I have a Django view that runs a particular function when a POST request is received.
Snippet:
def run_function(request):
if request.method == 'POST':
run_some_function()
This is called via AJAX as follows:
$.ajax({
'type' : 'POST',
'url' : '/run_function/',
'data' : data,
'success' : function(json) {
// Display results to user
}
});
This works as expected. However, this particular function can take a while to run, so I want to display progress information to the user.
Luckily, I have another function that can return the progress (an integer between 0-100) of the task.
Snippet:
def get_progress(request):
progress = calculate_progress()
return HttpResponse(json.dumps(progress), content_type="application/json")
I can then make an AJAX call every X seconds to get the progress and update my progress bar:
function check_progress() {
$.ajax({
'type' : 'POST',
'url' : '/get_progress/',
'success' : function(response) {
if (response >= 100) {
// Update progress bar to 100% and clearInterval
} else {
// Update the progress bar based on the value returned by get_progress
}
}
});
}
var check = setInterval(check_progress, 500);
The problem is...how can I do both simultaneously? I need to be able to make the AJAX call to run the function and make the AJAX calls to monitor progress, at the same time.
Are there any suggestions for how to accomplish this? Or perhaps a better design than making two AJAX calls?
Thanks for any help!
The A in AJAX stands for Asynchronous. You don't need to do anything special. If you have your views and progress sorted out, all you need to do is:
$.ajax({
'type' : 'POST',
'url' : '/run_function/',
'data' : data,
'success' : function(json) {
// Display results to user
}
});
var check = setInterval(check_progress, 500);
Related
I'm trying to send some data from my view to my controller via ajax. How do I retrieve this data in my action?
I've tried jQuery's $.ajax and $.post methods, providing the url and data, but using $this->data, $this->request->data, $_POST, $_GET or $_REQUEST doesn't work (all return as empty arrays).
$.ajax({
url: "<?php echo Router::url( array("controller" => "Progression", "action" => "submit", $user['User']['id']) ); ?>",
type: 'post',
data: { name: "John" }
}).done( function(data) {
console.log(data);
});
function submit() {
$this->request->allowMethod('ajax');
$this->autoRender = false;
$data = array();
$data['answer'] = $this->request->data; // or any of $_POST, $_GET, etc.
return json_encode($data);
}
My console always keeps printing {"answer":[]}. I checked the network tab of my devtools and the data is successfully listed under Form data, yet I can't seem to get hold of the data in the action.
EDIT:
Thanks to Greg Schmidt I found out that my request indeed got redirected: first it gives me a 302, then it makes a new request without the post data and returns a 200. I just can't find what the critical difference is between the two requests (URLs look the same, no case difference or anything). Can anybody help me with that?
First request:
Second request:
I am currently creating an AJAX call which queries a controller and returns the appropriate reponse. The only issue is is that the response is coming back as undefined doe to the async nature of the AJAX cal. I am unsure as to how I tell the function to wait for the response. Here is my code:
View:
jQuery(document).on("click", "#payment .membership", function(e) {
e.preventDefault();
var price = SignUpObject.membershipClick(jQuery(this).attr("data-membership-id"));
alert(price);
});
Javascript Library Function (which is within an object):
var SignUpObject = {
membershipClick : function(membershipDetailsId) {
jQuery.ajax({
type : 'POST',
dataType : 'json',
url : 'api/membership-choice',
data : 'membershipid=' + membershipDetailsId
}).done(function(response) {
return response
});
}
}
The PHP that the AJAX call is calling returns the correct response back so I don't need to include them here. Can anyone tell me how to make the AJAX call wait for a response?
Thanks
You've got two problems:
1) You're attempting to call the response synchronously, before the (asynchronous) request has completed.
2) membershipClick does not return the request object, so you've got no means of hooking a completion callback onto it.
To fix:
1) Change the line
jQuery.ajax({...
to
return jQuery.ajax({
2) Change the line
alert(price);
to
price.done(function(response) { alert(response); });
However, the variable price would be better named something like price_request, since it stores a reference to the request, not the actual price (which is the response.)
Change
}).done(function(response) {
return response
});
For:
}), success: function(response) {
return response
};
I'm trying to use Ajax in CakePHP, and not really getting anywhere!
I have a page with a series of buttons - clicking one of these should show specific content on the current page. It's important that the page doesn't reload, because it'll be displaying a movie, and I don't want the movie to reset.
There are a few different buttons with different content for each; this content is potentially quite large, so I don't want to have to load it in until it's needed.
Normally I would do this via jQuery, but I can't get it to work in CakePHP.
So far I have:
In the view, the button control is like this:
$this->Html->link($this->Html->image('FilmViewer/notes_link.png', array('alt' => __('LinkNotes', true), 'onclick' => 'showNotebook("filmNotebook");')), array(), array('escape' => false));
Below this there is a div called "filmNotebook" which is where I'd like the new content to show.
In my functions.js file (in webroot/scripts) I have this function:
function showNotebook(divId) {
// Find div to load content to
var bookDiv = document.getElementById(divId);
if(!bookDiv) return false;
$.ajax({
url: "ajax/getgrammar",
type: "POST",
success: function(data) {
bookDiv.innerHTML = data;
}
});
return true;
}
In order to generate plain content which would get shown in the div, I set the following in routes.php:
Router::connect('/ajax/getgrammar', array('controller' => 'films', 'action' => 'getgrammar'));
In films_controller.php, the function getgrammar is:
function getgrammar() {
$this->layout = 'ajax';
$this->render('ajax');
}
The layout file just has:
and currently the view ajax.ctp is just:
<div id="grammarBook">
Here's the result
</div>
The problem is that when I click the button, I get the default layout (so it's like a page appears within my page), with the films index page in it. It's as if it's not finding the correct action in films_controller.php
I've done everything suggested in the CakePHP manual (http://book.cakephp.org/view/1594/Using-a-specific-Javascript-engine).
What am I doing wrong? I'm open to suggestions of better ways to do this, but I'd also like to know how the Ajax should work, for future reference.
everything you show seems fine. Double check that the ajax layout is there, because if it's not there, the default layout will be used. Use firebug and log function in cake to check if things go as you plan.
A few more suggestions: why do you need to POST to 'ajax/getgrammar' then redirect it to 'films/getgrammar'? And then render ajax.ctp view? It seems redundant to me. You can make the ajax call to 'films/getgrammar', and you don't need the Router rule. You can change ajax.ctp to getgrammar.ctp, and you won't need $this->render('ajax');
this is ajax call
$(function() {
$( "#element", this ).keyup(function( event ) {
if( $(this).val().length >= 4 ) {
$.ajax({
url: '/clients/index/' + escape( $(this).val() ),
cache: false,
type: 'GET',
dataType: 'HTML',
success: function (clients) {
$('#clients').html(clients);
}
});
}
});
});
This the action called by ajax
public function index($searchterm=NULL) {
if ( $this->RequestHandler->isAjax() ) {
$clients=$this->Client->find('list', array(
'conditions'=>array('LOWER(Client.lname) LIKE \''.$searchterm.'%\''),
'limit'=>500
));
$this->set('clients', $clients);
}
}
This is a function I use to submit forms in cakephp 3.x it uses sweet alerts but that can be changed to a normal alert. It's very variable simply put an action in your controller to catch the form submission. Also the location reload will reload the data to give the user immediate feedback. That can be taken out.
$('#myForm').submit(function(e) {
// Catch form submit
e.preventDefault();
$form = $(this);
// console.log($form);
// Get form data
$form_data = $form.serialize();
$form_action = $form.attr('action') + '.json';
// Do ajax post to cake add function instead
$.ajax({
type : "PUT",
url : $form_action,
data : $form_data,
success: function(data) {
swal({
title: "Updated!",
text: "Your entity was updated successfully",
type: "success"
},
function(){
location.reload(true);
});
}
});
});
What happens when we create setTimeout or Ajax call?
I have a problem with invoking autoplay in HTML5 player on iPad.
If I call thing like that:
function playItem()
{
var playerArea = $('#playerArea');
var flowplayerAjdi = getFlowplayerId();
playerArea.empty();
playerArea.append(createQualityChooserHTML()+'');
clipProperties.url = 'http://192.168.100.107:1935/ia/live/playlist.m3u8';
playLiveFlowplayer(flowplayerAjdi, getWowzaUrl('ia'), '', '', true, true);
}
everything works fine. But you can see that url is hardcoded - it has to be assigned by ajax call. So here is what I did:
function playItem()
{
$.ajax({
url : 'playVODServlet',
type : 'GET',
data : JSON.stringify(playItemParams),
timeout : 5000,
dataType : "json",
error : function(xhr, ajaxOptions, thrownError)
{
console.error("Error");
},
success : function(searchResult)
{
var playerArea = $('#playerArea');
var flowplayerAjdi = getFlowplayerId();
playerArea.empty();
playerArea.append(createQualityChooserHTML()+'');
clipProperties.url = searchResult.assetId;
playLiveFlowplayer(flowplayerAjdi, getWowzaUrl('ia'), '', '', true, true);
}
});
}
An how autostart doesn't work. So my question is: what could be the problem? It looks it is related with ajax call breaks normally code execution and creates error and success function. Same thing happens if I put player constructor to setTimeout.
Phones & tablets do not allow you to autoplay audio/video. This is precaution so the user doesn't get a hefty bill because your application automatically streamed video/audio.
You could try triggering a click event on the player once your page has loaded, but I doubt it'll work.
I'm making an online form for customers and now adding a submit button which saves the record in database. Is there any way i can submit data using AJAX ?
Take a look at jQuery. It will do the job for you.
Here is some sample jQuery code which may help:
$('.submitter').click(function() {
$.ajax({
'url' : 'url.php',
'type' : 'POST',
'data' : $('.myForm').serialize(), //Gets all of the values from a form
'success' : function(data) {
if (data == 'saved') {
alert('Form was saved!');
}
}
});
});
Hope that helps,
spryno724