get container's name from shared directory - bash

Question

Currently I am running docker with more than 15 containers with various apps. I am exactly at the point that I am getting sick and tired of looking into my docs every time the command I used to create the container. Trying to create scripts and alias commands to get this procedure easier I encountered this problem:
Is there a way to get the container's name from the host's shared folder?
For example, I have a directory "MyApp" and inside this I start a container with a shared folder "shared". It would be perfect if:
a. I had a global script somewhere and an alias command set respectively and
b. I could just run something like "startit"/"stopit"/"rmit" from any of my "OneOfMyApps" directory and its subdirectories. I would like to skip docker ps-> Cp -> etc etc every time, and just get the container's name from the script. Any ideas?

Answer 1

Well, one solution would be to use environment variables to pass the name into the container and use some pre-determined file in the volume to store the name. So, you would create the container with -e flag
docker create --name myapp -e NAME=myapp myappimage
And inside the image entry point script you would have something like
cd /shared/volume
echo $NAME >> .containers
And in your shell script you would do something like
function stopit() {
for name in `cat .containers`; do
docker stop $name;
done;
}
But this is a bit fragile. If you are going to script the commands anyway, I would suggest using docker ps to get a list of containers and then using docker inspect to find which ones use this particular shared volume. You can do all of it inside the script, so what is the problem.