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I'm working with a script that only takes integer values. I'm reading from a CSV with a timestamp example of 12:34. Is there a way I get ruby to read it as an integer?
Not sure if you are dealing with a Time object. If so:
str = Time.now.to_s[/\d\d:\d\d:\d\d/]
=> "19:04:53"
str.gsub(":", "").to_i
=> 190453
If it's a string just start with the sub:
"12:34".sub(":", "").to_i
=> 1234
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I'm trying to use a negative value in a string which is in a hash.
{"amount"=>"-50.01", "currency"=>"CAD"}
If I write transaction.amount I get 0.5001E2, if I use to_f I get 50.01.
I'm trying to extract the -50 value.
Thank you for your help!
Try
transaction['amount']
For example
a = {"amount"=>"-50.01", "currency"=>"CAD"}
Then
a['amount']
returns '-50.01'
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There is one string like this: 'xxxxxxx#code#xxxxxxxx', I want to replace the code.
Use regex and string.gsub()
2.0.0-p643 :004 > "xxxxxxx#code#xxxxxxxx".gsub(/\#code#/i, "#NEWCODE#")
=> "xxxxxxx#NEWCODE#xxxxxxxx"
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I have an api, which has java DateTime type, which returns the following hash:
{"Date":1403592945000}
The actual date value is: "2014-06-24 06:55:45". How do I convert it in Ruby?
Time.at is the function you want to use. However, it seems that your value also contains milliseconds, that in Ruby should passed apart.
Time.at(1403592945000) # wrong
Time.at(1403592945) # => 2014-06-24 08:55:45 +0200
This will work:
Time.at(hash['Date']/1000)
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I'm trying to split a string in 2 parts: the first word and the last one.
I know I need to use the .split method but don't know how.
Is this what you want to do?
first, *_, last = "now is the time for all".split
first #=> "now"
last #=> "all"
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I want for a variable to be 'name' for example. If I use read(x) and for that variable to be char it will only load the first letter. So if i type 'name' it would be only the first letter.
the word you refer to is actually called string, so you can declare a variable and read string in it:
var
msg:string[10];
begin
readln(msg);
writeln(msg);
end.