Laravel: needing help querying two tables into one result - laravel

Question

Im interested in giving users the option to add articles to custom lists that they create. (like youtube's playlist feature).
I want to know how to show a 'checked' checkbox next to a list if the article already exists within it, so they don't add it twice.
My database tables:
list : | id | person_id | list_name | list_desc
list_ref : | id | list_id | article_id
My code for displaying lists.
$lists = Lists::where('person_id', Auth::user()->person_id)->get();
#foreach($lists as $list)
<input type="checkbox" id="available_list" value="{{ $list->id }}">
{{ $list->list_name }}
#endforeach
If anyone could help me understand the code to query the two tables to see if list already used || list is available.

Answer 1

You could use a raw expression in conjunction with a left join like this:
$lists = DB::table('list')->
leftJoin('list_ref', 'list_ref.list_id', '=', 'list.id')->
select(DB::raw('list.*, IF(list_ref.list_id = list.id, 1, 0) used'))->
where('person_id', Auth::user()->person_id)->
get();
The above uses a join to figure out which list rows has a corresponding key in the list_ref table. The result will contain a field called used that will tell if the entry has a reference in the list_ref table.
You should now be able to generate you form like this:
#foreach($lists as $list)
<input type="checkbox" id="available_list" value="{{ $list->id }}" {{ $list->used ? "CHECKED" : "" }}>
{{ $list->list_name }}
#endforeach

Answer 2

First crate class, here is example for facility
class HotelFacilities
{
public $facility_id;
public $facility;
public $status;
}
Get all data
$facilities = Facility::all();
Get user related data
$user_facilities = UserFacility::where('user_id', 3)->get();
//Here you add status
$array_hotel_facility = array();
for($i=0; $i<count($facilities); $i++)
{
$obj_hotel_facilities = new HotelFacilities;
$obj_hotel_facilities->facility_id = $facilities[$i]['id'];
$obj_hotel_facilities->facility = $facilities[$i]['facility'];
$obj_hotel_facilities->status = false;
for($j=0; $j<count($user_facilities); $j++)
{
if($user_facilities[$j]->facility_id == $facilities[$i]->id)
{
$obj_hotel_facilities->status = true;
}
}
//Pass this array to view
$array_hotel_facility[$i] = $obj_hotel_facilities;
}
//Pass to view
return view('extranet.view_facilities')->with('facilities', $array_hotel_facility);
//Generate UI like this
#foreach($facilities as $facility)
<div class="form-group col-md-3">
<div class="form-group">
<label>
<input type="checkbox" class="minimal" name="facilities[]" value="{{ $facility->facility_id }}" <?php if($facility->status){echo "checked";} ?>>
{{ $facility->facility }}
</label>
</div>
</div>
#endforeach