Print and assign array values to another variable in batch file - windows

I face some problem while trying to print array values as shown below:
#echo off
setlocal EnableDelayedExpansion
set args=
set /A argc=0
SET /A argn=0
for %%a in (%*) do (
SET args[!argn!]=%%a
SET /A argn+=1
)
FOR %%q in (%*) DO (
echo !args[%argc%]! //not able to print the value
call echo %%args[!argc!]%% // this worked
if "%%q" == "--snap" (
set /A argc+=1
set SNAP=!args[%argc%]! //this didn't work
)
if "%%q" == "--source" (
set /A argc+=1
call SET "SOURCE=%%args[!argc!]%%" //this didn't work too
)
set /A argc+=1
)
Using this segment of code prints only the first value of the array but the other method of using for /l works fine.
How do i correct this?
Is it possible to store this array value in any other variable? If so, how?

You are trying to echo a variable you haven't set, it will therefore be blank.
#Echo Off
SetLocal EnableDelayedExpansion
Set argc=0
For %%q In (%*) Do (
Set "args[!argc!]=%%q"
Rem The next line is for information only
Call Echo=%%args[!argc!]%%
Set/A argc+=1
)
Rem take a look at the variables
Set args[
Timeout -1

Assuming delayedexpansion has been invoked and argn has been set to #args+1 as reported in comments,
set /a argn-=1
for /L %%q in (0,1,%argn%) do echo !args[%%q]!
set /a argn+=1
would be my preference.

Related

Why is the array filled with "m"

I'm fairly new to batch and I've been trying to write some simple sorting programs. This program uses the most basic sorting system, and the code(from what I can see) seems to be error-free. Yet when I run it, a random list is generated, and it seems as if some sorting is going on, then the array is filled with the letter "m". I don't see why this is occurring, so if somebody could point me in the correct direction I would greatly appreciate it.
My code:
#echo off
color b
title sorting
set ar=0
set num=0
set check=0
set checknum=0
set totalnumber=500
set randmax=5000
:array
if %num% LSS %totalnumber% (
set /A a[%num%]=%random% %% %randmax%
set /A num=%num%+1
goto array
)
if %num% EQU %totalnumber% (
goto echo1
)
:echo1
for /F "tokens=2 delims==" %%s in ('set a[') do echo %%s
echo sort initialized
goto sort
)
:sort
set n=0
:sortloop
set /A m=%n%+1
if %n% EQU %totalnumber% (
goto check
)
if %a[%n%]% GTR %a[%m%]% (
set hold=%a[%m%]%
set a[%m%]=%a[%n%]%
set a[%n%]=%hold%
set /A n=%n%+1
goto sortloop
)
if %a[%n%]% LSS %a[%m%]% (
echo a[%n%] check
set /A n=%n%+1
goto sortloop
)
:check
set check=0
set checknum=0
:checkloop
set /A checknumplus=%checknum%+1
if %check% EQU %totalnumber% (
goto complete
)
if %checknum% EQU %totalnumber% (
set n=0
goto sort
)
if %a[%checknum%]% LSS %a[%checknumplus%]% (
set /A check=%check%+1
set /A checknum=%checknum%+1
goto checkloop
)
:complete
for /F "tokens=2 delims==" %%s in ('set a[') do echo %%s
for /F "tokens=2 delims==" %%s in ('set a[') do echo %%s > sortedlist.txt
When you need to use variables inside of variables in batch (most commonly when working with arrays), you need to use delayed expansion.
Right now, your code says set hold=%a[%m%]%. The interpreter is treating this value as the variable %a[% (which doesn't exist, so it using nothing), the literal character m, and the variable %]% (which also doesn't exist and is therefore empty).
To get around this, put setlocal enabledelayedexpansion at the top of your code and then change your set statement to set hold=!a[%m%]! (and do the same thing with the other lines that are using it).

Windows Batch File can't use variable in for syntax

I want to use a variable skip parameter in for loop, but it won't let me do it.
Here is my code
#echo off
setlocal ENABLEDELAYEDEXPANSION
set /p testcase=<testcases.txt
set /a end=%testcase%*13
for /L %%P IN (1,13,%end%) DO (
set skip=skip=%%P
echo !skip!
set vidx=0
for /f "%skip%" %%A in (testcases.txt) do (
set /a vidx=!vidx! + 1
set var!vidx!=%%A
)
)
Here skip is skip=1, but it doesn't skip any line. When I replace it with skip=1. then it works fine, but I want to skip variable no. of lines in each iteration. Please help.
I think with this logic the only option is a subroutine:
#echo off
setlocal ENABLEDELAYEDEXPANSION
set /p testcase=<testcases.txt
set /a end=%testcase%*13
for /L %%P IN (1,13,%end%) DO (
set skip=skip=%%P
echo !skip!
set vidx=0
call :innerFor %%P
)
exit /b 0
:innerFor
for /f "skip=%~1" %%A in (testcases.txt) do (
set /a vidx=!vidx! + 1
set var!vidx!=%%A
)
exit /b 0
parametrization of FOR /F options is a little bit tricky..
Though I have no the content of your files I cant test if this works correctly .

Windows Batch: Split String to individual characters to variables

in Windows Batch, if I had a variable (length can change) that was, for example: "hello world!"
is it possible to "split" the variable so each character is its own variable so the output could look like:
t1=h
t2=e
t3=l
etc.
Any help would be appreciated.
Use this code:
setlocal EnableDelayedExpansion
set str="hello world^!"
set tempstr=%str%
set count=0
:loop
if defined tempstr (
set tempstr=%tempstr:~1%
set /a count+=1
set /a pos=%count%-1
set t!count!=!str:~%pos%,1!
goto loop
)
:: check the generated variables
set t
To get the nth character in a string, use set char=%str:~n,1%.
I hope this was helpful!
Here is a variant using for /L to iterate over all characters of the string. The number of characters, so the length of the string, is retrieved in sub-routine :LENGTH first:
#echo off
setlocal EnableExtensions DisableDelayedExpansion
rem // Define constants here:
set "_STRING=Hello world!"
call :LENGTH LEN "%_STRING%"
setlocal EnableDelayedExpansion
for /L %%I in (0,1,%LEN%) do (
set "$CHR[%%I]=!_STRING:~%%I,1!"
)
set $CHR
endlocal
endlocal
exit /B
:LENGTH rtn_length val_string
setlocal DisableDelayedExpansion
set /A "RET=0" & set "STR=%~2"
if defined STR set /A "RET=1"
setlocal EnableDelayedExpansion
for %%L in (4096 2048 1024 512 256 128 64 32 16 8 4 2 1) do (
if not "!STR:~%%L,1!"=="" (
set /A "RET+=%%L"
set "STR=!STR:~%%L!"
)
)
(
endlocal
endlocal
set "%~1=%RET%"
)
exit /B
Here is a different variant, using cmd /U to convert the string into Unicode, where a null-byte becomers inserted behind every character, and find, which treats these null-bytes like end-of-line markers:
#echo off
setlocal EnableExtensions DisableDelayedExpansion
rem // Define constants here:
set "_STRING=Hello world!"
set /A "IDX=0"
for /F delims^=^ eol^= %%I in ('
cmd /U /V /C echo^(!_STRING!^| find /V ""
') do (
set "CHR=%%I"
setlocal EnableDelayedExpansion
for /F "delims=" %%J in ("$CHR[!IDX!]=!CHR!") do (
endlocal
set "%%J"
)
set /A "IDX+=1"
)
set $CHR
endlocal
exit /B
Finally, here is another variant, based on a goto loop. This uses a position pointer POS to scan the string and to extract a single character. If no character is returned, the end of the string is reached:
#echo off
setlocal EnableExtensions DisableDelayedExpansion
rem // Define constants here:
set "_STRING=Hello world!"
setlocal EnableDelayedExpansion
if not defined _STRING goto :QUIT
set /A "POS=0"
:LOOP
set "CHR=!_STRING:~%POS%,1!"
if defined CHR (
set "$CHR[%POS%]=!CHR!"
set /A "POS+=1"
goto :LOOP
)
:QUIT
set $CHR
endlocal
endlocal
exit /B
Old thread, but accepted answer misses letter d?
Changed
set /a pos=%count%-1 to
set /a pos=!count!-1
setlocal EnableDelayedExpansion
set str="hello world!"
set tempstr=%str%
set count=0
:loop
if defined tempstr (
set tempstr=%tempstr:~1%
set /a count+=1
set /a pos=!count!-1
set t!count!=!str:~%pos%,1!
goto loop
)
:: check the generated variables
set t
pause
Here is another version.
variables start with 0, though
setlocal EnableDelayedExpansion
set var="hello world!"
rem remove quotes
set var=%var:"=%
rem add limiter
set var=%var%_
echo %var%
set count=0
:loop
set tempvar=!var:~%count%,1!
if !tempvar!==_ goto skip
set arr!count!=!tempvar!
set /a count=!count!+1
goto loop
:skip
echo out
echo display output
set arr
pause

Reading from a csv file and extracting certain data columns based on first column value

This is my first batch program and I have been searching online but still struggling to write up a solution.
I have the following CSV file:
"RH",2013/06/15 02:14:58 -0400,"X","LQ3SUEEWPWKL6",005,
"FH",01
"SH",2013/06/14 00:00:00 -0400,2013/06/14 23:59:59 -0400,"LQ3SUEEWPWKL6",""
"CH","TransactionID","InvoiceID",
......
I'm trying to write a simple program to do the following:
If column1 = "RH", then extract column2 value (2013/06/15 02:14:58 -0400)
If column1 = "SH", then extract column4 value (LQ3SUEEWPWKL6)
and pipe output to a file.
This is my code so far but the if condition is not working for me
#echo off
:: Set input file in variable
::Set _InputFile=%1
:: Store input line into different variables
FOR /F "tokens=1-18* delims=," %%A IN (%_InputFile%) DO (
Set _var1=%%A
Set _var2=%%B
Set _var3=%%C
Set _var4=%%D
Set _var5=%%E
Set _var6=%%F
Set _var7=%%G
Set _var8=%%H
Set _var9=%%I
Set _var10=%%J
Set _var11=%%K
Set _var12=%%L
Set _var13=%%M
Set _var14=%%N
Set _var15=%%O
Set _var16=%%P
Set _var17=%%Q
Set _var18=%%R
IF "%_var1%"=="RH" echo %var2%
)
My CSV file looks fine in Excel and Notepad but when I execute the script to display the first variable, it looks like there's some garbage characters just before the "RH" on the first record - I cannot bypass it since I need to extract additional column data if var1 = "RH":
"RH"
FH
01
SH
CH
TransactionID,PaymentTrackingID,
SF
SF
SC
RF
CAD,CR,0
RF
USD,CR,0
RC
FF
(
FOR /F "tokens=1-18* delims=," %%A IN (%_InputFile%) DO (
if "%%~A"=="RH" echo %%~B
if "%%~A"=="SH" echo %%~D
)
)>youroutputfilename
Should work - no need to assign all the values to different variables - BUT if you plan to use them, then
FOR /F "tokens=1-18* delims=," %%A IN (%_InputFile%) DO (
...
Set _var17=%%Q
Set _var18=%%R
CALL :PROCESS
)
...
GOTO :EOF
:PROCESS
IF %_var1%=="RH" echo %_var2%
IF %_var1%=="SH" echo %_var4%
GOTO :EOF
Note that with this method, since you are assigning %%x to _varx then if %%x is quoted, the quotes will be INCLUDED in the value assigned. To remove the enclosing quotes (if they exist) use SET _varx=%%~x.
Addendum 20130703-1956Z for OP's problem
#ECHO OFF
SETLOCAL
SET _Inputfile=u:\noname1.txt
(
FOR /F "tokens=1-18* delims=," %%A IN (%_InputFile%) DO (
SET "RH="
SET "SH="
ECHO(%%A|FINDSTR /l /c:"\"RH\"" >NUL
IF NOT ERRORLEVEL 1 SET RH=Y
ECHO(%%A|FINDSTR /l /c:"\"SH\"" >NUL
IF NOT ERRORLEVEL 1 SET SH=Y
if DEFINED RH echo %%~B
if DEFINED SH echo %%~D
)
)>u:\youroutputfilename
TYPE u:\youroutputfilename
del u:\youroutputfilename
echo========First way
(
FOR /F "tokens=1-18* delims=," %%A IN (%_InputFile%) DO (
SET _var1=%%A
SET "RH="
SET "SH="
CALL :process
if DEFINED RH echo %%~B
if DEFINED SH echo %%~D
)
)>u:\youroutputfilename
TYPE u:\youroutputfilename
del u:\youroutputfilename
echo========Second way
SETLOCAL ENABLEDELAYEDEXPANSION
(
FOR /F "tokens=1-18* delims=," %%A IN (%_InputFile%) DO (
SET _var1=%%A
IF "!_var1:~-4!"==""RH"" echo %%~B
IF "!_var1:~-4!"==""SH"" echo %%~D
)
)>u:\youroutputfilename
TYPE u:\youroutputfilename
del u:\youroutputfilename
echo========Third way
ENDLOCAL
GOTO :EOF
:process
IF "%_var1:~-4%"==""RH"" SET RH=Y
IF "%_var1:~-4%"==""SH"" SET SH=Y
GOTO :EOF
You have a parsing issue. First end the for loop with ), after this you can use the new variables:
#echo off
:: Set input file in variable
::Set _InputFile=%1
:: Store input line into different variables
FOR /F "tokens=1-18* delims=," %%A IN (%_InputFile%) DO (
Set "_var1=%%A"
Set "_var2=%%B"
Set "_var3=%%C"
Set "_var4=%%D"
Set "_var5=%%E"
Set "_var6=%%F"
Set "_var7=%%G"
Set "_var8=%%H"
Set "_var9=%%I"
Set "_var10=%%J"
Set "_var11=%%K"
Set "_var12=%%L"
Set "_var13=%%M"
Set "_var14=%%N"
Set "_var15=%%O"
Set "_var16=%%P"
Set "_var17=%%Q"
Set "_var18=%%R"
)
IF "%_var1%"=="RH" echo %var2%
You need to enable delayed expansion:
#echo off
setlocal EnableDelayedExpansion
set "_InputFile=..."
for /f "tokens=1-18* delims=," %%A in (%_InputFile%) do (
Set _var1=%%A
Set _var2=%%B
...
if "!_var1!"=="RH" echo !_var2!
)
as there was no answer to the "why does my line starts with "RH"", I'll do some gravedigging.
So, the  comes from the BOM (Byte Order Mark) which indicates the file is in UTF, and the way the bytes are written if necessary.
for the answer:
you can use
if x%_var1:RH=%x NEQ x%_var1%x (echo %_var2%)
this will check if RH is in %_var1% (if after replacing RH in the var, it is unchanged, RH is not in the var)
which means, whether the Bom is here or not is not important. Though, you'll have problems if you want an exact match.
another way to deal with it is to not include the bom in your file, which means saving either in ASCII or UTF-8 without BOM; Or using a tool to strip the bom from your UTF-8 file.

How to get the value from a dynamic variable in windows batch file

I am using Microsoft Windows XP [Version 5.1.2600]
Trying to do this.
Trying to create the variable dynamically and then read the value out of that variable in a loop.
#ECHO off
SET SQL1=TEST
SET SQL2=TEST1
SET SQL3=TEST2
SET SQL=SQL
SETLOCAL ENABLEDELAYEDEXPANSION
SET /A number=0
FOR /l %%A IN (1,1,3) DO (
SET /A number = number + 1
echo !number!
echo %SQL%!number!
)
endlocal
Output should be
1
test
2
test2
3
test3
I am getting
C:\temp>c.bat
1
SQL1
2
SQL2
3
SQL3
Please help!
Ugh.
First way (note that instead of your number variable, it uses the loop counter variable %%A):
#ECHO off
SET SQL1=TEST
SET SQL2=TEST1
SET SQL3=TEST2
SETLOCAL ENABLEDELAYEDEXPANSION
SET /A number=0
FOR /l %%A IN (1,1,3) DO (
SET /A number = number + 1
echo !number!
echo !SQL%%A!
)
endlocal
Second way (ugly but it does what you want):
#ECHO off
SET SQL1=TEST
SET SQL2=TEST1
SET SQL3=TEST2
SETLOCAL ENABLEDELAYEDEXPANSION
SET /A number=0
FOR /l %%A IN (1,1,3) DO (
SET /A number = number + 1
echo !number!
for %%i in (!number!) do (echo !SQL%%i!)
)
endlocal

Resources