Shell script - Log file not updating - bash

Question

I'm trying to get my shell script to alert me if the 2 log files is not updating. I am trying to get the current size... wait 10 seconds and if the file did not change size send an email alert. any help would be great!
My Code:
#! /bin/bash
logFiles="lg.log lg2.log"
logLocation="/user/file/logs"
sleepTime=10
subject="issue - file not updated"
failMessage="::no recent updates "
successMessage="OK"
not_updated_time=0
arr=($logFiles)
arrlen=${#arr[#]}
arrcount=()
date
for ((count=0; count<arrlen; count++)) ; do
arrcount[$count]=`ls -l $logLocation${arr[$count]} |awk '{print $5}'`
echo "${arr[$count]} Original size :: ${arrcount[$count]}"
done
echo
while [ "e" == "e" ] ; do
sleep $sleepTime
date
for ((count=0; count<arrlen; count++)) ; do
nc=`ls -l $logLocation${arr[$count]} |awk '{print $5}'`
echo -n "${arr[$count]} "
if [ $nc == ${arrcount[$count]} ] ; then
echo 'error' | mailx -s "issue" cat#gmail.com
else
arrcount[$count]=$nc
echo $successMessage
not_updated_time=0
fi
done
echo
done
Fixed the issue with comma, script still not working. any ideas?

Answer 1

There appears to be a / missing either on the initialization of logLocation or when you're using that variable as $logLocation${arr[$count]}.
Try one of these two changes:
logLocation="/user/file/logs/"
Or:
`ls -l $logLocation/${arr[$count]} |awk '{print $5}'`