I want the date format Thu Nov 3 17:21:08 2016 to be converted to Thursday, 3 November 2016 7:48:24 PM AEDT .
Actually, i want to achieve in converting the 12hrs time to 24hrs format using a shell script .
Thanks
I believe below command would help you to go ahead:
date +"%T"
Related
Basically, I want to take a time, and day of the week, in UTC+8, and adjust the datetime object to a given UTC offset, within bash, I don't have any code to show because I'm not sure how to start attempting this in the first place honestly
(I'm writing a custom script for a friend who lives in UTC+8 and want to make the input as easy as possible for them, basically they just give it a time in their timezone, and a day of the week, and it'll tell them what date and time that'll be in a different timezone, for an overarching purpose)
For a reference, look at the section 1 of the manual page for "date":
In your shell, just type: man 1 date
or see the online man page:
https://man7.org/linux/man-pages/man1/date.1.html
One way is to parse the date into the number of seconds since epoch (since 1970), and then convert that number of seconds into the format you want:
For example:
$ date +%s --date='2022-12-27 11:30:17 +008'
1672140137
$ date +%c --date='#1672140137'
Tue 27 Dec 2022 06:22:17 AM EST
or you could also convert to ISO format then back to local time
$ date -Iseconds --date='TZ="GMT" 2022-12-22 11:33:44 +08'
2022-12-21T22:33:44-05:00
$ date --date='2022-12-21T22:33:44-05:00'
Wed 21 Dec 2022 10:33:44 PM EST
I hope this helps you get started with some ideas for converting to/from different timezones.
Also, to help with user input, you can show the current month calendar using cal
$ cal
December 2022
Su Mo Tu We Th Fr Sa
1 2 3
4 5 6 7 8 9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25 26 27 28 29 30 31
$ date --date='Fri 08:30'
Fri 30 Dec 2022 08:30:00 AM EST
In the above example, I specified "Fri 08:30" which gets set to the next Friday at 08:30 in the morning for my local timezone.
I have extracted the current month using
currentMonth=`date +"%b"`
I want to get all previous five months in a file. Suppose its October now, i want Sep, Aug, Jul, Jun, May in a file. I tried using multiple utilities like cal, ncal, date but could not achieve this.
I want the months in the file as
Sep
Aug
Jul
Jun
May
Any help or suggestion is greatly appreciated.
Simple bash/shell solution (for Unix):
for i in 1 2 3 4 5; do date -d" - $i month" +%b; done
The output:
Sep
Aug
Jul
Jun
May
For MacOS:
for i in {1..5}; do date -v-"$i"m +%b; done
I have the following Unix timestamp: 1478698378000
And I'm trying to show this as a datetime in Ruby, e.g.
<%= Time.at(#timestamp).to_datetime %>
Which should be returning a date of: Wed, 09 Nov 2016 13:32:58 GMT but the above code actually returns a date of: 48828-02-01T13:26:40+00:00 Ignore formatting!
As you can see it thinks that timestamp is 2nd Feb 48828 13:26:40.
Why is the datetime coming out completely incorrect and the year so far into the future like that? Checking the timestamp on http://www.epochconverter.com/ reveals the timestamp to be correct, so it's Ruby that's returning it incorrectly.
Time.at expects seconds as an argument and your timestamp is an amount of milliseconds. See documentation on Time.at
Why won’t you check the unix timestamp correctness against “Fashion Week Magazine” or “Cosmopolitan” Site?
Unix timestamp is an amount of seconds lasted since 1970-01-01 UTC:
date --date='#1478698378000'
mar feb 1 14:26:40 CET 48828
BTW, dropping last three zeroes gives you back what you’ve expected:
date --date='#1478698378'
mié nov 9 14:32:58 CET 2016
I am using git-bash on a Windows system.
The Windows clock shows local time, but inside git-bash everything is in GMT time:
$ date
Mon Mar 31 16:08:57 GMT 2014
Also setting TZ will not change things:
$ TZ="Europe/Berlin" date
Mon Mar 31 16:09:01 GMT 2014
Similarly all times it git log are GMT only.
Is there a way to set the correct timezone in git-bash?
On Windows the TZ variable seems to work differently.
To get the German timezone you have to write:
TZ=GST-1GDT date
If you set it to some "invalid" value like "Europe/Berlin" it will default to GMT.
The same seems to happen on my system when TZ is not set at all.
With the above setting I get Thu Apr 17 16:23:23 GDT 2014 which is not exactly the same as Thu Apr 17 16:23:23 CEST 2014, but at least the time looks right.
Same problem here in my script. Windows was showing 15:47 and the "date" command in gitbash was answering 13:47.
export TZ="CEST-2"
This fixed the problem for me. I wanted Paris time.
To get the date of the last sunday one could use date --date="last sun" for Linux and date -j -v-sun for BSD.
How is it done however if I do have week numbers (1 to 7) instead of strings? I could always use a case-statement to convert the numbers to strings, but I bet there is a better solution for this?!
Thanks for your help.
Use an array:
number=1
days=(zero sun mon tue wed thu fri sat)
date --date="last ${days[number]}"