The below query returns a list of the most popular theatre and rowtype combinations sorted by total amount:
so for example:
NAME ROWTYPE TOTALAMOUNT
theatre1 middle 200
theatre2 front 190
theatre1 front 150
theatre2 middle 100
Whereas what I need is simply the maximum per theatre:
theatre1 middle 200
theatre2 front 190
Query:
SELECT name, rowtype, sum
from ( select
name, rowtype, sum(totalamount) sum from trow, fact, theatre
Where trow.trowid = fact.trowid
AND
theatre.theatreid = fact.theatreid
GROUP BY rowtype, name
)
ORDER BY sum DESC, name, rowtype ;
You can use window functions for this:
select name, rowtype, sum
from (select name, rowtype, sum(totalamount) as sumta,
max(sum(totalamount)) over (partition by name) as maxsumta
from trow join
fact
on trow.trowid = fact.trowid join
theatre
on theatre.theatreid = fact.theatreid
group byrowtype, name
) nr
where sumta = maxsumta;
In addition, you should learn to use proper, explicit JOIN syntax. A simple rule: Never use commas in the FROM clause. Always use proper explicit JOIN syntax.
Put your current query into a common table expression and then use window functions to find the max total amount for each theatre.
WITH cte AS
(
SELECT name, rowtype, SUM(totalamount) sum
FROM trow
INNER JOIN fact
ON trow.trowid = fact.trowid
INNER JOIN theatre
ON theatre.theatreid = fact.theatreid
GROUP BY name, rowtype
)
SELECT name, rowtype, sum
FROM
(
SELECT name,
rowtype,
sum,
MAX(sum) OVER (PARTITION BY name) maxSum
FROM cte
) t
WHERE t.sum = t.maxSum
Related
Output result
I want the running balance in my query. I had wrote the query.
May be i am mistaking any where please let me know.
SELECT
ACC_VMAST.VM_DATE,
ACC_VDET.CHEQUE,
ACC_VMAST.NARRATION,
ACC_VDET.DEBIT,
ACC_VDET.CREDIT,
sum(nvl(ACC_VDET.DEBIT,0) - nvl(ACC_VDET.CREDIT,0) )
over (order by ACC_VMAST.VM_DATE , ACC_VDET.DEBIT ) running_bal
FROM ACC_VMAST,
ACC_VDET,
ACC_COA
WHERE ACC_VMAST.VM_PK=ACC_VDET.VM_PK
AND ACC_COA.COA_PK=ACC_VDET.COA_PK
AND ACC_VMAST.POST_BY IS NOT NULL
AND ACC_VMAST.CANCEL_STATUS IS NULL
AND ACC_VMAST.VM_DATE BETWEEN '07/06/2021' AND '07/07/2021'
AND ACC_VDET.COA_PK= '303'
ORDER BY ACC_VMAST.VM_DATE , ACC_VDET.DEBIT;
If you have rows that have the same values for the ORDER BY clause then when you SUM the values then all the rows with the same ORDER BY value will be grouped together and totalled.
To prevent that, you can add the ROWNUM pseudo-column to the ORDER BY clause of the analytic function so that there will not be any ties:
SELECT m.VM_DATE,
d.CHEQUE,
m.NARRATION,
d.DEBIT,
d.CREDIT,
SUM( COALESCE(d.DEBIT,0) - COALESCE(d.CREDIT,0) )
OVER ( ORDER BY m.VM_DATE, d.DEBIT, ROWNUM ) AS running_bal
FROM ACC_VMAST m
INNER JOIN ACC_VDET d
ON (m.VM_PK = d.VM_PK)
INNER JOIN ACC_COA c
ON (c.COA_PK = d.COA_PK)
WHERE m.POST_BY IS NOT NULL
AND m.CANCEL_STATUS IS NULL
AND m.VM_DATE BETWEEN DATE '2021-07-06' AND DATE '2021-07-07'
AND d.COA_PK = '303'
ORDER BY
m.VM_DATE,
d.DEBIT;
You need to add a row range with "rows between unbounded preceding and current row".
sum(nvl(ACC_VDET.DEBIT,0) - nvl(ACC_VDET.CREDIT,0) )
over (order by ACC_VMAST.VM_DATE , ACC_VDET.DEBIT rows between unbounded preceding and current row ) running_bal
Anyone please help me, how to uniqe each row
SELECT T3.ID_JS,T5.DIVISI_AREA,T4.NAME_METHODE_REPAIR, T1.URUTAN AS SORT, TO_DATE(T1.TIME_FINISHED_WORK,'DD/MM/YYYY') AS DATE_FINISHED
FROM TB_WORK T1
JOIN TB_INSPECTION T2 ON T1.ID_INSPECTION=T2.ID_INSPECTION
JOIN TB_JOBSHEET T3 ON T2.ID_JS = T3.ID_JS
JOIN TB_METHODE_REPAIR T4 ON T1.ID_METHODE_REPAIR=T4.ID_METHODE_REPAIR
JOIN TB_DIVISI T5 ON T1.ID_DIVISI=T5.ID_DIVISI
where t3.id_js=142414
GROUP BY T3.ID_JS,T5.DIVISI_AREA,T4.NAME_METHODE_REPAIR, T1.URUTAN,TO_DATE(T1.TIME_FINISHED_WORK,'DD/MM/YYYY')
ORDER BY T3.ID_JS, TO_DATE(T1.TIME_FINISHED_WORK,'DD/MM/YYYY') desc
[Result] (http://prntscr.com/sfpuuq)
Those rows are unique, so I'll guess: there are two rows with sort = 3 and you'd want to have only one. If that's so, regarding the fact that date value is the only thing that makes difference, a simple way is to use aggregate function (such as min or max). I used max, but you can change it if you want:
SELECT t3.id_js,
t5.divisi_area,
t4.name_methode_repair,
t1.urutan AS sort,
MAX (TO_DATE (t1.time_finished_work, 'DD/MM/YYYY')) AS date_finished
FROM tb_work t1
JOIN tb_inspection t2 ON t1.id_inspection = t2.id_inspection
JOIN tb_jobsheet t3 ON t2.id_js = t3.id_js
JOIN tb_methode_repair t4
ON t1.id_methode_repair = t4.id_methode_repair
JOIN tb_divisi t5 ON t1.id_divisi = t5.id_divisi
WHERE t3.id_js = 142414
GROUP BY t3.id_js,
t5.divisi_area,
t4.name_methode_repair,
t1.urutan
ORDER BY t3.id_js, date_finished DESC
You'd remove date column from GROUP BY; besides, if you wanted to select distinct rows, why didn't you apply select distinct instead of using group by? Result is the same, but - group by is generally used with aggregates, not to return distinct result.
I have a query that I need for it to return a record even when there are no records. In the case where there are records, I simply want those records returned. On the other hand, when there are no records, I need it to still return a record but with the value for the "context" column (the GROUP BY column) equal to the value of the GROUP BY column that did not meet the criteria and a default value for aggregate function/column (e.g., 0). I tried a subquery:
SELECT
(
SELECT
CONTEXT,
SUM(VAL)
FROM
A_TABLE
WHERE
COL = 'absent'
GROUP BY
CONTEXT
)
FROM
DUAL;
but anything greater than one column in the subquery SELECT clause fails w/ a "too many values" message.
I also tried a UNION (with a little more context to more faithfully represent my situation):
SELECT
*
FROM
(
SELECT
CONTEXT,
SUM(VAL)
FROM
A_TABLE
WHERE
COL = 'absent'
GROUP BY
CONTEXT
UNION
SELECT
CONTEXT,
0
FROM
B_TABLE
)
AB_TABLE
INNER JOIN C_TABLE C -- just a table that I need to join to
ON
C.ID = AB_TABLE.C_ID
WHERE
C.ID = 10
AND ROWNUM = 1 -- excludes 2nd UNION subquery result when 1st returns record;
This one does work but I don't know why since the 2nd UNION subquery does not seem to be expressly connected w/ the first (I need the 2nd CONTEXT value to be the same as the 1st for the case where the 1st returns no records). The problem is that the real query does not return any records when I try to implement a similar strategy. I would like to see if there's a better way to approach this problem and perhaps get it to work for the real query (not included as it is too large and somewhat sensitive).
I am not sure I understand the question, but let's try.
I believe what you are saying is this. You have a table called A_TABLE, with columns CONTEXT, VAL, COL (and perhaps others as well).
You want to group by CONTEXT, and get the sum of VAL but only for those rows where COL = 'absent'. Otherwise you want to return a default value (let's say 0).
This can be done with conditional aggregation. The condition is in a CASE expression within the SUM, not in a WHERE clause (as you saw already, if you filter by COL='absent', in a WHERE clause, the query - past the WHERE clause - has no knowledge of the CONTEXT values that don't appear in any rows with COL = 'absent').
If the "default value" was NULL, you could do it like this:
select context, sum(case when col = 'absent' then value end) as val
from a_table
group by context
;
If the default value is anything other than NULL, the temptation may be to use NVL() around the sum. However, if VAL may be NULL, then it is possible that SUM(VAL) is NULL even when there are rows with COL = 'absent'. To address that possibility, you must leave the sum as NULL in those cases, and instead set the value to 0 (or whatever other "default value") only when there are NO rows with COL = 'absent'. Here is one way to do that. Still a standard "conditional" aggregate query:
select context,
case when count(case when col = 'absent' then 1 end) > 0
then sum(case when col = 'absent' then value end)
else 0 -- or whatever "default value" you must assign here
end as val
from a_table
group by context
;
Here's another way you could handle it that avoids the two additional tables (B_TABLE and C_TABLE).
SELECT context
, MAX(val)
FROM (
SELECT context
, SUM(val) as val
FROM a_table
WHERE col = 'absent'
GROUP BY context
UNION
SELECT context
, 0 as val
FROM a_table
) t
GROUP BY context
This assumes the default value you want to return is 0 and that any value in A_TABLE.VAL will be a positive integer.
http://sqlfiddle.com/#!4/c6ca0/20
SELECT b.context
, sum(a.val)
FROM b_table b
LEFT OUTER JOIN a_table a
ON a.context = b.context
AND a.col = 'absent'
GROUP BY b.context
I'm sorry for my strange title, but I don't know what exactly I'm looking for. The task is quite simple. I have the table of competitions. Another table groups. In every group there are several contestants. In the last table are stored the results of contestants. The task is to get the first three of the contestants of every group.
So I have to loop through the groups, get the first three contestants (according to achieved points) of every group and append them into some variable.
Here is the pseudocode:
CREATE OR REPLACE PROCEDURE get_first_three_of_all(contestants OUT SOME_TYPE) AS
CURSOR groups SELECT...
BEGIN
FOR group IN groups LOOP
APPEND(contestants, get_first_three_of_one_group(group.id))
END LOOP;
END;
I have no idea, how to solve this task. I even don't know what should I look for. Would you be so kind and help me, please? Thanks.
Edited: simplified structure of my tables:
Competition: competition_id
Contestant: contestant_id
GroupContestant: contestant_group_id, competition_d, group_number, contestant_id
Result: contestant_group_id, juror, points
Select to get data of one group (group number YYY) is here:
SELECT * FROM (
SELECT res.contestant_group_id, SUM(res.points) AS points
FROM Result res
WHERE res.couple_group_id IN (SELECT couple_group_id
FROM GroupContestant
WHERE competition_id = XXX
AND group_number = YYY)
GROUP BY res.contestant_group_id
ORDER BY points DESC
)
WHERE ROWNUM <= 3;
Analytic functions to the rescue. To select top 3 results for each group, each competition:
SELECT * FROM (
SELECT grp.competition_id, grp.group_number, res.contestant_group_id, res.points,
row_number() over (partition by grp.competition_id, grp.group_number
order by res.points desc) rn
FROM (SELECT contestant_group_id, SUM(points) AS points
FROM Result
GROUP BY contestant_group_id) res
JOIN GroupContestant grp ON (grp.contestant_group_id = res.contestant_group_id)
)
WHERE rn <= 3;
Pay attention to how you resolve ties (consider using rank or dense_rank instead of row_number).
You can use RANK() analytic function to achieve the goal:
select *
from (select group_num,
points,
rank() over(partition by group_num order by points desc) rank
from results
inner join group_contestant
using (contestant_group_id))
where rank <= 3
order by group_num, points desc;
Here is SQLFiddle to play with.
I'm trying to display only the largest group in this group by statement;
SELECT COUNT(type) AS booking, type FROM booking b, room r WHERE r.rno = b.rno AND r.hno = b.hno GROUP BY type;
I modified it so we get this query response now you can see group double is larger then family.
BOOKING TYPE
5 double
2 family
I know there is a HAVING keyword you can add in order display only a count compared to a number so I could do COUNT(type) HAVING > 2 or similar but that's not very dynamic and that would only work in this instance because I know the two amounts.
ORDER BY COUNT(type) DESC LIMIT 1
There isn't a having statement that does this. But you can use rownum with a subquery:
select t.*
from (SELECT COUNT(type) AS booking, type
FROM booking b join
room r
on r.rno = b.rno AND r.hno = b.hno
GROUP BY type
order by count(type) desc
) t
where rownum = 1;
Just order your query..
order by booking desc
regards
TRY this
SELECT COUNT(type) AS booking, type FROM booking b, room r WHERE r.rno = b.rno AND r.hno = b.hno ORDER BY type DESC LIMIT 1