Hello im developing an app for a gym and in the stats section i got stucked in this query. I need to select all the lessons that starts between the start of the day and 13:00 from the database and then count them but i havent figure out how to make the sentence. the closest i did was this, How can i select all the lessons that starts before 13:00 of all month togheter? thanks
#lessons_morning = Lesson.where(start_date: (beginning_of_day)..Time.beginning_of_day + 13.hours,updated_at: (Time.now.beginning_of_month)..Time.now.end_of_day)
Since you are storing both date and time in the same column, I would do it like this:
First, let's query for all lessons in the current month:
# use Time.zone.now instead of Time.now to use the timezone specified in your application config
#lessons = Lesson.where(
start_date: Time.zone.now.beginning_of_month..Time.zone.now.end_of_month
)
Then, let's only find lessons which start between 0:00 and 13:00:
#lessons.select do |lesson|
start_hour = lesson.start_date.strftime('%H%M').to_i
start_hour <= 1300
}
Related
The current function in use in the JMeter script is
${__timeShift(dd/MM/yyyy,${__time(dd/MM/yyyy)},-P31D,,)}
to specify a review date 31 days ago.
I now learn that the project requires the review date to always fall on a Monday. Is there any way to make sure that performing a timeShift only selects a Monday?
I'm afraid __timeShift() function is not flexible enough, you can consider using __groovy() function instead and implement the following algorithm:
Get current date
Subtract 31 day
If current day of week is Monday - return the date in the past
Otherwise add 1 day until the date in the past becomes Monday
Example function code:
${__groovy(def now = new Date(); def monthAgo = now.minus(31); while (monthAgo[Calendar.DAY_OF_WEEK] != Calendar.MONDAY) { monthAgo = monthAgo.plus(1)}; return monthAgo.format('dd/MM/yyyy'),)}
Demo:
More information: Apache Groovy - Why and How You Should Use It
In the project I'm working on I have a daily command that basically checks the date of the last record in the database and tries to fetch data from an API from the day after and then each month after that (the data is published monthly).
Basically, the last record's date is 2019-08-30. I'm mocking as if I were running the task on 2019-09-01 with
$test = Carbon::create(2019,9,1,4);
Carbon::setTestNow($test);
I then create a monthly period between the next day of the last record's date and the last day of the current month like so:
$period = CarbonPeriod::create($last_record_date->addDay(), '1 month', $last_day_of_current_month);
Successfully generating a period with start_date = 2019-08-31 and end_date = 2019-09-30. Which I use in a simple foreach.
What I expected to happen is that it runs twice, once for August and once for September, but it's running only once for the start date. It's probably adding a month and going past the end date, but I don't know how to force the behaviour I'm looking for.
TL;DR:
$period = CarbonPeriod::create('2019-08-31', '1 month', '2019-09-30');
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
This will print just 2019-08, while I expect 2019-08 and 2019-09. What's the best way to achieve that?
Solution :-
You can store actual date in $actual_day and current date for occurring monthly in $current_day. Put a check on comparing both dates, if not matched then make it on the same day it will skip 30,31 case in case of February month.
$current_date = $current_date->addMonths(1);
if($current_date->day != $actual_day){
$date = Carbon::parse($date->year."-".$date->month."-".$actual_day);
}
Your start date is 2019-08-31. Adding a month takes you to 2019-09-31. 2019-09-31 doesn't exist so instead you get 2019-10-01, which is after your end date. To avoid this I'd suggest you use a more regular interval such as 30 days.
Otherwise you're going to have to rigorously define what you mean by "a month later". If the start date is 31st Jan is the next date 28th February? Is the month after 28th or 31st March? How do leap years affect things?
I am trying to implement a delivery process that occurs at specific days of week for each region. So, in a Region that delivers on Tuesdays and Thursdays I need to be able to get next eligible date based on the date the product will be available. So, if I will have it read on the 5th, O need to get the date for the next Tuesday or Thursday.
I started implementing it on Carbon, but I and creating a lot of loops through dates, testing dates and checking if its valid. something of getting product availability date and checking each day after it if its a monday Tuesday or Thursday ... etc ///I am sure, using Carbon, will have a better way to do it.
Any hint on how to do that ?
Thanks for any help!
Define a date:
$date = Carbon::now();
Now you have to get the day:
$day = $date->dayOfWeekIso
If $date is monday, then you will get a integer and that would be 1. That is because: 1 (monday), 2 (Tuesday), ..., 7 (sunday).
Now that you have this number you just need to apply some simple logic.
If the number you get is a 2 (Tuesday) then you will need to add two days to your $date in order to get the delivery date:
$delivery_date = $date->addDays(2);
If your day is equal 4 (Thursday), then you need to add 6 days to your $date so that would give you the next Tuesday:
$delivery_date = $date->addDays(6);
I think that's what you want! I hope it helps!
I have a jquery calendar for the start date of a project.
Using Watir (automated browser driver, a gem for ruby), I have a set date that I would like to enter in.
The calendar start date is always today's date, whatever that may be for the day it is used. I was wondering if there was a way that ruby can process what today's date is, and use the specified date provided by the user, to calculate the difference of months between them.
Here is an example of the Calendar plugin: http://jqueryui.com/datepicker/
example:
today's date is 30/10/2012, if there was a project that were to start on the 20/12/2012, that would be 2 months from now, so 2 clicks on the next month button.
Is there a way I could do this?
Here is how I approached a similar situation with JSdatepicker:
$today = Time.now.strftime("%e").gsub(" ", "") #one digit day of month without leading space
#browser.text_field(:id => /dateAvailable/).click
Watir::Wait.until(60) {#browser.div(:id => /dateAvailable_popup_cal/).td(:text => $today).exists?}
#browser.div(:id => /dateAvailable_popup_cal/).td(:text => $today).click
Set or grab the date.
Click the text_field that fires the JSDatePicker object
Wait until the calendar actually pops up
The current month is shown, so choose today's date number.
In your case, you also need to set the month. Whether prompting the user for this, or choosing "today", the theory is the same:
$month = Date::MONTHNAMES[Date.today.month] #etc
Pseudo-code making lots of assumptions (only future dates, month name shown on calendar as text, etc):
while !#jquerytablewindow.text.include?($month)
next_month_button.click
end
I don't see a specific advantage to my method versus counting each month, unless of course we add a month to the calendar one day and you still want your code to work!
You could do:
#End date converted to date object
specified_date = '20/12/2012'
end_date = Date.parse(specified_date)
#Start date (today - 30/10/2012)
today = Date.today
#Determine difference in months
number_of_months_up_to_today = (today.month + today.year * 12)
number_of_months_up_to_end = (end_date.month + end_date.year * 12)
clicks_required = number_of_months_up_to_end - number_of_months_up_to_today
#=> 2
Basically it is counting the number of months since the year 0 and then finding the difference.
I want to create an Datetime object based on the number of day in the year.
This number is from the 365 days of the year (for example it can be: 123 or 23 or 344...)
How can I do that?
Thanks
Use the DateTime.ordinal method. Here's an example to get the 100th day of year 2011.
require 'date'
year, day = 2011, 100
DateTime.ordinal(year, day)
# #<DateTime: 2011-04-10T00:00:00+00:00 (4911323/2,0,2299161)>
If you want it as the number of days from now you should do the following:
time = Time.new + (60*60*24)*(numberOfDaysFromNow)
If you want it as the number of days from the start of the year you should do the following
time = Time.new(Time.now.year) + (60*60*24)*(dayOfTheYear-1)