I want to save what I do with the ckeditor as a new document and use it as a view in laravel is possible? Any idea how I could do it?
thanks for your attention
Well, you are not providing and code, but you can do something like this and it should work. because this is just a WYSIWYG editor, you will need to use {!!$post(or whatever)->content!!}, this way every styling you make with the editor will be saved in the database and will not be escaped.
This is the controller where I keep everything in the ckeditor and saves it in the view resource
public function store(Request $request)
{
$ruta = base_path().'/resources/views/oficios/pdf/';
$nombre = "p.blade.php";
$archivo= $request->editor1;
\Storage::disk('pdf')->put($nombre, $archivo);
dd('Plantilla Guardada');
}
This is the html that is created with ckeditor for example:
<p><strong><em><s>{{ $oficio->subject }}</s></em></strong></p>
Then in another view I include #include ('oficios.pdf.p')
And it is there where I mark error by the character
Related
I'm devising a small CMS for the in-house development team, where all have experience working with laravel.
The CMS requires a small feature where the services that are listed can have a quotation form attached. Instead of creating a completely separate module to add elements & other separately, I wanted to have the system in a manner that the developer adds the laravel collective form code, which we store in the database.
While retrieving, we render the form server side.
Here's my implementation
Controller
public function show($id)
{
$data['page'] = Service::where('slug', $id)->first();
if ($data['page']) {
....
$data['form'] = $data['page']->quoteform()->first();
....
And in the view
{!! $form['html'] !!}
But this is definitely won't help, so I tried this approach of rendering the collective form
$data['form'] = View::make('website.includes.render-form',['form'=>$data['page']->quoteform()->first()]);
But I'm not sure if this should work, as I couldn't make it work.
Looking forward to a solution if at all the approach I choose is possible, if yes or can be done, would like to know more on the same.
TIA
Edit 1:
I used the following blade command Blade::compileString('string here') which helped to a certain extent.
where I'm getting the following result
You can render the HTML of a view using render() method. So you can update to this :
$data['form'] = View::make('website.includes.render-form',
['form' => $data['page']->quoteform()->first()]
)->render();
Now the $data['form'] will have rendered HTML which you can use in blade using {!! $data['html'] !!} if you are passing $data to your main view.
This is an extension from a post I made a few days ago: Change a page without refreshing - Laravel / Ajax
Basically, I'm trying to replicate the URL Structure of Soundcloud where you can click on a link, it'll load the content without refreshing the page however if you land directly on that page, it won't replicate design and effecitvely break.
I've been thinking of ways on how I can check in Laravel if the page is requested via Ajax or has been landed on without an Ajax call.
What's happening at the moment is that when I call the page, the view has a master template that's extended thus creating duplicate master templates on the one view.
I was thinking if I done something like
#if(!Request::ajax())
#extends('masterlayout')
#endif
It would work but tried and no luck.
Any help as always is greatly appreciated!
Thanks
Looks like #extends directive is always executed even in falsy if
You can add an empty layout and perform check like this:
#extends(Request::ajax()? 'layouts.empty' : 'layouts.master')
and you need add only this in layout empty.blade.php:
#yield('content')
or you can add ajax check in the master layout
#if(!Request::ajax())
// all layout code
#else
#yield('content')
#endif
You can check that in your controller action.
public function index(Request $request)
{
if($request->ajax()){
return "This is an AJAX call!";
}
return "Not an AJAX call...";
}
Thanks for all the answers, I eventually got this fixed by using #if(!Request::ajax()) on section that didn't need to be shown when the page was loaded via ajax.
Thank you again! :D
I'm still learning Laravel and I'm working on a small project to help me understand better. In the project, I am in need of a global array, so that I may display it or its attributes on every view rendered. sort of on a notification bar, so that each page the user visits, he/she can see the number of notifications (which have been fetched in the background and are stored in the array).
I have done some research, and realized that I have to fetch and compile the array in a view composer I think. But everywhere I go, I cant seem to understand how to make a view composer.
I need to fetch the relevant rows from the database table, and make the resulting array available to each view rendered (I'm thinking attaching it somehow to my layouts/default.blade.php file.). Please help, any and all advice is greatly appreciated:)
You can now inject services on your view
More info here: https://laracasts.com/series/whats-new-in-laravel-5-1/episodes/2
You have to use Sub-Views of laravel blade. I guess your functionality is like a sidebar or like a top bar which will be rendered at every page.
//Your Controller pass data
class YOUR_CONTROLLER extends Controller {
public function index()
{
$data = YOUR_DATA;
return view('YOUR_VIEW_FILE', get_defined_vars());
}
}
//In Your View File
#extends('LAYOUTS_FILE')
#section('YOUR_SECTION')
#include('YOUR_SUB_VIEW_FOR_NOTIFICATION')//You need not pass any data passed all data will be available to this sub view.
#endsection
In your sub view
//Do what ever you want looping logic rendering HTML etc.
//In your layout file just yield or render the section that's it
#yield('YOUR_SECTION')
More explanation can be found Including Sub-Views
I am trying to load a view from my controller using the follow code but I only get a raw HTML view and does not show the site's template.
$view = $this->getView( 'download', 'html' );
$view->display();
Can some help me in what I am doing wrong to display the site's template.
I also tried a redirect but that did not work either
$this->redirect(JRoute::_('index.php?option=com_atdwcsv&view=download'), false);
Edit: I figured out what was wrong with the redirect. Code I needed was
$this->setRedirect('index.php?option=com_atdwcsv&view=download');
$this->redirect();
I could be wrong, but I don't think you need to use the display() method on the view, I think you need to use $this->display(); instead.
symfony: http://www.symfony-project.org
pjax: https://github.com/defunkt/jquery-pjax
Hi all,
I'm trying to use pjax in symfony in order to speed up our website (we will be able to keep header and footer static most of the time, and also avoid reloading lots of css/js and other files).
I have no problem with ajax or symfony, but I want to know if there is a better way:
Is it a good idea to use postExecute to return the html code back right away without sf going to the template at all
If so, can I somehow write this only once for all modules? I imagine that I can do:
mySfActions extends sfActions
moduleActions extends mySfActions
I wonder if there is a better way?
3. Is there a way to get the current layout name (defined in the module's view.yml) within the controller/action?
Question 1: Don't use post-execute like that. If you need to return html from an ajax call in your action then your action should return like this:
return $this->renderText("<p>Your html result.</p>");
This will skip the template call.
Question 2: That is correct. You have written the best way to write a function once and have it available to all module actions.
There is nothing to do.
When calling an action via XmlHttpRequest, symfony automaticaly skip the Layout render, and only return the module render.
You need to put all your "static" assets and html in your layout and that's all.
Thank you all for helping me, all your answers were helpful and pointed me to the right direction. I wanted to vote for both answers but since I can only accept one, I accepted the very first answer.
Anyhow, here is what I did:
First, I extended the sfActions class so I don't have to do add preExecute on every module:
<?php
class mySfActions extends sfActions{
public function preExecute(){
$request = $this->getRequest();
if ($request->getParameter('_pjax')) {
$this->setLayout(false);
}
}
}
Then of course each of my module action class must extend this new class.
Inside my individual template I have something like this:
<?php if($sf_request->getParameter('_pjax')):?>
<script type="text/javascript" src="/js/question_list.js"></script>
<?php endif;?>
This currently seems to work quite well for me, I'm enjoy the incredible loading speed when pushstate is supported, and still able to fallback when it is not (on the dumb IE for example)