I want to write a Shell Script.
The task is, that I have to pick a random number.
But the numbers must be one of the following three.
5,10,15
So if "let's say" 'a' is smaller than 5, I have to pick randomly a number of 5,10 or 15.
How can I do that?
Here's a hint to help you do this.
First, create a variable (array) containing your 3 values : arr = (5 10 15).
Then, create a random number called index and floor it to 2.
Finally, retrieve the number ${arr[$index]}.
Try the following
#!/bin/bash
arr=(5 10 15);
picked_element=${arr[$(($RANDOM % 3))]};
echo $picked_element;
Related
I want to simulate dice roll functionality. However, I don't get what I expect. I want to get a Dice with value ranging from 1 to 6 inclusively (dice).
I tried to find it in Eiffel Documentation, but it is very hard to do.
The following code prints values for 10 consecutive rolls:
local
r: RANDOM
do
across
1 |..| 10 as i
from
create r.set_seed (...) -- ... is the initial "seed"
r.start
loop
io.put_integer (r.item \\ 6 + 1)
io.put_new_line
r.forth
end
end
so this is what I'm trying to do, and I'm not sure how cause I'm new to python. I've searched for a few options and I'm not sure why this doesn't work.
So I have 6 different nodes, in maya, called aiSwitch. I need to generate random different numbers from 0 to 6 and input that value in the aiSiwtch*.index.
In short the result should be
aiSwitch1.index = (random number from 0 to 5)
aiSwitch2.index = (another random number from 0 to 5 different than the one before)
And so on unil aiSwitch6.index
I tried the following:
import maya.cmds as mc
import random
allswtich = mc.ls('aiSwitch*')
for i in allswitch:
print i
S = range(0,6)
print S
shuffle = random.sample(S, len(S))
print shuffle
for w in shuffle:
print w
mc.setAttr(i + '.index', w)
This is the result I get from the prints:
aiSwitch1 <-- from print i
[0,1,2,3,4,5] <--- from print S
[2,3,5,4,0,1] <--- from print Shuffle (random.sample results)
2
3
5
4
0
1 <--- from print w, every separated item in the random.sample list.
Now, this happens for every aiSwitch, cause it's in a loop of course. And the random numbers are always a different list cause it happens every time the loop runs.
So where is the problem then?
aiSwitch1.index = 1
And all the other aiSwitch*.index always take only the last item in the list but the time I get to do the setAttr. It seems to be that w is retaining the last value of the for loop. I don't quite understand how to
Get a random value from 0 to 5
Input that value in aiSwitch1.index
Get another random value from 0 to 6 different to the one before
Input that value in aiSwitch2.index
Repeat until aiSwitch5.index.
I did get it to work with the following form:
allSwitch = mc.ls('aiSwitch')
for i in allSwitch:
mc.setAttr(i + '.index', random.uniform(0,5))
This gave a random number from 0 to 5 to all aiSwitch*.index, but some of them repeat. I think this works cause the value is being generated every time the loop runs, hence setting the attribute with a random number. But the numbers repeat and I was trying to avoid that. I also tried a shuffle but failed to get any values from it.
My main mistake seems to be that I'm generating a list and sampling it, but I'm failing to assign every different item from that list to different aiSwitch*.index nodes. And I'm running out of ideas for this.
Any clues would be greatly appreciated.
Thanks.
Jonathan.
Here is a somewhat Pythonic way: shuffle the list of indices, then iterate over it using zip (which is useful for iterating over structures in parallel, which is what you need to do here):
import random
index = list(range(6))
random.shuffle(index)
allSwitch = mc.ls('aiSwitch*')
for i,j in zip(allSwitch,index):
mc.setAttr(i + '.index', j)
I have a number of files (having 10 columns each) with following order:
file_001.txt, file_002.txt, file_003_txt,
file_021.txt, file_023.txt, file_023.txt,
file_041.txt, file_042.txt, file_043.txt,
file_061.txt, file_062.txt, file_063.txt,
file_081.txt, file_082.txt, file_083.txt,
I would like to plot each file with different line. e.g. using 1:2, using 1:3, using 1:5, using 1:8. I can not able to make a loop to call different columns. My following script is not working for k field
plot for [k=2, 3, 5, 8] for [j=0:8:2] for [i=1:3] 'file_0'.j.i.'.txt' u 1:k;
Use for [k in "2 3 5 8"] if you have a list rather than a range.
If j can be > 9, you should set up a function
fname(j,i) = sprintf("name%02.f%.f",j,i)
to get proper file names.
Format string "%02.f" means float (f), no digits after the comma (.), minimum two postions (2), fill empty space with zeroes.
print fname(2,3)
name023
print fname(13,3)
name133
print fname(113,3)
name1133
These are libc format strings, they are not documented inside the gnuplot docs, but there are many sources in the web.
I'm still new with SPSS, I Have Data For The Following :
Cereals Vegetables Fruit Meat Dairy Fat Sugar Pulses
I Have Also Computed The Variables With This Formula :
Total FCS = (Cereals*2)+(Vegetables)+(Fruits)+(Meat*4)+(Dairy*4)+(Sugar*0.5)+(Pulses*3)
Now I Want To Rank The Data from the Total FCS In One Column In Order To Make Graph From It As Following:
Rank as :
<28 Poor
>28.5 - <42 Borderline
>42.5 Acceptable
What Should I Do ?
I would use a DO IF statement to assign the ranks. Example below.
DO IF FCS < 28.
COMPUTE RankFCS = 1.
ELSE IF FCS <= 42.5.
COMPUTE RankFCS = 2.
ELSE.
COMPUTE RankFCS = 3.
END IF.
VALUE LABELS RankFCS
1 'Poor'
2 'Borderline'
3 'Acceptable'.
There is a command called Recode in SPSS, you can use that command to create this rank variable. Recode command has two options
1). Recode into same variables
2). Recode into Different variables.
I am using 2nd option as you need to create a new Rank variable.
STRING RankFCS (A8).
RECODE FCS (Lowest thru 28='Poor') (28.5 thru 42='Borderline')
(42.5 thru Highest='Acceptable')
INTO RankFCS.
EXECUTE.
I'm attempting to solve http://projecteuler.net/problem=1.
I want to create a method which takes in an integer and then creates an array of all the integers preceding it and the integer itself as values within the array.
Below is what I have so far. Code doesn't work.
def make_array(num)
numbers = Array.new num
count = 1
numbers.each do |number|
numbers << number = count
count = count + 1
end
return numbers
end
make_array(10)
(1..num).to_a is all you need to do in Ruby.
1..num will create a Range object with start at 1 and end at whatever value num is. Range objects have to_a method to blow them up into real Arrays by enumerating each element within the range.
For most purposes, you won't actually need the Array - Range will work fine. That includes iteration (which is what I assume you want, given the problem you're working on).
That said, knowing how to create such an Array "by hand" is valuable learning experience, so you might want to keep working on it a bit. Hint: you want to start with an empty array ([]) instead with Array.new num, then iterate something num.times, and add numbers into the Array. If you already start with an Array of size num, and then push num elements into it, you'll end up with twice num elements. If, as is your case, you're adding elements while you're iterating the array, the loop never exits, because for each element you process, you add another one. It's like chasing a metal ball with the repulsing side of a magnet.
To answer the Euler Question:
(1 ... 1000).to_a.select{|x| x%3==0 || x%5==0}.reduce(:+) # => 233168
Sometimes a one-liner is more readable than more detailed code i think.
Assuming you are learning Ruby by examples on ProjectEuler, i'll explain what the line does:
(1 ... 1000).to_a
will create an array with the numbers one to 999. Euler-Question wants numbers below 1000. Using three dots in a Range will create it without the boundary-value itself.
.select{|x| x%3==0 || x%5==0}
chooses only elements which are divideable by 3 or 5, and therefore multiples of 3 or 5. The other values are discarded. The result of this operation is a new Array with only multiples of 3 or 5.
.reduce(:+)
Finally this operation will sum up all the numbers in the array (or reduce it to) a single number: The sum you need for the solution.
What i want to illustrate: many methods you would write by hand everyday are already integrated in ruby, since it is a language from programmers for programmers. be pragmatic ;)