id');
Well, your goal is to get information from the location, so I'd start your query with that. You can condition your query based on the relationships using the whereHas() method.
This assumes your Location has the campaigns relationship defined, and your Campaign has the profile relationship defined.
$ids = Location::whereHas('campaigns.profile', function ($query) use ($profile) {
return $query->where('id', $profile->id);
})->pluck('id');
You can read more about querying by relationships in the documentation here.
I've been searching for a while and couldn't find an answer, here's what I have:
1- ShowCategory (id & title)
class ShowCategory extends Model
{
public function shows()
{
return $this->belongsToMany(Show::class, 'category_show');
}
}
2- Show (id, title & active)
class Show extends Model
{
public function categories()
{
return $this->belongsToMany(ShowCategory::class, 'category_show');
}
}
So there's a many to many relationship, what I need is retrieving all ShowCategory elements that has at least one Show related to it, and to filter each ShowCategory->shows by show.active, only return shows that are active
Here's what I'm trying to do:
$categories = ShowCategory::whereHas('shows', function($query) {
$query->where('shows.active', '=', true);
})->get();
It only filters ShowCategory that includes shows and if only one of those shows are active, it returns the category with all shows inside, even if others are not active, I need to filter those who are not active.
What should I do? Thanks in advance
This requires a combination of whereHas() and with(). First, whereHas() will filter the ShowCategory model to those that have an active Show, while the with() clause will limit the results of the relationship to only return active ones:
$categories = ShowCategory::whereHas("shows", function($subQuery) {
$subQuery->where("shows.active", "=", true); // See note
})->with(["shows" => function($subQuery){
$subQuery->where("shows.active", "=", true);
}])->get();'
Note: You should be able to use active instead of shows.active, but depends on if that column is on multiple tables.
Using this query, you will get a Collection of ShowCategory models, each with their active Show models already loaded and available via ->shows:
foreach($categories AS $category){
dd($category->shows); // List of `active` Shows
}
This is what you need.
$categories = ShowCategory::whereHas('shows', function($query) {
$query->whereActive(true);
})->get();
Try, this can be a possible way to retreive related results.
// This will only return ShowCategory which will have active shows.
/* 1: */ \ShowCategory::has('shows.active')->get();
// So, logically this will only have active shows -__-
$showCategory->shows
Laravel allows to extends foreign relation by using this . notation as a condition for retreival.
Update
You should update the \ShowCategory model as
public function shows(){
return $this->belongsToMany(Show::class, 'category_show')->where('active', true);
}
I am using laravel eloquent. I have fetched data from two table using eloquent.
I have post table and chat table. For post table I have model Post.php and for chat table I have model Chat.php. Here is the the eloquent relation I have created to fetch chat for individual post for a user.
in Post.php
public function TeamMessage()
{
return $this->hasMany('App\Chat','post_id');
}
And in Chat.php
public function ChatRelation()
{
return $this->belongsTo('App\Post');
}
it is working perfect. But this relation fetch all messages for a specific post. I want to fetch all unread message from chat table. I have a column named unread in chat table.
Now my question is how I can fetch only unread message for a specific post.
While the other answers all work, they either depend on scopes (which are very useful in many circumstances) or on you having already instantiated an instance of $post, which doesn't let you eager load multiple posts with their messages.
The dynamic solution is this, which will let you fetch either 1 or more posts and eager load their messages with subquery:
$posts = Post::with(['TeamMessage' => function ($query) {
$query->where('unread', true); // This part applies to the TeamMessage query
}])->get();
See in documentation
Edit:
If you, however, want to filter the posts, to only show those that have unread messages, you need to use whereHas instead of with:
$posts = Post::whereHas(['TeamMessage' => function ($query) {
$query->where('unread', true); // This part applies to the TeamMessage query
}])->get();
More in the documentation.
You can also chain whereHas(...) with with(...).
For querying relationships, you have to call them as functions instead of properties, like this:
$unreadPosts = $post->TeamMessage()->where('unread', true)->get();
For more information on this you can take a look at the docs.
You need to create a local scope on your model, information on local scopes can be found here: https://laravel.com/docs/5.6/eloquent#local-scopes
public function scopeUnread($query)
{
return $query->where('unread', 1);
}
Then in your controller/view
$unread = $yourmodel->unread()
First I would change your relation names to the name of the entity in lower case:
in Post.php
public function chats()
{
return $this->hasMany('App\Chat','post_id');
}
And in Chat.php
public function post()
{
return $this->belongsTo('App\Post');
}
public function scopeUnread($query)
{
return $query->where('unread', 1);
}
Then you can use
$post->chats()->unread()->get();
I have table with many to many relationship.
User many to many Permission
I already define many to many relationship on both model, and create the pivot table also.
What I want is get all user which contain permission name
What I have done so far is
User::all()->permissions->contains('name', 'access.backend.admin')->get();
But it give me
Undefined property: Illuminate\Database\Eloquent\Collection::$permissions on line 1
What wrong with my code?
User::All() returns a collection not model object. You have iterate over the collection to get the model object and use ->permissions().
For exapmle:
$users = User::all();
foreach ($users as $user) {
$user->permissions->contains('name', 'access.backend.admin'); // returns boolean
}
Or you can get a single model from DB as:
$user = User::first();
$user->permissions->contains('name', 'access.backend.admin'); // returns boolean
Update 1
To get users which contain desired permission use filter() method as:
$filtered_users = $users->filter(function ($user) {
if ($user->permissions->contains('name', 'access.backend.admin')) {
return $user;
}
});
Update 2
You can also write a query which returns the desired result as:
$filtered_users = User::whereHas('permissions', function($q) {
$q->where('name', 'access.backend.admin');
})->get()
I have a similar case of questions and tags, they have many to many relationship.
So when i have to fetch all question with a particular tag then i do this
$tag = Tag::where('name','laravel')->get()->first();
I first retrieved the Tag model with name laravel.
and then retrieved all questions having tag laravel.
$questions = $tag->questions;
Similarly you can do this
$permission = Permission::where('name','access.backend.admin')->get()->first();
$users = $permission->users;