I found the following mixin on the web, but have forgotten where I found it.
#mixin linear-gradient($direction, $gradients...) {
background-color: nth($gradients, 1);
background-image: linear-gradient($direction, $gradients...);
}
and then be called upon in a class with:
.selector {
#include linear-gradient(to right, magenta, red, orange, yellow, green, blue, purple);
}
This works fine, my question is about the background-color: nth($gradients, 1);is this a index that starts with 1 and is it used as a color-start?
Can someone explain?
Thanks :)
Yes,nth(gradients,1) picks the first element from the gradients list
so it would background-color:magenta here
for more explanation this
As you suspected, nth($gradients, 1) picks the first item from $gradients as Sass lists are 1-indexed.
In this case background-color is set to the first colour from gradients. You can think of this as a fallback in case the user's browser doesn't support linear-gradients.
Related
I have two separate SASS files among many, on a ReactJS repository, such as _main.sass and _partials.sass. They are combined using #use on a separate file named index.css.
The SASS package as a dependency is just sass via npm.
_main.sass and all of its variables can be accessed by _partials.sass, thanks to #use "./main" as *.
I have the following code on _main.sass which detects OS preference for dark mode:
#media (prefers-color-scheme: light)
body
background-color: $white
color: $black
#media (prefers-color-scheme: dark)
body
background-color: $dark
color: $light
All of these color variables are defined and they're working well.
But the problem is that I need to use complement() function on the background-color which is currently active, in _partials.sass.
The main issue seems to me that when I assign a variable e.g. $accent on both ends of the media queries, the variable does not get picked up by the remote file. I could not wrap my head around to do it in such way, since I'm only a beginner at coding SASS.
Unfortunately, I need the plain CSS #media query implementations for automatically detecting the preference. But any suggestion is appreciated in case it is impossible to keep it like that and achieve what I wanted.
Thank you!
I've found the solution myself.
So, I was trying to make a light/dark theme compliant SASS implementation.
What complement function does is that it rotates the color in the input for 180deg on the RGB hue. I needed this to get corresponding inverted-like colors for each color, for better dark-mode contrast. The difference between invert and complement are listed here.
But, I realized that I did not need that. Here is the code for my theme implementation using SASS.
// rainbow
$blue: #00a4ef
$yellow: #f4b400
$red: #db4437
$green: #61b500
$purple: #6e14ef
$pink: #ff0090
$carmine: #c6004b
// monochroma
$white: #fff
$light: #f5f5f5
$lgray: #c2c2c2
$dgray: #6e6e6e
$ldark: #363636
$dark: #232323
$black: #000
$themes: (light: (logo: url("../static/logo-light.svg"), bg: $white, card-bg: $light, text: $black, link: $red, hover: $pink, active: $carmine, border: $lgray, button: $yellow), dark: (logo: url("../static/logo-dark.svg"), bg: $dark, card-bg: $ldark, text: $light, link: $red, hover: $pink, active: $carmine, border: $dgray, button: $purple))
#mixin themeProperty($theme, $property, $color, $additionalProperties)
#if $additionalProperties
#{$property}: unquote(map-get($theme, $color) + " " + $additionalProperties)
#else
#{$property}: unquote(map-get($theme, $color))
#mixin theme($property, $color, $additionalProperties: "")
$light: map-get($themes, light)
$dark: map-get($themes, dark)
#media (prefers-color-scheme: light)
#include themeProperty($light, $property, $color, $additionalProperties)
#media (prefers-color-scheme: dark)
#include themeProperty($dark, $property, $color, $additionalProperties)
There is a color map named "themes" which lists each color for light and dark themes for different use cases.
Furthermore, the mixins match the exact color for exact usage for the desired theme mode, whichever is being used by the client-side (browser or OS), thanks to #media queries.
For example, if you'd like to color a background-color using the button preset on the theme mapping, the usage is as follows:
#include theme("background-color", button)
I need to output this:
#footer-widgets .container .row {
background-image: url("RANDOMLY PICKED");
background-position: right bottom;
background-repeat: no-repeat;
}
... and there should be a list with 4 or 5 links to the actual background-images (http://domain.com/blablabla/image.png) to pick from. How can I do this with SASS?
The most recent version of Sass (v3.3.0) adds a new random function. If you mix that with a list of images (and a wee bit of variable interpolation), you will have CSS with a randomly selected background image every time Sass is compiled. Example:
$imgKey: random(5);
$list: apple, banana, cherry, durian, eggplant;
$nth: nth($list, $imgKey);
body {
background-image: "/images/#{$nth}.jpg";
}
Live example: http://sassmeister.com/gist/8966210
As above, the random value will only change when the Sass is compiled, which won't necessarily be every time your page is visited.
When creating a color scheme in SASS what's the conventional variable names for defining colors?
I know using color names are bad. Such as:
$blue
$red
$green
But I've not seen an alternative. I'm struggling for variable names for colors on the site that convey meaning.
Any ideas?
I found another idea in "SASS & Color Variables" article. The solution suggested by Sacha Greif is to use some variables to store descriptive color names, and some other to assign those colors to their functions:
// first we set descriptive variables:
$darkgrey: #333333;
$blue: #001eff;
// then we set functional variables:
$text_color: $darkgrey;
$link_color: $lightblue;
$border_color: $lightblue;
.myClass {
color: $text_color;
border-color: $border_color;
}
a {
color: $link_color;
}
I'm just beginning with SASS and don't know which approach is more practical, but I like the way it separates colors from their function.
In my personal experience the most useful way to name colors is to do it in regards of the color's function, such as
$background
$contrast
$text
$aside
$link
And so on. Of course which colors and name may depend on the design.
Then you may have different and exchangeable color schemes defined on different styles, such as:
_dark_scheme.scss
_light_scheme.scss
_pastels.scss
The idea here, is that you can use the same color variables in your main stylesheets, and do not depend on specific colors.
I like the idea of combining generic to specific naming (good for code completion) and description/functional naming. So you have something like this:
// Descriptive naming
$color-gray-light: #f3f3f3;
$color-gray-dark: #999999;
$color-red: red;
// Functional naming
$link-color: $color-red;
$link-border-color: $color-gray-light;
You can even create a mixin for greys (in the example RGBA is used for transparency, for example black on a red background would be more visible if it is 80% transparent black rather than dark grey).
#mixin grey($intensity: 0.5, $type: color) {
#{$type}: rgba(black, $intensity);
}
.i-am-50-percent-gray {
#include grey(0.5, color);
}
Give the result
.i-am-50-percent-gray {
color: rgba(0, 0, 0, 0.5);
}
Does anyone have any examples of input validation changing the input border color to red?
Thanks.
Erik
It's best to keep as much of the styling as you can in the style-sheets. Defined a
input.invalid {
border: solid red 1px;
}
and use .addClass("invalid") on your elements
hey guys,
somehow i can't find the solution for my little problem.
i have a paragraph setting with a max-width of 630px.
in some cases i have images within one of those paragraphs - and in this case i want the image to act normal -> without any max-width setting.
.post-body p {
width:99%;
max-width: 630px;
}
.post-body p img{
max-width:100% !important;
}
is it even possible to have the image larger than the max-width setting that's set to it's parent? do i need to use javascript (jquery)?
thank you for your help.
Unless you're modifying the image width some other way, as long as you don't do anything to the image it will display at full size.
See here: http://jsfiddle.net/WrfQQ/
I didn't bother declaring any CSS for the image, so it, by default, will show up at full size. (Please note, for the sake of testing I decreased the width of the p to 100px)
As I can see the problem is that you put a MAX-width to the img... you have to code the relative width... so:
.post-body p img{
position: relative;
width: 100%;
}
if you want it in jQuery the code is the below:
$('.post-body p img').width() == $('.post-body p').width();