Extracting output to use for a variable in bash - bash

After running an fdisk -l, I want to be able to extract the volume group name to input later in a bash script. Example below:
fdisk -l | grep /dev/mapper/vg_palpatine
Disk /dev/mapper/vg_palpatine-lv_root: 105.1 GB
vgextend /dev/vg_$vg_name $partitioned_drive
I want to extract palpatine out of the fdisk -l output and input it as my $vg_name variable. I've been suggested a few different solutions, like sed, cut and awk, but I don't have much experience with those. How would I go about doing this?

We can whole input string with the volume name only. To do this, we ask sed to replace (s///) regex matching with second expression:
vg_name=$(fdisk -l | grep /dev/mapper/vg_palpatine | sed -rn 's/.*vg_(.+)-lv_root.*/\1/p')
Regex explanation:
.* -> Any number of characters.
vg_(.+)-lv_root -> Capture the volume name as group 1.
We use the .* to match the whole input string, then we use group 1 (\1), which captures the volume name only, as substitution.
Note that if you want to use $vg_name on a different script you need to export it first.

You can use this:
vg_name=$(fdisk -l | grep /dev/mapper/vg_palpatine | sed -n "s/.*\/\(.*\)-.*/\1/p")
vgextend /dev/$vg_name $partitioned_drive

Related

Extracting all but a certain sequence of characters in Bash

In bash I need to extract a certain sequence of letters and numbers from a filename. In the example below I need to extract just the S??E?? section of the filenames. This must work with both upper/lowercase.
my.show.s01e02.h264.aac.subs.mkv
great.s03e12.h264.Dolby.mkv
what.a.fab.title.S05E11.Atmos.h265.subs.eng.mp4
Expected output would be:
s01e02
s03e12
S05E11
I've been trying to do this with SED but can't get it to work. This is what I have tried, without success:
sed 's/.*s[0-9][0-9]e[0-9][0-9].*//'
Many thanks for any help.
With sed we can match the desired string in a capture group, and use the I suffix for case-insensitive matching, to accomplish the desired result.
For the sake of this answer I'm assuming the filenames are in a file:
$ cat fnames
my.show.s01e02.h264.aac.subs.mkv
great.s03e12.h264.Dolby.mkv
what.a.fab.title.S05E11.Atmos.h265.subs.eng.mp4
One sed solution:
$ sed -E 's/.*\.(s[0-9][0-9]e[0-9][0-9])\..*/\1/I' fnames
s01e02
s03e12
S05E11
Where:
-E - enable extended regex support
\.(s[0-9][0-9]e[0-9][0-9])\. - match s??e?? with a pair of literal periods as bookends; the s??e?? (wrapped in parens) will be stored in capture group #1
\1 - print out capture group #1
/I - use case-insensitive matching
I think your pattern is ok. With the grep -o you get only the matched part of a string instead of matching lines. So
grep -io 'S[0-9]{2}E[0-9]{2}'
solves your problem. Compared to your pattern only numbers will be matched. Maybe you can put it in an if, so lines without a match show that something is wrong with the filename.
Suppose you have those file names:
$ ls -1
great.s03e12.h264.Dolby.mkv
my.show.s01e02.h264.aac.subs.mkv
what.a.fab.title.S05E11.Atmos.h265.subs.eng.mp4
You can extract the substring this way:
$ printf "%s\n" * | sed -E 's/^.*([sS][0-9][0-9][eE][0-9][0-9]).*/\1/'
Or with grep:
$ printf "%s\n" *.m* | grep -o '[sS][0-9][0-9][eE][0-9][0-9]'
Either prints:
s03e12
s01e02
S05E11
You could use that same sed or grep on a file (with filenames in it) as well.

How to create argument variable in bash script

I am trying to write a script such that I can identify number of characters of the n-th largest file in a sub-directory.
I was trying to assign n and the name of sub-directory into arguments like $1, $2.
Current directory: Greetings
Sub-directory: language_files, others
Sub-directory: English, German, French
Files: Goodmorning.csv, Goodafternoon.csv, Goodevening.csv ….
I would be at directory “Greetings”, while I indicating subdirectory (English, German, French), it would show the nth-largest file in the subdirectory indicated and calculate number of characters as well.
For instance, if I am trying to figure out number of characters of 2nd largest file in English, I did:
langs=$1
n=$2
for langs in language_files/;
Do count=$(find language_files/$1 name "*.csv" | wc -m | head -n -1 | sort -n -r | sed -n $2(p))
Done | echo "The file has $count bytes!"
The result I wanted was:
$ ./script1.sh English 2
The file has 1100 bytes!
The main problem of all the issue is the fact that I don't understand how variables and looping work in bash script.
no need for looping
find language_files/"$1" -name "*.csv" | xargs wc -m | sort -nr | sed -n "$2{p;q}"
for byte counting you should use -c, since -m is for char counting (it may be the same for you).
You don't use the loop variable in the script anyway.
Bash loops are interesting. You are encouraged to learn more about them when you have some time. However, this particular problem might not need a loop. Set lang (you can call it langs if you prefer) and n appropriately, and then try this:
count=$(stat -c'%s %n' language_files/$lang/* | sort -nr | head -n$n | tail -n1 | sed -re 's/^[[:space:]]*([[:digit:]]+).*/\1/')
That should give you the $count you need. Then you can echo it however you like.
EXPLANATION
If you wish to learn how it works:
The stat command outputs various statistics about the named file (or files), in this case %s the file's size and %n the file's name.
The head and tail output respectively the first and last several lines of a file. Together, they select a specific line from the file
The sed command screens a certain part of the line. (You can use cut, instead, if you prefer.)
If you wish to be cleverer, then you can optimize as #karafka has done.

Search all occurences of a instance ids in the variable

I have a bash variable which has the following content:
SSH exit status 255 for i-12hfhf578568tn
i-12hdfghf578568tn is able to connect
i-13456tg is not able to connect
SSH exit status 255 for 1.2.3.4
I want to search the string starting with i- and then extract only that instance id. So, for the above input, I want to have output like below:
i-12hfhf578568tn
i-12hdfghf578568tn
i-13456tg
I am open to use grep, awk, sed.
I am trying to achieve my task by using following command but it gives me whole line:
grep -oE 'i-.*'<<<$variable
Any help?
You can just change your grep command to:
grep -oP 'i-[^\s]*' <<<$variable
Tested on your input:
$ cat test
SSH exit status 255 for i-12hfhf578568tn
i-12hdfghf578568tn is able to connect
i-13456tg is not able to connect
SSH exit status 255 for 1.2.3.4
$ var=`cat test`
$ grep -oP 'i-[^\s]*' <<<$var
i-12hfhf578568tn
i-12hdfghf578568tn
i-13456tg
grep is exactly what you need for this task, sed would be more suitable if you had to reformat the input and awk would be nice if you had either to reformat a string or make some computation of some fields in the rows, columns
Explanation:
-P is to use perl regex
i-[^\s]* is a regex that will match literally i- followed by 0 to N non space character, you could change the * by a + if you want to impose that there is at least 1 char after the - or you could use {min,max} syntax to impose a range.
Let me know if there is something unclear.
Bonus:
Following the comment of Sundeep, you can use one of the improved versions of the regex I have proposed (the first one does use PCRE and the second one posix regex):
grep -oP 'i-\S*' <<<$var
or
grep -o 'i-[^[:blank:]]*' <<<$var
You could use following too(I tested it with GNU awk):
echo "$var" | awk -v RS='[ |\n]' '/^i-/'
You can also use this code (Tested in unix)
echo $test | grep -o "i-[0-z]*"
Here,
-o # Prints only the matching part of the lines
i-[0-z]* # This regular expression, matches all the alphabetical and numerical characters following 'i-'.

Joining every group of N lines into one with bash

I would like to join every group of N lines in the output of another command using bash.
Are there any standard linux commands i can use to achieve this?
Example:
./command
46.219464 0.000993
17.951781 0.002545
15.770583 0.002873
87.431820 0.000664
97.380751 0.001921
25.338819 0.007437
Desired output:
46.219464 0.000993 17.951781 0.002545
15.770583 0.002873 87.431820 0.000664
97.380751 0.001921 25.338819 0.007437
If your output has consistent number of fields, you can use xargs -n N to group on X elements per line:
$ ...command... | xargs -n4
46.219464 0.000993 17.951781 0.002545
15.770583 0.002873 87.431820 0.000664
97.380751 0.001921 25.338819 0.007437
From man xargs:
-n max-args, --max-args=max-args
Use at most max-args arguments per command line. Fewer than max-args
arguments will be used if the size (see the -s option) is exceeded,
unless the -x option is given, in which case xargs will exit.
Seems like you're trying to join every two lines with the delimiter \t(tab). If yes then you could try the below paste command,
command | paste -d'\t' - -
If you want space as delimiter then use -d<space>,
command | paste -d' ' - -

Getting max version by file name

I need to write a shell script that does the following:
In a given folder with files that fit the pattern: update-8.1.0-v46.sql I need to find the maximum version
I need to write the maximum version I've found into a configuration file
For 1, I've found the following answer: Shell script: find maximum value in a sequence of integers without sorting
The only problem I have is that I can't get down to a list of only the versions,
I tried:
ls | grep -o "update-8.1.0-v\(\d*\).sql"
but I get the entire file name in return and not just the matching part
Any ideas?
Maybe move everything to awk?
I ended up using:
SCHEMA=`ls database/targets/oracle/ | grep -o "update-$VERSION-v.*.sql" | sed "s/update-$VERSION-v\([0-9]*\).sql/\1/p" | awk '$0>x{x=$0};END{print x}'`
based on dreamer's answer
you can use sed for this:
echo "update-8.1.0-v46.sql" | sed 's/update-8.1.0-v\([0-9]*\).sql/\1/p'
The output in this case will be 46
grep isn't really the best tool for extracting captured matches, but you can use look-behind assertions if you switch it to use perl-like regular expressions. Anything in the assertion will not be printed when using the -o flag.
ls | grep -Po "(?<=update-8.1.0-v)\d+"
46

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