Oracle SQL Merge Multiple rows With Same ID But Out of Order Identifiers - oracle

Question

I am trying to create a distinct list of parts to do analysis on in a table. The table contains a column of Part IDs and a column of Identifiers. The Identifiers are separated within the same entry by pipes but unfortunately the Identifiers are out of order. I'm not sure if this is possible but any help would be greatly appreciated!
For example (currently Both ID and Identifiers are VARCHAR2)
ID Identifiers
1 |1|2|
1 |2|1|
2 |3|A|1|B|
2 |B|1|3|A|
3 |1|3|2|
3 |1|5|
3 |2|1|3|
4 |AA|BB|1|3A|
4 |1|3A|AA|BB|
and I need the query to return
ID Identifiers
1 |1|2|
2 |3|A|1|B|
3 |1|5|
3 |1|3|2|
4 |1|AA|BB|3A|
It does not matter what specific order the identifiers are ordered in as long as all contents within that identifier are the same. For example, |1|5| or |5|1| doesn't matter but I need to see both entries |1|5| and |1|3|2. My original thought was to create separate out the identifiers into separate columns and then alphabetically concatenate back into one column but i'm not sure...thanks in advance!

Answer 1

Something like this (assuming there are no duplicate rows in the input table - if there are, the solution needs to be modified a bit).
In the solution I build the test_table for testing (it is not part of the solution), and I build another factored subquery in the WITH clause. This works in Oracle 11 and above. For earlier versions of Oracle, the subquery defined as prep needs to be moved as a subquery within the final query instead.
with
test_table ( id, identifiers ) as (
select '1', '|1|2|' from dual union all
select '1', '|2|1|' from dual union all
select '2', '|3|A|1|B|' from dual union all
select '2', '|B|1|3|A|' from dual union all
select '3', '|1|3|2|' from dual union all
select '3', '|1|5|' from dual union all
select '3', '|2|1|3|' from dual union all
select '4', '|AA|BB|1|3A|' from dual union all
select '4', '|1|3A|AA|BB|' from dual
),
prep ( id, identifiers, token ) as (
select id, identifiers, regexp_substr(identifiers, '[^|]+', 1, level)
from test_table
connect by level <= regexp_count(identifiers, '\|') - 1
and prior identifiers = identifiers
and prior sys_guid() is not null
)
select distinct id,
'|' || listagg(token, '|') within group (order by token) || '|'
as identifiers
from prep
group by id, identifiers
order by id, identifiers -- ORDER BY is optional
;
Output:
ID IDENTIFIERS
--- --------------------
1 |1|2|
2 |1|3|A|B|
3 |1|2|3|
3 |1|5|
4 |1|3A|AA|BB|
5 rows selected.