How can I make this rectangle slow down? - processing

Question

The rectangle is moving and when I click it needs to be moving at 0.1 instead of 3. I don't know how to code the mousePressed part so that it stays at 0.1 the whole time.
float stripeX = 0;
void setup() {
size(500, 300);
}
void draw() {
background(255);
fill(10, 10, 100);
rect(stripeX, 90, 150, 250);
stripeX = stripeX + 3;
stripeX = stripeX % width;
}
void mousePressed() {
stripeX = stripeX - 2.9;
}

Answer 1

You could just use the mousePressed variable along with an if statement inside the draw() function:
float stripeX = 0;
void setup() {
size(500, 300);
}
void draw() {
background(255);
fill(10, 10, 100);
rect(stripeX, 90, 150, 250);
if(mousePressed){
stripeX = stripeX + .1;
}
else{
stripeX = stripeX + 3;
}
stripeX = stripeX % width;
}

Answer 2

The best way in Your case is to use mouseReleased() method:
float stripeX, deltaX;
void setup() {
size(500, 300);
stripeX = 0f; // init values here, in setup()
deltaX = 3f;
}
void draw() {
background(255);
fill(10, 10, 100);
rect(stripeX, 90, 150, 250);
stripeX += deltaX;
stripeX = stripeX % width;
}
void mousePressed(){
deltaX = 0.1;
}
void mouseReleased(){
deltaX = 3f;
}

Answer 3

This is all a bit dicey. How often is draw() called? On every frame? Generally it's a bad idea to adjust things in a draw function, it should just draw.
To hack it somewhat
float stripeX = 0;
float deltaX = 3.0;
void draw()
{
//omitted some code
stripeX += deltaX;
}
void mousePressed()
{
if(deltaX > 0.1)
deltaX = 0.1;
else
deltaX = 3.0; // let a second press put it back to 3.0
}
However you probably want to put it back to 3.0 on mouse up. You haven't
given enough information to know how to intercept that event.