My Project is using spotless plugin. I need to ignore java files from the generated-resources directory. How to do the same.
This is how I am using the plugin.
apply plugin: "com.diffplug.gradle.spotless"
spotless {
lineEndings = 'unix';
java {
eclipseFormatFile "eclipse-java-google-style.xml"
}
}
sourceSets has generated-resources directory included which I do not want to remove.
You can specify a target for the spotless formatter which allows includes and excludes.
I use the following in the top-level build.gradle in a multi-project build where all Java code resides in subdirectories under the modules directory:
subprojects {
...
spotless {
java {
target project.fileTree(project.rootDir) {
include '**/*.java'
exclude 'modules/*/generated/**/*.*'
}
googleJavaFormat()
}
}
...
}
Related
Gradle project deprecated 'classesDir' so the previously working method:
sourceSets {
main {
output.classesDir = "myDir"
}
}
should be replaced with something else. Documentation talks about 'output.classesDirs' but this is read-only property.
What is the method to specify custom compilation output directory in Gradle 4.x scripts?
If you are working with java you can do this
apply plugin: 'java'
sourceSets {
main {
// Compiled Java classes should use this directory
java.outputDir = file('myDir')
}
}
See more: https://docs.gradle.org/current/javadoc/org/gradle/api/tasks/SourceSetOutput.html
As per Gradle 6.5.1 docs the java.outputDir property is has been replaced by classesDirectory:
Gradle 6.5.1 docs for SourceDirectorySet
However I think that the destinationDirectory property should be used to read or modify the compiler output dir. So the docs should say that it is replaced by the destinationDirectory property rather than the classesDirectory property.
The compiler output directory can be changed using either of the following ways:
sourceSets {
main {
java {
destinationDirectory.set(file("${project.buildDir}/classes/${sourceSets.main.name}/java"))
}
}
}
OR
sourceSets {
main {
java {
destinationDirectory.value(project.getLayout().getBuildDirectory().dir("classes/${sourceSets.main.name}/java"));
}
}
}
In my opinion, the second option is better.
To read the output dir for a particular sourceSet use:
project.sourceSets.main.java.destinationDirectory.get()
I'm trying to get Gradle to handle the deployment of a very large Web application. In the past when we used Ant, instead of creating a very large .war file, we would simply assemble all the code in one folder--libraries, .jsp's etc--and then scp them to the deployment destination. This would speed deployment since we would be moving only the files that changed.
I'm having trouble trying to do this with Gradle, however. Using the War plugin creates an actual .war file, which we don't want. I've tried simply creating a task that depends on 'classes' and that generates the necessary classes and resources folders. However, where are the library dependencies? How can I get this all in one place so I can do an scp?
Current build:
apply plugin: "java"
apply plugin: "maven"
apply plugin: 'war'
apply plugin: 'eclipse-wtp'
sourceCompatibility = 1.6
targetCompatibility = 1.6
repositories {
maven {
url 'http://buildserver/artifactory/repo'
}
}
sourceSets {
main {
java {
srcDir 'src'
}
resources {
srcDir 'src'
}
}
}
webAppDirName = 'web'
dependencies {
compile 'antlr:antlr:2.7.6'
compile 'antlr:antlr:2.7.7'
*** etc ***
}
task deploystage(dependsOn: 'classes') << {
println 'assemble and scp code here'
}
your right Opal ... no easynway to use the War plugin for this ... although it would be nice if it had a createExplodedWar option. I just used the Jar plugin methods.
The .jars were available, along with other things in war.classpath.files:
gradle.taskGraph.whenReady { TaskExecutionGraph taskGraph ->
project.ext.set("allclasspathjars", files(war.classpath.files))
}
I then when through these to separate out the .jars from the other stuff:
task deployJars(dependsOn: 'classes') << {
FileUtils.cleanDirectory(new File("web/WEB-INF/lib/"))
project.allclasspathjars.each {File file ->
if(file.name.endsWith(".jar")) {
println "Including .jar: " + file.name
org.apache.commons.io.FileUtils.copyFile(file, new File("web/WEB-INF/lib/" + file.name))
}
}
After this I could copy all the classes & resources into the .war structure:
task createExplodedWar(type: Copy, dependsOn: 'deployJars') {
from 'build/classes/main'
from 'build/resources/main'
into 'web/WEB-INF/classes'
}
Finally used Gradle SSH Plugin to push it up to tomcat and restart the server.
All good.
I am new to Gradle and I have a source code location different than what Gradle expects.
Gradle expects to find the production source code under src/main/java and your test source code under src/main/resources. How do I configure Gradle to a different source code?
You have to add few lines to build.gradle:
To replace the default source folders, you will want to use srcDirs instead, which takes an array of the path.
sourceSets {
main.java.srcDirs = ['src/java']
main.resources.srcDirs = ['src/resources']
}
Another way of doing it is:
sourceSets {
main {
java {
srcDir 'src/java'
}
resources {
srcDir 'src/resources'
}
}
}
The same thing is applicable to test folder too.
I have a multi-project gradle build using the java plugin setup as follows:
myProj/
settings.gradle
build.gradle
util/
build.gradle
In my util project, I would like to generate 2 jars... one for packageA and one for packageB. I'm a noob with gradle so any help here would be much appreciated. Here are my settings and gradle files:
myProj/settings.gradle
include 'util'
myProj/build.gradle
subprojects {
apply plugin: 'java'
repositories {
maven {
url "http://mymavenurl"
}
}
sourceSets {
main {
java {
srcDir 'src/java'
}
}
}
}
myProj/util/build.gradle
dependencies {
.
.
.
}
jar {
baseName = 'packageA'
includes = ['com/mycomp/packageA']
}
task packageBJar(type: Jar) {
dependsOn classes
includes = ['com/mycomp/packageB']
baseName = 'packageB'
}
When I try to build my project here is the output:
:util:compileJava
:util:processResources UP-TO-DATE
:util:classes
:util:jar
:util:assemble
:util:compileTestJava UP-TO-DATE
:util:processTestResources UP-TO-DATE
:util:testClasses UP-TO-DATE
:util:test
:util:check
:util:build
I would hope to see :util:packageBJar after classes, but I'm not having any luck.
One way is to declare packageBJar as an artifact of, say, the archives configuration:
artifacts {
archives packageBJar
}
Now gradle assemble, and therefore also gradle build, will produce packageBJar.
1.My project has two main class i want to build jar for each main class using gradle. my source has 2 files ValidationRule.java
SupportValidator.java both the file have one main class each i want to
build the jar for each main class
i can achieve the same from eclipse working fine
2.I want to load the source file for my project from 2 different folder,some part is there in one folder and remaining is
there in
another folder i.e like
project/src snd another folder outside the project(../../../SharedClass)
my script as follows
apply plugin: 'eclipse'
apply plugin: 'java'
sourceCompatibility = 1.6
archivesBaseName = 'Process_XY'
configurations {
configurations.compile.transitive = false
}
dependencies {
compile fileTree(dir:'/trunk/Solutions/project/Source/Binaries/CommonFunctions/build/libs', include: '*.jar')
compile fileTree(dir:'/trunk/Solutions/project/lib/GeoTools/geotools-2.7.4-bin/geotools-2.7.4', include: '*.jar')
compile "org.apache.hadoop:hadoop-core:1.0.3"
compile "commons-collections:commons-collections:3.2.1"
compile "commons-configuration:commons-configuration:1.6"
compile "commons-discovery:commons-discovery:0.2"
compile "commons-lang:commons-lang:2.4"
compile "commons-logging:commons-logging:1.1.1"
compile "commons-logging:commons-logging:1.0.4"
compile "log4j:log4j:1.2.16"
compile "com.vividsolutions:jts:1.8"
compile "commons-net:commons-net:1.4.1"
compile "org.apache.hadoop:hadoop-core:1.0.3"
compile "commons-httpclient:commons-httpclient:3.0.1"
compile "org.mortbay.jetty:servlet-api:2.5-20081211"
compile "org.apache.hbase:hbase:0.94.0"
compile "org.apache.zookeeper:zookeeper:3.4.3"
}
repositories {
mavenCentral()
maven { url "https://repository.cloudera.com/artifactory/cloudera-repos/" }
maven { url "http://repo.springsource.org/libs-release" }
maven { url "http://repo.springsource.org/libs-milestone" }
maven { url "http://repo.springsource.org/libs-snapshot" }
maven { url "http://www.datanucleus.org/downloads/maven2/" }
maven { url "http://oss.sonatype.org/content/repositories/snapshots" }
maven { url "http://people.apache.org/~rawson/repo" }
}
jar {
from configurations.compile.collect { it.isDirectory() ? it : zipTree(it) }
manifest.attributes("Main-Class":"org.project.seismic.Process_XY")
}
sourceSets {
main {
java {
source = ['src/org', '../../../SharedClass/org']
}
}
}
above in sourceSets method i tried to load source from 2 folder but it
didnt worked
Thanks in advance..!!
How to achieve using gradle.
Ok, first of all, the source on a SourceDirectorySet takes another SourceDirectorySet. The srcDirs method however takes paths. Change that block to the following:
sourceSets {
main {
java {
srcDirs ['src/org', '../../../SharedClass/org']
}
}
}
And you can easily add a second jar task as follows:
task secondJar(type: Jar) {
name = other-main-jar
from ...
manifest.attributes(...)
}
assemble.dependsOn(secondJar)
This will register a new Jar task called secondJar and makes sure that when the project is assembled, this jar is also created.