Xpath: Finding node next to node if present - xpath

Question

I'm trying to scrape a site using a highly varying HTML structure. The information at interest is not encapsulated. The only marker is a span with a target id TARGETID.
Structure is:
<h2>
<span class="TARGETID">TARGETID</span>
</h2>
<p> <!-- this is not always present, could be more p tags --> </p>
<ul> <!-- also not always present, if there, this is what we want --> </ul>
<h2>
<span class="SOMEIRRELEVANTID">IRRELEVANT</span>
</h2>
My approach was:
//h2/span[contains(text(), 'TARGETID')]/../following-sibling::ul[1][count(li) > 1][li]//a/text()
Which succeeds when a unordered list is present after the TARGETID, but if not, it takes the next unordered list it finds (which makes sense based on the query).
My question is: How can I limit the query to the nodes of two H2's, starting with the one containing a span with the target id and limited by any following H2 with a span of a different id?
Any hints are greatly appreciated.

Answer 1

This XPath,
//ul[preceding::h2[1][.='TARGETID']]//a
will select all a elements beneath a ul that occurs after a h2 with string value of "TARGETID" but before any other h2 elements.
So, for this expanded example,
<div>
<h2>
<span class="TARGETID">TARGETID</span>
</h2>
<p> <!-- this is not always present, could be more p tags --> </p>
<ul> link1 </ul>
<h2>
<span class="SOMEIRRELEVANTID">IRRELEVANT</span>
</h2>
<ul> link2 </ul>
<h2>
<span class="SOMEIRRELEVANTID">IRRELEVANT</span>
</h2>
</div>
it would select only
link1
and not link2, as requested.