I'm working on mongo with spring data and using the query "findBy" based on property fields.
My goal will be find same value across multiple properties by OR clause like this:
List<Event> findByCreatorOrOrganizersOrGuests(User user);
this query involves 3 properties: "creator", "organizers" and "guests" that are a single value (creator) and 2 lists (organizers and guests) that contains the same class type (User)
at compile time I receive this error:
org.springframework.data.repository.query.ParameterOutOfBoundsException: Invalid parameter index! You seem to have declare too little query method parameters!
Do I need to repeat the same parameter 3 times? There's no workaround?
thanks
The using of Mongo queries for lists are not so efficient even if you define it with an index.
Another important thing is that the query:
List<Event> findByCreatorOrOrganizersOrGuests(User user);
includes some syntax errors (The MongoDB expects to get 3 parameters as variables int the ( ) relatively to the findBy keys, the return value should be inserted into a list object, and I am not sure that the Or in the find query is legal syntax.
As a concept the DB documents should have a good ability to be searched, cause it is the most expensive action.
When find using OR in MongoDB the direct query should looks like that:
def events = find({ $or: [ { user.username: { $lt: 20 } }, { price: 10 } ] } )
While searching in a list this is should be different, so please follow the links I attached.
When I try to think of the use you are looking for, I would suggest a different aspect. If the events is what interest you please read about the AbstractPersistenceEventListener. By define the appropriate
void onPostInsert(entity) {}
void onPostUpdate(entity) {}
void onPostDelete(entity) {}
You get all the events for each of the objects you want to listen to.
Here are 2 a great examples:
Example 1
Example 2
Related
So I'm doing some tests with GraphQL, and I'm failing in doing something that I believe is fairly simple.
When going to the GraphQL demo site (https://graphql.org/swapi-graphql) I'm presented with a default query which goes like this:
{
allFilms {
films {
title,
director,
releaseDate
}
}
}
This works as expected and returns a list of films.
Now - I would like to modify this query to return only the films where the director is George Lucas, and for the life of me - I can't figure out how to do that.
I've tried using the where and filter expressions, and also change the second line to films: (director: "George Lucas") but keep getting error messages.
What's the correct syntax for doing that?
Thanks!
If you check the docs of the provided GraphQL schema, you'll see that this is not possible. Following is the definition of the allFilms field:
allFilms(
after: String
first: Int
before: String
last: Int
): FilmsConnection
As per the doc, it has 4 input arguments, which are after, first, before, and last. There is no way to filter this out using the director's name.
GraphQL is not SQL. You cannot use expressions like WHERE or FILTER in GraphQL. The schema is already defined and the filters are pre-defined too. If the schema does not allow you to filter values using a certain field, you just can't do it.
You can to see the graphql schema here https://github.com/graphql/swapi-graphql/blob/master/schema.graphql
The allFilms query does not contain a filter for the field director. Also i can't find other query with this filter.
Most likely you need to write a filter on the result of the query.
Good Morning.
I'm starting to learn some mongo right now.
I'm facing this problem right now, and i'm start to think if this is the best approach to resolve this "task", or if is bettert to turn around and write another way to solve this "problem".
My goal is to iterate a simple map of values (key) and vector\array (values)
My test map will be recived by a rest layer.
{
"1":["1","2","3"]
}
now after some logic, i need to use the Dao in order to look into db.
The Key will be "realm", the value inside vector are "castle".
Every Realm have some castle and every castle have some "rules".
I need to find every rules for each avaible combination of realm-castle.
AccessLevel is a pojo labeled by #Document annotation and it will have various params, such as castle and realm (both simple int)
So the idea will be to iterate a map and write a long query for every combination of key-value.
public AccessLevel searchAccessLevel(Map<String,Integer[]> request){
Query q = new Query();
Criteria c = new Criteria();
request.forEach((k,v)-> {
for (int i: Arrays.asList(v)
) {
q.addCriteria(c.andOperator(
Criteria.where("realm").is(k),
Criteria.where("castle").is(v))
);
}
});
List<AccessLevel> response=db.find(q,AccessLevel.class);
for (AccessLevel x: response
) {
System.out.println(x.toString());
}
As you can see i'm facing an error concerning $and.
Due to limitations of the org.bson.Document, you can't add a second '$and' expression specified as [...]
it seems mongo can't handle various $and, something i'm pretty used to abuse over sql
select * from a where id =1 and id=2 and id=3 and id=4
(not the best, sincei can use IN(), but sql allow me)
So, the point is: mongo can actualy work in this way and i need to dig more into the problem, or i need to do another approach, like using criterion.in(), and make N interrogation via mongotemplate one for every key in my Map?
in my app there are many entities which get exposed by GraphQL. All that entities get Resolvers and those have many methods (I think they are called "fields" in GraphQl). Since there is only one Query type allowed, I get an "endless" list of fields which belong to many different contexts, i.E.:
query {
newsRss (...)
newsCurrent (...)
userById(...)
weatherCurrent (...)
weatherForecast(...)
# ... many more
}
As you can see, there are still 3 different contexts here: news, users and weather. Now I can go on and prefix all fields ([contextName]FieldName), as I did in the example, but the list gets longer and longer.
Is there a way to "group" some of them together, if they relate to the same context? Like so, in case of the weather context:
query {
weather {
current(...)
forecast(...)
}
}
Thanks in advance!
If you want to group them together , you need to have a type which contain all fields under the same context . Take weather as an example , you need to have a type which contain currentWeather and forecastWeather field. Does this concept make sense to your application such that you can name it easily and users will not feel strange about it ? If yes , you can change the schema to achieve your purpose.
On the other hand, if all fields of the same context actually return the same type but they just filtering different things, you can consider to define arguments in the root query field to specify the condition that you want to filter , something like :
query {
weather(type:CURRENT){}
}
and
query {
weather(type:FORECAST){}
}
to query the current weather and forecast weather respectively.
So it is a question about how you design the schema.
I have gone through the docs and also Googled. I see little mention of returning multiple queries on the same sheet from Maat's Laravel Excel. I presume therefore it is 1 query for 1 downloaded spreadsheet. I also presume that if you do have multiple queries that you will need to place each query on an additional sheet.
Have got this right ?
Many thanks
In a perfect world, every query would get its own sheet. But in reality, it will export whatever you give it so long as it receives a single array or collection for the output, depending on your configuration. It would be up to you to determine how to combine your queries into a format that could be interpreted as rows and columns.
Basic example with two queries:
class ExportSample implements FromCollection
{
// ...
public function collection()
{
// query 1
$a = User::where('id',2)->get();
// query 2
$b = User::where('id',4)->get();
// merge collections
return $a->merge($b);
}
}
Of course, if your queries result in different column structures, there may be additional obstacles.
I am performing an Elasticsearch query using the high-level-rest-api for Java and expect to see records that are either active or do not have a reference id. I'm querying by name for the records and if I hit the index directly with /_search?q=, I see the results I want.
Is my logic correct (pseudo-code):
postFilters.MUST {
Should {
MustNotExist {referenceId}
Must {status = Active}
}
Should {
MustNotExist {referenceId}
Must {type = Person}
}
}
What I get are records that are active with a reference id. But, I want to include records that also do not have a referenceId, hence why I have MustNotExist {referenceId}.
For simplicity, the second Should clause can be dropped (for testing) as the first one is not working as expected by itself.
In my case, I had to use a match query instead of a term query because the value I was querying for was not a primitive or a String. For example, the part where Must, type = Person, Person was an enum, and so looking for "Person" was not quite right, whereas match allowed it to "match".