I have table with 3 important atributes: CT, DATE and OpenClosed. I have combo chart (on X axis is Date {2016-6-12} day by day) with two values: Count( {< OpenClosed = {'CLOSED'} >}Distinct CT) and Count( {< OpenClosed = {'OPEN'} >}Distinct CT) for open and closed CTs. I need add line chart to this combo chart with sum of counts of Open CTs day by day. For example: 4th December 2200 CTs, 5th December 2310 CTs, 6th December 2250 CTs..... Is it possible, or I must do some special table in Excel in this case? Thanks for your answers ;)
edited:
TOTAL OPEN CT is solved by Count( {< OpenClosed = {'OPEN'} >}Distinct CT)
It is for all days, but I need line chart day by day to combo chart...
Related
There is 2 dates column one is from date and second is to date .. and i want to get month difference from these two dates
like if
from date to date month difference
01-02-2019 02-02-2020 13
here 02 (feb) month 2019 till 02 (feb) moth 2020 so this means total 13 months covered..
i tried this but this shows wrong results
month(from date) - month(to date)
and i also try this
month([from date] - [to date])
I've been using the code below for this case.
It basically converts both dates to months and returns the difference.
First the Year component of the date is "converted" to months (year([to date]) * 12 part) and second adds the month number of the date (month([to date])
Num (
( (year([to date]) * 12) + month([to date]) )
- ( ((year([from date]) * 12) + month([from date])) ) + 1
)
UPDATE:
below is a screenshot of the result table with 2 expressions - including the +1 and excluding it. Depends how you want to calculate the full months +1 will "include" the last month as well
I'm working on Excel and Power Pivot and I'm trying to get the average sales between the last day of the past month and the last day of the current month, but I'm unable to get the right expression for it.
I have the "Credits" table and the "Calendar" table, both linked by the "Date" field.
So, this is what I have:
=CALCULATE ( AVERAGE(Credits[Sales] );
FILTER ( Calendar ;
Calendar[DateNum] >= VALUE(FORMAT(STARTOFMONTH(Calendar[Date])-1;"YYYYMMDD"))
&&
Calendar[DateNum] <= VALUE(FORMAT(ENDOFMONTH(Calendar[Date]);"YYYYMMDD"))))
I use that measure in a dynamic table along with the "Month" dimension, but it only shows the average for the full month, not taking into account the filters I'm trying to apply so that it also takes the last day from the previous month.
I think what's happening is that the month is still in your filter context.
Try FILTER( ALL(Calendar) ; instead.
I think you could probably also simplify your measure a bit. Maybe try something along these lines:
CALCULATE(
AVERAGE( Credits[Sales] );
DATESBETWEEN(
Calendar[Date];
STARTOFMONTH( Calendar[Date] ) - 1;
ENDOFMONTH( Calendar[Date] )
)
)
I have the following query that gets the week of a date:
SELECT pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww') semana,
SUM (rta.kms_acumulados) kms,
COUNT
(DISTINCT (CASE
WHEN v.secuencia BETWEEN rta.sec_origen AND rta.sec_destino
THEN v.cod_inc
ELSE '0'
END
)
)
- 1 numincidencias
FROM (SELECT ms.tren, ms.fecha_origen_tren, ms.secuencia, ri.cod_inc
FROM r_incidencias ri, mer_sitra ms
WHERE ri.cod_serv = ms.tren
AND ri.fecha_origen_tren = ms.fecha_origen_tren
AND ri.cod_tipoin IN (SELECT cod_tipo_iincidencia
FROM v_tipos_incidencias
WHERE grupo = '45')
AND ri.punto_desde = ms.cod_estacion) v,
r_trenes_asignar rta,
r_maquinas rm,
planificador.pl_dh_material pdm
WHERE rta.fecha BETWEEN TO_DATE ('21/09/2018', 'dd/mm/yyyy') AND TO_DATE ('21/09/2018',
'dd/mm/yyyy'
)
AND rta.serie >= 4000
AND rta.matricula_ant IS NOT NULL
AND rm.matricula_maq = rta.matricula_ant
AND rm.cod_serie = pdm.id_material
AND rta.grafico BETWEEN pdm.desde AND pdm.hasta
AND v.tren(+) = rta.tren
AND v.fecha_origen_tren(+) = rta.fecha
GROUP BY pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww')
ORDER BY pdm.serie, rta.matricula_ant, TO_CHAR (fecha, 'ww')
For example week 1
I want to display
week 1 : 1 january - 7 january
How can I get this?
Oracle offers the TRUNC(datestamp, format) function to manipulate dates this way. You may use a variety of format strings to get the first day of a quarter, year, or even the top of the hour.
Given a particular datestamp value, Oracle returns midnight on the first day of the present week with this expression:
TRUNC(datestamp,'DY')
You can add days to a datestamp. Therefore this expression gives you midnight on the last day of the week
TRUNC(datestamp,'DY') + 6
A WHERE-clause selector for all rows in the present week might be this.
WHERE datestamp >= TRUNC(SYSDATE,'DY')
AND datestamp < TRUNC(SYSDATE,'DY') + 7
Notice that the end of the range is just before (<) midnight on the first day of the next week. You need that because you may have datestamps after midnight on the last day of the week. (Beware using BETWEEN for datestamp ranges.)
And,
SELECT TO_CHAR(TRUNC(SYSDATE,'DY'),'YYYY-MM-DD'),
TO_CHAR(TRUNC(SYSDATE,'DY')+6,'YYYY-MM-DD')
FROM DUAL;
displays the first and last dates of the present week in ISO-like format.
Date arithmetic is cool. It's worth your trouble to study the date-arithmetic functions in your DBMS at least once a year.
Can someone explain me what does the below oracle query do and what is it's output?
select unique trunc(sysdate-370 + level, 'IW') AS datetime from dual
connect by level <= 360 order by datetime;
select sysdate-370 + level AS datetime
from dual
connect by level <= 360;
Will generate 360 rows starting with the current date/time minus 370 days plus one day per row. So rows between 369 and 10 days before the current date/time.
TRUNC( datetime, 'IW' ) will truncate the date to the start of the ISO week (midnight on Monday of that week - irrespective of the NLS settings for date language and/or territory that affect some other options for truncating dates). So you will end up with duplicate rows for each generated row that is in the same week.
The UNIQUE keyword will get rid of those duplicate rows.
The order by datetime will order the results in ascending date order - however, the rows are generated in ascending order so this clause is unnecessary.
So the output will be 52 or 53 rows (depending on what the current day of the week is) starting with Monday midnight of each week containing the date 369 days before the current day up until the week containing 10 days before the current date.
The output (when run on 13th September 2017) is 52 rows (I skipped a few):
05-SEP-2016
12-SEP-2016
19-SEP-2016
26-SEP-2016
03-OCT-2016
...
31-JUL-2017
07-AUG-2017
14-AUG-2017
21-AUG-2017
28-AUG-2017
According to documentation trunc(dateval, 'IW') truncates to:
Same day of the week as the first day of the calendar week as defined by the ISO 8601 standard, which is Monday
connect by level <= N is a trick for producing a set of N rows with level values from 1 to N.
I have used the below query to find the number of weeks between two dates:
select count(week_id)
from fw
where week_begin_date >= '2015-01-01'
and week_end_date <= '2015-12-31';
Expected result should be 53 but the actual result is 51.
Kindly help on this.
Can't you just use the week of year function? subtract if needed...
select to_char(to_date('12/31/2015','MM/DD/YYYY'),'WW') from dual;
select To_Number(to_char(to_date('12/31/2015','MM/DD/YYYY'),'WW')) -
To_number(to_char(to_date('01/01/2015','MM/DD/YYYY'),'WW')) +1
from dual;
We have to add +1 because weeks start at 1 not 0.
Now maybe you're after the ISO week format which would be IW instead of WW.
WW: Week of year (1-53) where week 1 starts on the first day of the year and continues to the seventh day of the year.
IW: Week of year (1-52 or 1-53) based on the ISO standard.
I know this is a very old thread, but I used a modified version of this code today that I thought might be beneficial for someone else. My modification solves for the fractional week issue and the removal of the minus sign:
SELECT
CEIL(
ABS(
(
TO_DATE('20160101','YYYYMMDD')
- TO_DATE('20161231','YYYYMMDD')
) / 7
)
) AS DT
FROM DUAL
The ABS function takes the absolute value of the result of subtracting the two dates, thereby eliminating the minus sign if it exists (I switched the order of the dates to demonstrate this). The CEIL function rounds up any fractional week to the next whole week (I changed the year to 2016 to demonstrate this - CEIL is logically equivalent to the ROUNDUP function in Excel). NOTE: We have to apply the ABS function first (inner parenthesis) because CEIL will also round up negative numbers, which would in effect round the weeks down if ABS were applied after CEIL. The result of this calculation is 53 (subtraction of the dates returns about -52.142857, ABS removes the minus sign, CEIL rounds up to 53).
I hope this ends up being useful to someone. Thanks.
Did you try this:
SELECT
REPLACE((
to_date('20151231','yyyymmdd') - to_date('20150101','yyyymmdd')
)/7, '-', '')
FROM
DUAL