How to reduce join operation to a single row in Oracle? - oracle

This example is invented for the purpose of the question.
SELECT
PR.PROVINCE_NAME
,CO.COUNTRY_NAME
FROM
PROVINCE PR
JOIN COUNTRY CO ON CO.COUNTRY_ID=PR.COUNTRY_ID
WHERE
PR.PROVINCE_ID IN (1,2)
Let's assume that COUNTRY_ID is not the Primary Key in the Country table and the above join on Country table returns potentially multiple rows. We don't know how many rows and we don't care why there are multiple ones. We only want to join on one of them, so we get one row per Province.
I tried subquery for the join but can't pass in PR.COUNTRY_ID for Oracle 11.2. Are there any other ways that this can be achieved?

A typical safe approach of handling tables without PK is to extend the duplicated column with a unique index (row_numer of the duplicated row)
In your case this would be:
with COUNTRY_UNIQUE as (
select COUNTRY_ID,
row_number() over (partition by COUNTRY_ID order by COUNTRY_NAME) rn,
COUNTRY_NAME
from country)
select * from COUNTRY_UNIQUE
order by COUNTRY_ID, rn;
leading to
COUNTRY_ID RN COUNTRY_NAME
---------- ---------- ------------
1 1 C1
2 1 C2
2 2 C3
The combination of COUNTRY_IDand RN is unique, so if you constraint only RN = 1 the COUNTRY_ID is unique.
You may define the order of the duplicated records and control with it the selection - in our case we choose the smalest COUNTRY_NAME.
The whole join used this subquery and constraints the countries on RN = 1
with COUNTRY_UNIQUE as (
select COUNTRY_ID,
row_number() over (partition by COUNTRY_ID order by COUNTRY_NAME) rn,
COUNTRY_NAME
from country)
SELECT
PR.PROVINCE_NAME
,CO.COUNTRY_NAME
FROM
PROVINCE PR
JOIN COUNTRY_UNIQUE CO ON CO.COUNTRY_ID=PR.COUNTRY_ID
WHERE
PR.PROVINCE_ID IN (1,2)
AND CO.RN = 1; /* consider only unique countries */

If you have Oracle 12c, you can use a LATERAL view in the join. Like this:
SELECT
PR.PROVINCE_NAME
,CO.COUNTRY_NAME
FROM
PROVINCE PR
CROSS JOIN LATERAL (
SELECT * FROM COUNTRY CO
WHERE CO.COUNTRY_ID=PR.COUNTRY_ID
FETCH FIRST 1 ROWS ONLY) CO
WHERE
PR.PROVINCE_ID IN (1,2)
Update for Oracle 11.2
In Oracle 11.2, you can use something along these lines. Depending on the size of COUNTRY and how many duplicates there are per COUNTRY_ID, it could perform as well or better than the 12c approach. (Fewer buffer gets but more memory required).
SELECT pr.province_name,
co.country_name
FROM province pr
INNER JOIN (SELECT *
FROM (SELECT co.*,
ROW_NUMBER () OVER (PARTITION BY co.country_id ORDER BY co.country_name) rn
FROM country co)
WHERE rn = 1) co
ON co.country_id = pr.country_id
WHERE pr.province_id IN (1, 2)

Related

ORACLE Query to find value in other table based on dates

I have two tables, Table A has an ID and an Event Date and Table B has an ID, a Description and an Event Date.
Not all IDs in Table A appear in Table B and some IDs appear multiple times in Table B with different Descriptions for each event.
The Description in Table B is an attribute that can change over time, the Event date in Table B is the date that a given ID's Description changes from its default value (kept in another table) to the new value.
I want to find the Description in Table B that matches the Event Date in Table A so, for example
Table Sample Data
A1234 would return Green and A4567 would return Null
I can't create tables here so I need to be able to this with a query.
This query will select last description from before the event:
SELECT * FROM (
SELECT tabA.id, tabA.event_date, tabB.description,
ROW_NUMBER() OVER(PARTITION BY tabB.id ORDER BY tabB.event_date DESC) rn
FROM Table_A tabA
LEFT JOIN Table_B tabB ON tabA.id = tabB.id AND tabB.event_date <= tabA.event_date
) WHERE rn = 1
If I understand well your need, this could be a way:
select a.id, description
from tableA A
left join
(select id,
description,
event_date from_date,
lead(event_date) over (partition by id order by event_date) -1 as to_date
from tableB
) B
on (A.id = B.id and a.event_date between b.from_date and b.to_date)
The idea here is to evaluate, for each row in tableB the range of dates for which that row, and its description, is valid; given this, a simple join should do the job.
You can left join tables like:
select a.ID , b1.DESCRIPTION
from TABLE_A a
left join TABLE_B b1 on a.ID = b1.id and a.EVENT_DATE > b1.EVENT_DATE
left join TABLE_B b2 on a.ID = b2.id and b1.EVENT_DATE < b2.EVENT_DATE and a.EVENT_DATE > b2.EVENT_DATE
where b1.id is null or b2.EVENT_DATE is null;

Top 3 Max Score for each section SQL Developer

I looked at the other questions related to this but it did not work. I even played around with Dense_Rank and still couldn't get the right answer.
Using the Oracle Student Scheme Data. I am trying to find the highest 3 grades for each section based on two tables ( NOT the top 3 rows for each sections. )
This is based off the Student and the Grade table from the Student Scheme
I am using the Oracle Developer 10 and it does not look like it takes the LIMIT function. Cause it gives me the error
missing right parenthesis
select
g.SECTION_ID,g.NUMERIC_GRADE, s.First_Name,s.Last_Name
from GRADE g Join Student s
On g.student_ID = s.student_ID
and Grade_Type_Code='MT'
Where numeric_grade in(Select distinct numeric_grade
from grade
order by numeric_grade desc limit 3);
You can use ROWNUM in Oracle:
SELECT g.SECTION_ID,
g.NUMERIC_GRADE,
s.First_Name,
s.Last_Name
FROM grade g
JOIN Student s
ON g.student_ID = s.student_ID
AND Grade_Type_Code='MT'
WHERE numeric_grade in (SELECT numeric_grade
FROM (SELECT DISTINCT numeric_grade
FROM grade
ORDER BY numeric_grade desc)
WHERE ROWNUM <=3);
Solution with dense_rank:
select section_id, numeric_grade, first_name, last_name
from (
select g.section_id, g.numeric_grade, s.First_Name,s.Last_Name,
dense_rank() over (partition by g.section_id
order by g.numeric_grade desc) rnk
from GRADE g
join Student s on g.student_ID = s.student_ID
and Grade_Type_Code='MT' )
where rnk < 4
order by section_id, numeric_grade desc
SQLFiddle demo

Joining the top result in Oracle

I'm using this query:
SELECT *
FROM HISTORY
LEFT JOIN CUSTOMER ON CUSTOMER.CUST_NUMBER = HISTORY.CUST_NUMBER
LEFT JOIN (
Select LOAN_DATE, CUST_NUMBER, ACCOUNT_NUMBER, STOCK_NUMBER, LOC_SALE
From LOAN
WHERE ACCOUNT_NUMBER != 'DD'
ORDER BY LOAN_DATE DESC
) LOAN ON LOAN.CUST_NUMBER = HISTORY.CUST_NUMBER
order by DATE desc
But I want only the top result from the loan table to be joined (Most recent by Loan_date). For some reason, it's getting three records (one for each loan on the customer I'm looking at). I'm sure I'm missing something simple?
If you're after joining the latest loan row per cust_number, then this ought to do the trick:
select *
from history
left join customer on customer.cust_number = history.cust_number
left join (select loan_date,
cust_number,
account_number,
stock_number,
loc_sale
from (select loan_date,
cust_number,
account_number,
stock_number,
loc_sale,
row_number() over (partition by cust_number
order by loan_date desc) rn
from loan
where account_number != 'DD')
where rn = 1) loan on loan.cust_number = history.cust_number
order by date desc;
If there are two rows with the same loan_date per cust_number and you want to retrieve both, then change the row_number() analytic function for rank().
If you only want to retreive one row, then you'd have to make sure you add additional columns into the order by, to make sure that the tied rows always display in the same order, otherwise you could find that sometimes you get different rows returned on subsequent runs of the query.

Oracle join rows in order where order is defined differently on each table

I have two tables
TABLE_A with columns project_id, id and load_date
and TABLE_B with columns project_id, delete_flag and delete_date
where TABLE_A.load_date is a new column and I want to populate it based on TABLE_B.delete_date for historic data. Basically, a file has been repeatedly loaded into the system and historically we didn't keep track of when it was loaded. However, each time the file is re-loaded, the previous version of it is updated in TABLE_B with a delete_date (i.e. a soft delete). The previous version just stays in TABLE_A without any changes.
I would like to populate TABLE_A.load_date based on matching projects in TABLE_B. The oldest row in TABLE_A (smallest TABLE_A.id) matches the oldest row in TABLE_B (oldest delete_date), etc. So the rows should match up if you keep picking the next one in order from each table. But I don't know how to turn that into an Oracle statement. What I've got so far is this which doesn't deal with matching on row order:
MERGE INTO TABLE_A a
USING
(
SELECT PROJECT_ID, DELETE_DATE
FROM TABLE_B
WHERE DELETE_FLAG = 'Y'
ORDER BY DELETE_DATE ASC
) b ON (a.PROJECT_ID = b.PROJECT_ID)
WHEN MATCHED THEN UPDATE
SET a.LOAD_DATE = p.DELETE_DATE;
This merge should do the work, as far as I properly understood your criteria:
merge into table_a ta
using (
select pid project_id, id, delete_date
from (
select project_id pid, id,
row_number() over (partition by project_id order by id) rn
from table_a) a
join (
select project_id pid, delete_date,
row_number() over (partition by project_id order by delete_date ) rn
from table_b
where delete_flag='Y') b using (pid, rn) ) tb
on (ta.project_id = tb.project_id and ta.id = tb.id)
when matched then update
set ta.load_date = tb.delete_date

How to lists the maximum of counting with where syntax?

For Oracle,
I have 2 tables; first is Store and another is Book whereas they are connected by store ID (PK FK).
I would like to lists the name of the store which has the highest numbers of books.
However, the result showed every store in orders but I just want the highest.
SELECT STORE.STORE_NAME
FROM STORE, BOOK
WHERE STORE.STORE_ID=BOOK.BOOK_STOREID
GROUP BY STORE.STORE_NAME
ORDER BY COUNT(BOOK.BOOK_STOREID) DESC;
the result is
Store:
D
E
F
B
A
C
It should be only 'D'. What should I do? Thank you.
Try
SELECT STORE_NAME
FROM
(SELECT STORE.STORE_NAME
FROM STORE, BOOK
WHERE STORE.STORE_ID=BOOK.BOOK_STOREID
GROUP BY STORE.STORE_NAME
ORDER BY COUNT(BOOK.BOOK_STOREID) DESC)
WHERE rownum = 1
Here is a sqlfiddle demo
BTW, you can also use row_number() function
select STORE_NAME
from
(SELECT STORE.STORE_NAME,
row_number() over( order by COUNT(BOOK.BOOK_STOREID)desc) rn
FROM STORE join BOOK on STORE.STORE_ID=BOOK.BOOK_STOREID
group by STORE.STORE_NAME)
where rn = 1;
UPDATE If you want to see all stores which have the max number of books you can use rank instead of row_number:
select STORE_NAME
from
(SELECT STORE.STORE_NAME,
rank() over( order by COUNT(BOOK.BOOK_STOREID)desc) rn
FROM STORE join BOOK on STORE.STORE_ID=BOOK.BOOK_STOREID
group by STORE.STORE_NAME)
where rn = 1;
Just for fun, here's another formulation:
with store_counts as (
select store_name,
count(*) books
from store join book on store_id=book_storeid
group by store_name)
select *
from store_counts
where books = (
select max(books)
from store_counts)

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