i may recieve these two strings:
base = Base64.encode64(File.open("/home/usr/Desktop/test", "rb").read)
=> "YQo=\n"
string = File.open("/home/usr/Desktop/test", "rb").read
=> "a\n"
what i have tried so far is to check string with regular expression i-e. /([A-Za-z0-9+\/]{4})*([A-Za-z0-9+\/]{4}|[A-Za-z0-9+\/]{3}=|[A-Za-z0-9+\/]{2}==$)/ but this would be very heavy if the file is big.
I also have tried base.encoding.name and string.encoding.name but both returns the same.
I have also seen this post and got regular expression solution but any other solution ?
Any idea ? I just want to get is the string is actually text or base64 encoded text....
You can use something like this, not very performant but you are guaranteed not to get false positives:
require 'base64'
def base64?(value)
value.is_a?(String) && Base64.strict_encode64(Base64.decode64(value)) == value
end
The use of strict_encode64 versus encode64 prevents Ruby from inadvertently inserting newlines if you have a long string. See this post for details.
Is there any way to decode the below string,
"location.replace(i+\"&utm_content=\"+s)}(document,window,navigator,screen,\"\\x68\\x74\\x74\\x70\\x3a\\x2f\\x2f\\x6d\\x6f\\x62\\x76\\x69\\x64\\x69\\x2e\\x6d\\x6f\\x62\\x73\\x74\\x61\\x72\\x72\\x2e\\x63\\x6f\\x6d\\x2f\\x3f\\x75\\x74\\x6d\\x5f\\x74\\x65\\x72\\x6d\\x3d\\x36\\x35\\x34\\x33\\x34\\x39\\x39\\x37\\x36\\x39\\x31\\x38\\x32\\x39\\x34\\x36\\x33\\x30\\x32\\x26\\x63\\x6c\\x69\\x63\\x6b\\x76\\x65\\x72\\x69\\x66\\x79\\x3d\\x31\",fi
I have tried as,
URI.unescape string
But its not working
There may be another way to do this, but here's one way:
>> hex = "\\x68\\x74\\x74\\x70\\x3a\\x2f\\x2f\\x6d\\x6f\\x62\\x76\\x69\\x64\\x69\\x2e\\x6d\\x6f\\x62\\x73\\x74\\x61\\x72\\x72\\x2e\\x63\\x6f\\x6d\\x2f\\x3f\\x75\\x74\\x6d\\x5f\\x74\\x65\\x72\\x6d\\x3d\\x36\\x35\\x34\\x33\\x34\\x39\\x39\\x37\\x36\\x39\\x31\\x38\\x32\\x39\\x34\\x36\\x33\\x30\\x32\\x26\\x63\\x6c\\x69\\x63\\x6b\\x76\\x65\\x72\\x69\\x66\\x79\\x3d\\x31"
=> "\\x68\\x74\\x74\\x70\\x3a\\x2f\\x2f\\x6d\\x6f\\x62\\x76\\x69\\x64\\x69\\x2e\\x6d\\x6f\\x62\\x73\\x74\\x61\\x72\\x72\\x2e\\x63\\x6f\\x6d\\x2f\\x3f\\x75\\x74\\x6d\\x5f\\x74\\x65\\x72\\x6d\\x3d\\x36\\x35\\x34\\x33\\x34\\x39\\x39\\x37\\x36\\x39\\x31\\x38\\x32\\x39\\x34\\x36\\x33\\x30\\x32\\x26\\x63\\x6c\\x69\\x63\\x6b\\x76\\x65\\x72\\x69\\x66\\x79\\x3d\\x31"
>> Array(hex.gsub("\\x","")).pack('H*')
=> "http://mobvidi.mobstarr.com/?utm_term=6543499769182946302&clickverify=1"
I created a string variable for the hex string and then stripped out the backslashes and 'x' characters. Then, this is converted into an array so we can call the pack method (specifying the capital H string directive for a high nibble first hex string) which you can read about here.
How can I convert a Base64 encoded string to a hex encoded string with dashes(basically to uuid format)?
For example if I have
'FWLalpF2T5mmyxS03Q+hNQ0K'
then how can I convert it to:
1562da96-9176-4f99-a6cb-14b4dd0fa135
I was familiar with unpack but this prompted me to learn the directive as pointed out by cremno.
simplest form:
b64 = 'FWLalpF2T5mmyxS03Q+hNQ0K'
b64.unpack("m0").first.unpack("H8H4H4H4H12").join('-')
#=> "1562da96-9176-4f99-a6cb-14b4dd0fa135"
b64.unpack("m0")
give us:
#=> ["\x15b\xDA\x96\x91vO\x99\xA6\xCB\x14\xB4\xDD\x0F\xA15\r\n"]
which is an array so we use .first to grab the string and unpack again using the directive to format it in the 8-4-4-4-12 format:
b64.unpack("m0").first.unpack("H8H4H4H4H12")
gives us:
#=> ["1562da96", "9176", "4f99", "a6cb", "14b4dd0fa135"]
an array of strings, so now we just join it with the -:
b64.unpack("m0").first.unpack("H8H4H4H4H12").join('-')
#=> "1562da96-9176-4f99-a6cb-14b4dd0fa135"
OOPS
The accepted answer has a flaw:
b64 = 'FWLalpF2T5mmyxS03Q+hNQ0K'
b64.unpack("m0").first.unpack("H8H4H4H4H12").join('-')
# => "1562da96-9176-4f99-a6cb-14b4dd0fa135"
Changing the last char in the b64 string results in the same UUID:
b64 = 'FWLalpF2T5mmyxS03Q+hNQ0L'
b64.unpack("m0").first.unpack("H8H4H4H4H12").join('-')
# => "1562da96-9176-4f99-a6cb-14b4dd0fa135"
To prevent this, you might want to hash your input (base64 or anything else) to the correct length e.g. with MD5:
require "digest"
b64 = 'FWLalpF2T5mmyxS03Q+hNQ0K'
Digest::MD5.hexdigest(b64).unpack("a8a4a4a4a12").join('-')
# => "df71c785-6552-a977-e0ac-8edb8fd63f6f"
Now the full input is relevant, altering the last char results in a different UUID:
require "digest"
b64 = 'FWLalpF2T5mmyxS03Q+hNQ0L'
Digest::MD5.hexdigest(s).unpack("a8a4a4a4a12").join('-')
# => "2625f170-d05a-f65d-38ff-5d9a7a972382"
Is it possible to recognize if a string is formatted as a BSON ObjectID?
For strings we could do:
"hello".is_a?(String) # => true
That would not work since the ObjectID is a String anyway. But is it possible to analyze the string to determine if it's formatted as a BSON ObjectID?
Usually, ObjectIDs have this format.
52f4e2274d6f6865080c0000
The formatting criteria is stated in the docs:
ObjectId is a 12-byte BSON type, constructed using:
a 4-byte value representing the seconds since the Unix epoch,
a 3-byte machine identifier,
a 2-byte process id, and
a 3-byte counter, starting with a random value.
Any 24 chararcters long hexadecimal string is a valid BSON object id, so you can check it using this regular expression:
'52f4e2274d6f6865080c0000' =~ /\A\h{24}\z/
# => 0
Both the moped (used by mongoid) and the bson (used by mongo_mapper) gems encapsulates this check in a legal? method:
require 'moped'
Moped::BSON::ObjectId.legal?('00' * 12)
# => true
require 'bson'
BSON::ObjectId.legal?('00' * 12)
# => true
In Mongoid use: .is_a?(Moped::BSON::ObjectId) sytanx.
Example:
some_id = YourModel.first.id
some_id.is_a?(Moped::BSON::ObjectId)
Note:
"52d7874679478f45e8000001".is_a?(String) # Prints true
we allow users to import data via csv (using ruby 1.9.2, hence it's fastercsv).
being user data, of course, it might not be properly sanitized.
When we try to display the data in an /index method we sometimes get the error "invalid byte sequence in UTF-8" pointing to our erb where we display one of the fields widget.name
When we do the import we'd like to FORCE the incoming data to be valid... is there a ruby operator that will map a string to a valid utf8 string, eg, something like
goodstring = badstring.no_more_invalid_bytes
One example of 'bad' data is char that looks like a hyphen but is not a regular ascii hyphen. We'd prefer to map the non-utf-8 chars to a reasonable ascii equivalent (umlat-u going to u for exmaple) BUT we're okay with simply stripping the character to.
since this is when importing lots of data, it needs to be a fast built-in operator, hopefully...
Note: here is an example of the data. The file comes form windows and is 8bit ascii. when we import it and in our erb we display widget.name.inspect (instead of widget.name) we get:
"Chains \x96 Accessories"
so one example of the data is a "hyphen" that's actually 8 bit code 96.
--- when we changed our csv parse to assign fldval = d.encode('UTF-8')
it throws this error:
Encoding::UndefinedConversionError in StoresController#importfinderitems
"\x96" from ASCII-8BIT to UTF-8
what we're looking for is a simple way to just force it to be valid utf8 regardless of origin type, even if we simply strip non-ascii.
while not as 'nice' as forcing the encoding, this works at a slight expense to our import time:
d.to_s.strip.gsub(/\P{ASCII}/, '')
Thank you, Mladen!
Ruby 1.9 CSV has new parser that works with m17n. The parser works with Encoding of IO object in the string. Following methods: ::foreach, ::open, ::read, and ::readlines could take in optional options :encoding which you could specify the the Encoding.
For example:
CSV.read('/path/to/file', :encoding => 'windows-1251:utf-8')
Would convert all strings to UTF-8.
Also you can use the more standard encoding name 'ISO-8859-1'
CSV.read('/..', {:headers => true, :col_sep => ';', :encoding => 'ISO-8859-1'})
CSV.parse(File.read('/path/to/csv').scrub)
I answered a similar question that deals with reading external files in 1.9.2 with non-UTF-8 encodings. I think that answer will help you a lot: Character Encoding issue in Rails v3/Ruby 1.9.2
Note that you need to know the source encoding for you to convert it anything reliably. There are libraries like the one I linked to in my other answer that can help you determine this.
Also, if you aren't loading the data from a file, you can convert the encoding of a string in 1.9.2 quite easily:
'string'.encode('UTF-8')
However, it's rare that you're building a string in another encoding, and it's best to convert it at the time it's read into your environment if possible.
Ruby 1.9 can change string encoding with invalid detection and replacement:
str = str.encode('UTF-8', :invalid => :replace)
For unusual strings such as strings loaded from a file of unknown encoding, it's wise to use #encode instead of a regex, #gsub, or #delete, because these all need the string to be parsed-- but if the string is broken, it can't be parsed, so those methods fail.
If you get a message like this:
error ** from ASCII-8BIT to UTF-8
Then you're probably trying to convert a binary string that's already in UTF-8, and you can force UTF-8:
str.force_encoding('UTF-8')
If you know the original string is not in binary UTF-8, or if the output string has illiegal characters, then read up on Ruby encoding transliterations.
If you are using Rails, you can try to fix it with the following
'Your string with strange stuff ##~'.mb_chars.tidy_bytes
It removes you the invalid utf-8 chars and replaces it with valid ones.
More info: https://apidock.com/rails/String/mb_chars
Upload the CSV file to Google Docs Spreadsheet and re-download it as a CSV file. Import and voila! (Worked in my case)
Presumably Google converts it to the wanted format..
Source: Excel to CSV with UTF-8 Encoding
As mentioned by someone else, scrub works well to clean this up in Ruby 2.1+. If you have a large file you may not want to read the whole thing into memory, so you can use scrub like this:
data = IO::read(file_path).scrub("")
CSV.parse(data, :col_sep => ',', :headers => true) do |row|
puts row
end
I am using MAC and I was having the same error:
rescue in parse:Invalid byte sequence in UTF-8 in line 1 (CSV::MalformedCSVError)
I added :encoding => 'ISO-8859-1' that resolved my error and csv file could be read.
results = CSV.read("query_result.csv",{:headers => true, :encoding => 'ISO-8859-1'})
:headers => true : If set to :first_row or true, the initial row of the CSV file will be treated as a row of headers. If set to an Array, the contents will be used as the headers. If set to a String, the String is run through a call of ::parse_line with the same :col_sep, :row_sep, and :quote_char as this instance to produce an Array of headers. This setting causes #shift to return rows as CSV::Row objects instead of Arrays and #read to return CSV::Table objects instead of an Array of Arrays.
irb(main):024:0> rows = CSV.new(StringIO.new("a,b,c\n1,2,3"), headers: true)
=> <#CSV io_type:StringIO encoding:UTF-8 lineno:0 col_sep:"," row_sep:"\n" quote_char:"\"" headers:true>
irb(main):025:0> rows = CSV.new(StringIO.new("a,b,c\n1,2,3"), headers: true).to_a
=> [#<CSV::Row "a":"1" "b":"2" "c":"3">]
irb(main):026:0> rows.first['a']
=> "1"
In above example you can clearly see that this also enables us to use data as hashes.
The only thing you would need to be careful about while using headers: true that it won't allow any duplicate headers as keys are unique in hashes.
Only do this
anyobject.to_csv(:encoding => 'utf-8')