find -iname not working in script - bash

Question

Following find command.
find Work/Linux4/test/test/test_goal/spyglass_reports/clock-reset/Ac_coherency06/ -iname "Ac_coherency*.csv"
is working fine when run on shell.
But in perl script it return nothing.
#!/bin/bash
REPORT_DIR=$1
FIND_CMD=$2
echo "##";
echo $REPORT_DIR ;
echo $FIND_CMD ;
LIST_OF_CSV=$(find $REPORT_DIR $FIND_CMD)
echo $LIST_OF_CSV
if [ "X" == "X${LIST_OF_CSV}" ]; then
echo "No files Found for : '$FIND_CMD' in directory ";
echo " '$REPORT_DIR' " | sed -e 's;Work/.*/test_reports;Work/PLATFORM/test_reports;g';
echo;
exit 0;
fi
Output of script:
##
Work/$PLATFORM_SPECIES/test_reports/clock-reset/Ac_coherency06 -iname "Ac_coherency06*.csv"
No files Found for : '-iname "Ac_coherency06*.csv"' in directory 'Work/PLATFORM/test_reports/clock-reset/Ac_coherency06'

Answer 1

If you're allowing a list of find predicates to be passed, keep them in list form, one argument to find per argument to your script. As an example implemented in this manner:
#!/bin/bash
# read report_dir off the command line, and shift it from arguments
report_dir=$1; shift
# generate a version of report_dir for human consumption
re='Work/.*/test_reports'
replacement='Work/PLATFORM/test_reports'
if [[ $report_dir =~ $re ]]; then
report_dir_name=${report_dir//${BASH_REMATCH[0]}/$replacement}
else
report_dir_name=$report_dir
fi
# read results from find -- stored NUL-delimited -- into an array
# using NUL-delimited inputs ensure that even unusual filenames work correctly
declare -a list_of_csv
while IFS= read -r -d '' filename; do
list_of_csv+=( "$filename" )
done < <(find "$report_dir" '(' "$#" ')' -print0)
# Use the length of that array to determine whether we found contents
echo "Found ${#list_of_csv[#]} files" >&2
if (( ${#list_of_csv[#]} == 0 )); then
echo "No files found in $report_dir_name" >&2
fi
Here, shift consumes the first argument from your list, and "$#" refers to all the others that remain after that point. This means that the items you want to have passed as separate, individual arguments to find can (and must) be passed as separate, individual arguments to your script.
Thus, with usage yourscript "/path/to/report/dir" -name '*.txt', initially, $1 will be /path/to/report/dir, $2 will be -name, and $3 will be *.txt. However, after shift is run, $1 will be -name, and $2 will be *.txt; and "$#" will refer to both of those, each passed as a separate word.
For details on the use of a while read loop to read items off of a stream, see BashFAQ #001.
For details on the syntax used for bash-native string replacement, see BashFAQ #100 or http://wiki.bash-hackers.org/syntax/pe
For details on shell arrays, including ${#arrayname[#]} to check their length or "${arrayname[#]}" to expand to their contents, see BashFAQ #005.

Answer 2

If you have a command that is running well on the shell but not on your script, the first thing I would try would be to specify Bash on the command being called, see if this works:
bash -c 'find Work/Linux4/test/test/test_goal/spyglass_reports/clock-reset/Ac_coherency06/ -iname "Ac_coherency*.csv"'
Or even better:
/bin/bash -c 'find Work/Linux4/test/test/test_goal/spyglass_reports/clock-reset/Ac_coherency06/ -iname "Ac_coherency*.csv"'
You could also store the result on a variable or other data structure as needed, and pass it later to the script, for example:
ResultCommand="$(bash -c 'find Work/Linux4/test/test/test_goal/spyglass_reports/clock-reset/Ac_coherency06/ -iname "Ac_coherency*.csv"')"
Edit: this answer was edited more than once to fix possible issues.