To be specific, I was trying this code:
package hello;
public class Hello {
Clock clock = new Clock();
public static void main(String args[]) {
clock.sayTime();
}
}
But it gave the error
Cannot access non-static field in static method main
So I changed the declaration of clock to this:
static Clock clock = new Clock();
And it worked. What does it mean to put that keyword before the declaration? What exactly will it do and/or restrict in terms of what can be done to that object?
static members belong to the class instead of a specific instance.
It means that only one instance of a static field exists[1] even if you create a million instances of the class or you don't create any. It will be shared by all instances.
Since static methods also do not belong to a specific instance, they can't refer to instance members. In the example given, main does not know which instance of the Hello class (and therefore which instance of the Clock class) it should refer to. static members can only refer to static members. Instance members can, of course access static members.
Side note: Of course, static members can access instance members through an object reference.
Example:
public class Example {
private static boolean staticField;
private boolean instanceField;
public static void main(String[] args) {
// a static method can access static fields
staticField = true;
// a static method can access instance fields through an object reference
Example instance = new Example();
instance.instanceField = true;
}
[1]: Depending on the runtime characteristics, it can be one per ClassLoader or AppDomain or thread, but that is beside the point.
It means that there is only one instance of "clock" in Hello, not one per each separate instance of the "Hello" class, or more-so, it means that there will be one commonly shared "clock" reference among all instances of the "Hello" class.
So if you were to do a "new Hello" anywhere in your code:
A- in the first scenario (before the change, without using "static"), it would make a new clock every time a "new Hello" is called, but
B- in the second scenario (after the change, using "static"), every "new Hello" instance would still share and use the initial and same "clock" reference first created.
Unless you needed "clock" somewhere outside of main, this would work just as well:
package hello;
public class Hello
{
public static void main(String args[])
{
Clock clock=new Clock();
clock.sayTime();
}
}
The static keyword means that something (a field, method or nested class) is related to the type rather than any particular instance of the type. So for example, one calls Math.sin(...) without any instance of the Math class, and indeed you can't create an instance of the Math class.
For more information, see the relevant bit of Oracle's Java Tutorial.
Sidenote
Java unfortunately allows you to access static members as if they were instance members, e.g.
// Bad code!
Thread.currentThread().sleep(5000);
someOtherThread.sleep(5000);
That makes it look as if sleep is an instance method, but it's actually a static method - it always makes the current thread sleep. It's better practice to make this clear in the calling code:
// Clearer
Thread.sleep(5000);
The static keyword in Java means that the variable or function is shared between all instances of that class as it belongs to the type, not the actual objects themselves.
So if you have a variable: private static int i = 0; and you increment it (i++) in one instance, the change will be reflected in all instances. i will now be 1 in all instances.
Static methods can be used without instantiating an object.
Basic usage of static members...
public class Hello
{
// value / method
public static String staticValue;
public String nonStaticValue;
}
class A
{
Hello hello = new Hello();
hello.staticValue = "abc";
hello.nonStaticValue = "xyz";
}
class B
{
Hello hello2 = new Hello(); // here staticValue = "abc"
hello2.staticValue; // will have value of "abc"
hello2.nonStaticValue; // will have value of null
}
That's how you can have values shared in all class members without sending class instance Hello to other class. And whit static you don't need to create class instance.
Hello hello = new Hello();
hello.staticValue = "abc";
You can just call static values or methods by class name:
Hello.staticValue = "abc";
Static means that you don't have to create an instance of the class to use the methods or variables associated with the class. In your example, you could call:
Hello.main(new String[]()) //main(...) is declared as a static function in the Hello class
directly, instead of:
Hello h = new Hello();
h.main(new String[]()); //main(...) is a non-static function linked with the "h" variable
From inside a static method (which belongs to a class) you cannot access any members which are not static, since their values depend on your instantiation of the class. A non-static Clock object, which is an instance member, would have a different value/reference for each instance of your Hello class, and therefore you could not access it from the static portion of the class.
Static in Java:
Static is a Non Access Modifier.
The static keyword belongs to the class than instance of the class.
can be used to attach a Variable or Method to a Class.
Static keyword CAN be used with:
Method
Variable
Class nested within another Class
Initialization Block
CAN'T be used with:
Class (Not Nested)
Constructor
Interfaces
Method Local Inner Class(Difference then nested class)
Inner Class methods
Instance Variables
Local Variables
Example:
Imagine the following example which has an instance variable named count which in incremented in the constructor:
package pkg;
class StaticExample {
int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 1 1
Since instance variable gets the memory at the time of object creation, each object will have the copy of the instance variable, if it is incremented, it won't reflect to other objects.
Now if we change the instance variable count to a static one then the program will produce different output:
package pkg;
class StaticExample {
static int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 2 3
In this case static variable will get the memory only once, if any object changes the value of the static variable, it will retain its value.
Static with Final:
The global variable which is declared as final and static remains unchanged for the whole execution. Because, Static members are stored in the class memory and they are loaded only once in the whole execution. They are common to all objects of the class. If you declare static variables as final, any of the objects can’t change their value as it is final. Therefore, variables declared as final and static are sometimes referred to as Constants. All fields of interfaces are referred as constants, because they are final and static by default.
Picture Resource : Final Static
To add to existing answers, let me try with a picture:
An interest rate of 2% is applied to ALL savings accounts. Hence it is static.
A balance should be individual, so it is not static.
This discussion has so far ignored classloader considerations. Strictly speaking, Java static fields are shared between all instances of a class for a given classloader.
A field can be assigned to either the class or an instance of a class. By default fields are instance variables. By using static the field becomes a class variable, thus there is one and only one clock. If you make a changes in one place, it's visible everywhere. Instance varables are changed independently of one another.
In Java, the static keyword can be simply regarded as indicating the following:
"without regard or relationship to any particular instance"
If you think of static in this way, it becomes easier to understand its use in the various contexts in which it is encountered:
A static field is a field that belongs to the class rather than to any particular instance
A static method is a method that has no notion of this; it is defined on the class and doesn't know about any particular instance of that class unless a reference is passed to it
A static member class is a nested class without any notion or knowledge of an instance of its enclosing class (unless a reference to an enclosing class instance is passed to it)
The keyword static is used to denote a field or a method as belonging to the class itself and not to any particular instance. Using your code, if the object Clock is static, all of the instances of the Hello class will share this Clock data member (field) in common. If you make it non-static, each individual instance of Hello will have a unique Clock.
You added a main method to your class Hello so that you could run the code. The problem with that is that the main method is static and as such, it cannot refer to non-static fields or methods inside of it. You can resolve this in two ways:
Make all fields and methods of the Hello class static so that they could be referred to inside the main method. This is not a good thing to do (or the wrong reason to make a field and/or a method static)
Create an instance of your Hello class inside the main method and access all its fields and methods the way they were intended to be accessed and used in the first place.
For you, this means the following change to your code:
package hello;
public class Hello {
private Clock clock = new Clock();
public Clock getClock() {
return clock;
}
public static void main(String args[]) {
Hello hello = new Hello();
hello.getClock().sayTime();
}
}
static methods don't use any instance variables of the class they are defined in. A very good explanation of the difference can be found on this page
I have developed a liking for static methods (only, if possible) in "helper" classes.
The calling class need not create another member (instance) variable of the helper class. You just call the methods of the helper class. Also the helper class is improved because you no longer need a constructor, and you need no member (instance) variables.
There are probably other advantages.
Static makes the clock member a class member instead of an instance member. Without the static keyword you would need to create an instance of the Hello class (which has a clock member variable) - e.g.
Hello hello = new Hello();
hello.clock.sayTime();
//Here is an example
public class StaticClass
{
static int version;
public void printVersion() {
System.out.println(version);
}
}
public class MainClass
{
public static void main(String args[]) {
StaticClass staticVar1 = new StaticClass();
staticVar1.version = 10;
staticVar1.printVersion() // Output 10
StaticClass staticVar2 = new StaticClass();
staticVar2.printVersion() // Output 10
staticVar2.version = 20;
staticVar2.printVersion() // Output 20
staticVar1.printVersion() // Output 20
}
}
Can also think of static members not having a "this" pointer. They are shared among all instances.
Understanding Static concepts
public class StaticPractise1 {
public static void main(String[] args) {
StaticPractise2 staticPractise2 = new StaticPractise2();
staticPractise2.printUddhav(); //true
StaticPractise2.printUddhav(); /* false, because printUddhav() is although inside StaticPractise2, but it is where exactly depends on PC program counter on runtime. */
StaticPractise2.printUddhavsStatic1(); //true
staticPractise2.printUddhavsStatic1(); /*false, because, when staticPractise2 is blueprinted, it tracks everything other than static things and it organizes in its own heap. So, class static methods, object can't reference */
}
}
Second Class
public class StaticPractise2 {
public static void printUddhavsStatic1() {
System.out.println("Uddhav");
}
public void printUddhav() {
System.out.println("Uddhav");
}
}
main() is a static method which has two fundamental restrictions:
The static method cannot use a non-static data member or directly call non-static method.
this() and super() cannot be used in static context.
class A {
int a = 40; //non static
public static void main(String args[]) {
System.out.println(a);
}
}
Output: Compile Time Error
A question was asked here about the choice of the word 'static' for this concept. It was dup'd to this question, but I don't think the etymology has been clearly addressed. So...
It's due to keyword reuse, starting with C.
Consider data declarations in C (inside a function body):
void f() {
int foo = 1;
static int bar = 2;
:
}
The variable foo is created on the stack when the function is entered (and destroyed when the function terminates). By contrast, bar is always there, so it's 'static' in the sense of common English - it's not going anywhere.
Java, and similar languages, have the same concept for data. Data can either be allocated per instance of the class (per object) or once for the entire class. Since Java aims to have familiar syntax for C/C++ programmers, the 'static' keyword is appropriate here.
class C {
int foo = 1;
static int bar = 2;
:
}
Lastly, we come to methods.
class C {
int foo() { ... }
static int bar() { ... }
:
}
There is, conceptually speaking, an instance of foo() for every instance of class C. There is only one instance of bar() for the entire class C. This is parallel to the case we discussed for data, and therefore using 'static' is again a sensible choice, especially if you don't want to add more reserved keywords to your language.
Static Variables Can only be accessed only in static methods, so when we declare the static variables those getter and setter methods will be static methods
static methods is a class level we can access using class name
The following is example for Static Variables Getters And Setters:
public class Static
{
private static String owner;
private static int rent;
private String car;
public String getCar() {
return car;
}
public void setCar(String car) {
this.car = car;
}
public static int getRent() {
return rent;
}
public static void setRent(int rent) {
Static.rent = rent;
}
public static String getOwner() {
return owner;
}
public static void setOwner(String owner) {
Static.owner = owner;
}
}
A member in a Java program can be declared as static using the keyword “static” preceding its declaration/definition. When a member is declared static, then it essentially means that the member is shared by all the instances of a class without making copies of per instance.
Thus static is a non-class modifier used in Java and can be applied to the following members:
Variables
Methods
Blocks
Classes (more specifically, nested classes)
When a member is declared static, then it can be accessed without using an object. This means that before a class is instantiated, the static member is active and accessible. Unlike other non-static class members that cease to exist when the object of the class goes out of scope, the static member is still obviously active.
Static Variable in Java
A member variable of a class that is declared as static is called the Static Variable. It is also called as the “Class variable”. Once the variable is declared as static, memory is allocated only once and not every time when a class is instantiated. Hence you can access the static variable without a reference to an object.
The following Java program depicts the usage of Static variables:
class Main
{
// static variables a and b
static int a = 10;
static int b;
static void printStatic()
{
a = a /2;
b = a;
System.out.println("printStatic::Value of a : "+a + " Value of b :
"+b);
}
public static void main(String[] args)
{
printStatic();
b = a*5;
a++;
System.out.println("main::Value of a : "+a + " Value of b : "+b);
}
}
output::
printStatic::Value of a : Value of b : 5
main::Value of a : 6 Value of b : 25
In the above program, we have two static variables i.e. a and b. We modify these variables in a function “printStatic” as well as in “main”. Note that the values of these static variables are preserved across the functions even when the scope of the function ends. The output shows the values of variables in two functions.
Static Method
A method in Java is static when it is preceded by the keyword “static”.
Some points that you need to remember about the static method include:
A static method belongs to the class as against other non-static
methods that are invoked using the instance of a class.
To invoke a static method, you don’t need a class object.
The static data members of the class are accessible to the static
method. The static method can even change the values of the static
data member.
A static method cannot have a reference to ‘this’ or ‘super’ members.
Even if a static method tries to refer them, it will be a compiler
error.
Just like static data, the static method can also call other static
methods. A static method cannot refer to non-static data members or
variables and cannot call non-static methods too.
The following program shows the implementation of the static method in Java:
class Main
{
// static method
static void static_method()
{
System.out.println("Static method in Java...called without any
object");
}
public static void main(String[] args)
{
static_method();
}
}
output:
Static method in Java...called without any object
Static Block In Java
Just as you have function blocks in programming languages like C++, C#, etc. in Java also, there is a special block called “static” block that usually includes a block of code related to static data.
This static block is executed at the moment when the first object of the class is created (precisely at the time of classloading) or when the static member inside the block is used.
The following program shows the usage of a static block.
class Main
{
static int sum = 0;
static int val1 = 5;
static int val2;
// static block
static {
sum = val1 + val2;
System.out.println("In static block, val1: " + val1 + " val2: "+
val2 + " sum:" + sum);
val2 = val1 * 3;
sum = val1 + val2;
}
public static void main(String[] args)
{
System.out.println("In main function, val1: " + val1 + " val2: "+ val2 + " sum:" + sum);
}
}
output:
In static block, val1: 5 val2: 0 sum:5
In main function, val1: val2: 15 sum:20
Static Class
In Java, you have static blocks, static methods, and even static variables. Hence it’s obvious that you can also have static classes. In Java, it is possible to have a class inside another class and this is called a Nested class. The class that encloses the nested class is called the Outer class.
In Java, although you can declare a nested class as Static it is not possible to have the outer class as Static.
Let’s now explore the static nested classes in Java.
Static Nested Class
As already mentioned, you can have a nested class in Java declared as static. The static nested class differs from the non-static nested class(inner class) in certain aspects as listed below.
Unlike the non-static nested class, the nested static class doesn’t need an outer class reference.
A static nested class can access only static members of the outer class as against the non-static classes that can access static as well as non-static members of the outer class.
An example of a static nested class is given below.
class Main{
private static String str = "SoftwareTestingHelp";
//Static nested class
static class NestedClass{
//non-static method
public void display() {
System.out.println("Static string in OuterClass: " + str);
}
}
public static void main(String args[])
{
Main.NestedClassobj = new Main.NestedClass();
obj.display();
}
}
output
Static string in OuterClass: SoftwareTestingHelp
I think this is how static keyword works in java.
Good day, I have a fairly simple question to experienced C# programmers. Basically, I would like to have an abstract base class that contains a function that relies on the values of child classes. I have tried code similar to the following, but the compiler complains that SomeVariable is null when SomeFunction() attempts to use it.
Base class:
public abstract class BaseClass
{
protected virtual SomeType SomeVariable;
public BaseClass()
{
this.SomeFunction();
}
protected void SomeFunction()
{
//DO SOMETHING WITH SomeVariable
}
}
A child class:
public class ChildClass:BaseClass
{
protected override SomeType SomeVariable=SomeValue;
}
Now I would expect that when I do:
ChildClass CC=new ChildClass();
A new instance of ChildClass should be made and CC would run its inherited SomeFunction using SomeValue. However, this is not what happens. The compiler complains that SomeVariable is null in BaseClass. Is what I want to do even possible in C#? I have used other managed languages that allow me to do such things, so I certain I am just making a simple mistake here.
Any help is greatly appreciated, thank you.
You got it almost right, but you need to use properties instead of variables:
public abstract class BaseClass {
protected SomeType SomeProperty {get; set}
public BaseClass() {
// You cannot call this.SomeFunction() here: the property is not initialized yet
}
protected void SomeFunction() {
//DO SOMETHING WITH SomeProperty
}
}
public class ChildClass:BaseClass {
public ChildClass() {
SomeProperty=SomeValue;
}
}
You cannot use FomeFunction in the constructor because SomeProperty has not been initialized by the derived class. Outside of constructor it's fine, though. In general, accessing virtual members in the constructor should be considered suspicious.
If you must pass values from derived classes to base class constructor, it's best to do it explicitly through parameters of a protected constructor.
if i have a static method Only advantage is that we have single copy.Need not have a object to call the Method. The same can be done be creating an object i.e we can call method with object. Why should we have static method. Can someone provide a example to explain?
Static methods can be useful when you have private constructors, because you want to abstract the instantiation process.
For example in C++:
class Foo {
Foo() {}
public:
static Foo *create() {
return new Foo;
}
};
In that example the abstraction just called an otherwise in accessible constructor, but in practice you might want to have a pool of objects which is shared and so the create() method would be managing this for you.
Sometimes when you have const members which need to be initalised at construction time it can be cleaner to move the logic for this into a private static method, e.g.:
struct Foo;
struct Bar {
Bar() : f(make()) {
}
private:
const Foo f;
static Foo make() {
// Create it here
}
};
The static method is used when developer is really sure the method is only have one instance in the class. There are no other instance that can change that.
eg :
public class People
{
private
public static Int32 GetValue(Int x)
{
return x + 3;
}
}
So even you are make instances of object people, the return from getvalue static method only produce x + 3.
It is usually used when you are really sure to make a functional method like math or physics method.
You can refer to functional programming that using static point of view.
Some of the old school guys are overusing the static method instead of doing OOP approach.
eg:
public class People
{
public static DataSet GetPeopleById(String personId)
{ .... implementation that using SQL query or stored procedure and return dataset ... }
public static DataSet GetXXXXXXX(String name, DateTime datex)
{ .... implementation ... }
}
The implementation above can be thousands of lines
This style happens everywhere to make it like OOP style (because it happen in the class) but thinking like procedural approach.
This is a help since not all people understand OOP style rather than like OOP style.
The other advantage using static are saving memory footprints and faster.
You can see in the blogs : http://www.dotnetperls.com/callvirt
Sorry for the vague title, but I'm not sure what this is called.
Say I add IDisposable to my class, Visual Studio can create the method stub for me. But it creates the stub like:
void IDisposable.Dispose()
I don't follow what this syntax is doing. Why do it like this instead of public void Dispose()?
And with the first syntax, I couldn't work out how to call Dispose() from within my class (in my destructor).
When you implement an interface member explicitly, which is what the generated code is doing, you can't access the member through the class instance. Instead you have to call it through an instance of the interface. For example:
class MyClass : IDisposable
{
void IDisposable.Dispose()
{
// Do Stuff
}
~MyClass()
{
IDisposable me = (IDisposable)this;
me.Dispose();
}
}
This enables you to implement two interfaces with a member of the same name and explicitly call either member independently.
interface IExplict1
{
string InterfaceName();
}
interface IExplict2
{
string InterfaceName();
}
class MyClass : IExplict1, IExplict2
{
string IExplict1.InterfaceName()
{
return "IExplicit1";
}
string IExplict2.InterfaceName()
{
return "IExplicit2";
}
}
public static void Main()
{
MyClass myInstance = new MyClass();
Console.WriteLine( ((IExplcit1)myInstance).InstanceName() ); // outputs "IExplicit1"
IExplicit2 myExplicit2Instance = (IExplicit2)myInstance;
Console.WriteLine( myExplicit2Instance.InstanceName() ); // outputs "IExplicit2"
}
Visual studio gives you two options:
Implement
Implement explicit
You normally choose the first one (non-explicit): which gives you the behaviour you want.
The "explicit" option is useful if you inherit the same method from two different interfaces, i.e multiple inheritance (which isn't usually).
Members of an interface type are always public. Which requires their method implementation to be public as well. This doesn't compile for example:
interface IFoo { void Bar(); }
class Baz : IFoo {
private void Bar() { } // CS0737
}
Explicit interface implementation provides a syntax that allows the method to be private:
class Baz : IFoo {
void IFoo.Bar() { } // No error
}
A classic use for this is to hide the implementation of a base interface type. IEnumerable<> would be a very good example:
class Baz : IEnumerable<Foo> {
public IEnumerator<Foo> GetEnumerator() {}
System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator() { }
}
Note how the generic version is accessible, the non-generic version is hidden. That both discourages its use and avoids a compile error because of a duplicate method.
In your case, implementing Dispose() explicitly is wrong. You wrote Dispose() to allow the client code to call it, forcing it to cast to IDisposable to make the call doesn't make sense.
Also, calling Dispose() from a finalizer is a code smell. The standard pattern is to add a protected Dispose(bool disposing) method to your class.