Golang dynamically creating member of struct - go

Question

I know there is struct in Go, but for all I know, you have to define struct
type Circle struct{
x,y,r float64
}
I am wondering how you can declare a new variable that doesn't exist in the struct
circle := new(Circle)
circle.color = "black"

Answer 1

You will need to use a map (of type map[string]interface{}) to work with dynamic JSON. Here is an example of creating a new map:
// Initial declaration
m := map[string]interface{}{
"key": "value",
}
// Dynamically add a sub-map
m["sub"] = map[string]interface{}{
"deepKey": "deepValue",
}
Unmarshalling JSON into a map looks like:
var f interface{}
err := json.Unmarshal(b, &f)
The code above would leave you with a map in f, with a structure resembling:
f = map[string]interface{}{
"Name": "Wednesday",
"Age": 6,
"Parents": []interface{}{
"Gomez",
"Morticia",
},
}
You will need to use a type assertion to access it, otherwise Go won't know it's a map:
m := f.(map[string]interface{})
You will also need to use assertions or type switches on each item you pull out of the map. Dealing with unstructured JSON is a hassle.
More information:
https://blog.golang.org/json-and-go
https://godoc.org/encoding/json#Unmarshal

Answer 2

I've started to work on this small repository https://github.com/Ompluscator/dynamic-struct
It's possible at this point to extend existing struct in runtime, by passing a instance of struct and modifying fields (adding, removing, changing types and tags).
Still in progress, so don't expect something huge :)
EDIT: At this point, work on library is done, and it looks stable for last a couple of months :)

Answer 3

You can do it using reflect package, check StructOf method it allows you to create a new struct from []reflect.StructField. Example:
func main() {
typ := reflect.StructOf([]reflect.StructField{
{
Name: "Height",
Type: reflect.TypeOf(float64(0)),
Tag: `json:"height"`,
},
{
Name: "Age",
Type: reflect.TypeOf(int(0)),
Tag: `json:"age"`,
},
})
v := reflect.New(typ).Elem()
v.Field(0).SetFloat(0.4)
v.Field(1).SetInt(2)
s := v.Addr().Interface()
w := new(bytes.Buffer)
if err := json.NewEncoder(w).Encode(s); err != nil {
panic(err)
}
fmt.Printf("value: %+v\n", s)
fmt.Printf("json: %s", w.Bytes())
r := bytes.NewReader([]byte(`{"height":1.5,"age":10}`))
if err := json.NewDecoder(r).Decode(s); err != nil {
panic(err)
}
fmt.Printf("value: %+v\n", s)
}

Answer 4

You can't. Go is statically typed, and does not allow such constructs.
Structs have a layout in memory that directly related to the definition, and there's no where to store such additional fields.
You can use a map instead. Moreover, you can use &circle as a key or part of a key, to associate map elements with arbitrary structs.
type key struct {
target interface{}
field string
}
x := make(map[key]string)
x[key{ target: circle, field: "color" }] = "black"