I have rollup output of month-wise average sales of products in a quarter as shown below:
Rollup output:
Product Month Sales
------------------------------
Product1 MAY 101.27
Product2 MAY 5.47
Product1 JUN 1481.19
Product2 JUN 84.95
ALL QTR 836.44
I need final output in the following format:
Product1 Product2 AverageSales
May 101.27 1481.19 (null)
Jun 5.47 84.95 (null)
Jul 0 0 (null)
ALL (null) (null) 836.44
I tried to apply pivot on month but since month name is a dynamic value based on the quarter selected, I tried to pivot on the product:
select * from (rollup output)
PIVOT MIN(Sales) FOR Product IN ('Product1' AS Product1_sales, 'Product2' AS Product2_sales, 'ALL' AS Average Sales');
I received the following output:
MONTH Product1_sales Product2_sales Average Sales
MAY 5.47 (null) (null)
MAY (null) 101.27 (null)
JUN 84.95 (null) (null)
JUN (null) 1481.19 (null)
Qtr (null) (null) 836.44
However, I need data in the final format mentioned above. How can I achieve this?
Also, if data for a given month of the quarter is not available, I want to display its value as 0 (also shown in the final format above). How can I achieve that, considering that month name is dynamic?
Edit: I can pivot using product as well since I do not want xml output that comes out of dynamic pivot.
I'm not sure why it needs to be dynamic since the number of months is unlikely to change. Why not just:
select product
, nvl(jan,0) as jan
, nvl(feb,0) as feb
, nvl(mar,0) as mar
, nvl(apr,0) as apr
, nvl(may,0) as may
, nvl(jun,0) as jun
, nvl(jul,0) as jul
, nvl(aug,0) as aug
, nvl(sep,0) as sep
, nvl(oct,0) as oct
, nvl(nov,0) as nov
, nvl(dec,0) as dec
from rollup_output
pivot (min(sales) for (month) in
( 'JAN' as jan, 'FEB' as feb, 'MAR' as mar, 'APR' as apr, 'MAY' as may, 'JUN' as jun
, 'JUL' as jul, 'AUG' as aug, 'SEP' as sep, 'OCT' as oct, 'NOV' as nov, 'DEC' as dec)
);
SQL Fiddle
Calling
SELECT TO_DATE('Mon Sep 22 18:02:41 CDT 2014', 'DY MON DD HH24:MI:SS TZD YYYY') FROM Dual;
I get
ORA-01821: date format not recognized
01821. 00000 - "date format not recognized"
I put together the format string from these Oracle instructions. I tried both "TZR" and "TZD", neither works.
DY Abbreviated name of day.
MON Abbreviated name of month.
DD Day of month (1-31).
HH24 Hour of day (0-23).
MI Minute (0-59).
SS Second (0-59).
TZD Daylight savings information. For example, 'PST'
TZR Time zone region.
YYYY 4-digit year
Why is this not working?
TO_DATE doesn't support timezone.
I think you need to use to_timestamp_TZ() to do what you're after...
SELECT To_TimeStamp_TZ('Mon Sep 22 18:02:41 2014 CDT', 'DY MON DD HH24:MI:SS YYYY TZD')
FROM Dual;
Gives you something like (with my NLS paramaters)
22-SEP-14 06.02.41.000000000 PM AMERICA/CHICAGO
Also note the data type must be TIMESTAMP WITH TIME ZONE Data Type; or oracle just drops the timezone information w/o error.
https://docs.oracle.com/cd/E11882_01/server.112/e10729/ch4datetime.htm#NLSPG238
I am having an issue trying to convert multiple dates to one defined format. We are receiving the multiple dates from another DB source so I do not have control of the formatting until it reaches ours.
Here are all the formats:
YYYYMMDD
YYYY-MM-DD HH:MM:SS
MM/DD/YYYY
MM-DD-YYYY
Abrieviated Day Month DD HH:MM:SS TimeZone YYYY ('Thu Feb 02 20:49:59 MSK 2012')
Fully written Day, Month DD, YYYY HH:MM:SS AM/PM
My requirement is to set them all to the standard MM/DD/YYYY format or null. Any ideas?
Thank you.
You may define a transformation function, basically processing sequentially each format:
create or replace function translate_date(i_date_string VARCHAR2) return date as
begin
-- you may optimize to not to go in all blocks based on the string format
-- order the blocks on the expected frequency
begin
return to_date(i_date_string,'yyyymmdd');
EXCEPTION
WHEN OTHERS THEN NULL;
end;
begin
return to_date(i_date_string,'yyyy/mm/dd');
EXCEPTION
WHEN OTHERS THEN NULL;
end;
begin
return to_date(i_date_string,'yyyy-mm-dd');
EXCEPTION
WHEN OTHERS THEN NULL;
end;
begin
return to_date(i_date_string,'yyyy-mm-dd hh24:mi:ss');
EXCEPTION
WHEN OTHERS THEN NULL;
end;
begin
-- transform to local timestamp and than to date
return cast(cast(to_timestamp_tz(i_date_string,'dy month dd hh24:mi:ss tzr yyyy') as TIMESTAMP WITH LOCAL TIME ZONE) as date);
EXCEPTION
WHEN OTHERS THEN NULL;
end;
begin
return to_date(i_date_string,'dy, month dd, yyyy hh:mi:ss am');
EXCEPTION
WHEN OTHERS THEN NULL;
end;
return NULL;
end;
/
for example for sample data
TSTMP
------------------------
20150101
2015-01-01 23:59:59
2015/01/01
2015-01-01
Thu Feb 02 20:49:59 Europe/Moscow 2012
Thu, Feb 02, 2012 10:49:59 AM
Thu, Feb 02, 2012 10:49:59 PM
you get
TSTMP RESULT_DATE
------------------------------------------ -------------------
20150101 01.01.2015 00:00:00
2015-01-01 23:59:59 01.01.2015 23:59:59
2015/01/01 01.01.2015 00:00:00
2015-01-01 01.01.2015 00:00:00
Thu Feb 02 20:49:59 Europe/Moscow 2012 02.02.2012 17:49:59
Thu, Feb 02, 2012 10:49:59 AM 02.02.2012 10:49:59
Thu, Feb 02, 2012 10:49:59 PM 02.02.2012 22:49:59
Note that I skipped the case with time zone abbraviation (MSK), see possible solution in the answer from #Sentinel, but check Conversion of String with Abbreviated Timezone to Timestamp that this may be ambiguous.
I'd suggest using a case statement with regexp_like conditions to detect likely formats and return dates using the appropriate date mask in the then clauses e.g.:
with tz as (
SELECT distinct tzabbrev
, first_value(min(tzname)) over (partition by tzabbrev order by count(*) desc) tzname
FROM v$timezone_names
group by tzabbrev
, TZ_OFFSET(tzname)
), dta as (
select yt.install_date
, regexp_replace(yt.install_date,tzabbrev,tzname,1,1,'i') install_date2
from your_table yt
left join tz
on regexp_like(install_date, tz.TZABBREV,'i')
)
select install_date, install_date2
, to_timestamp_tz( install_date2
, case
when regexp_like(install_date2,'^[A-Z]{3,} [A-Z]{3,} [0-9]{1,2} [0-9]{1,2}(:[0-9]{2}){1,2} [[:print:]]{5,} [0-9]{2,4}','i') then 'DY MON DD HH24:MI:SS TZR YYYY'
when regexp_like(install_date2,'^[A-Z]{4,},? [A-Z]{3,},? [0-9]{1,2},? [0-9]{2,4}','i') then 'DAY MONTH DD YYYY'
when regexp_like(install_date2,'^[A-Z]{3},? [A-Z]{3,},? [0-9]{1,2},? [0-9]{2,4}','i') then 'DY MONTH DD YYYY'
when regexp_like(install_date2,'^[0-9]{1,2}[-/][0-9]{1,2}[-/]([0-9]{2}){1,2}') then 'MM-DD-RRRR'
when regexp_like(install_date2,'^[0-9]{1,2}[-/ ][A-Z]{3,}[-/ ]([0-9]{2}){1,2}','i') then 'DD-MON-RRRR'
when regexp_like(install_date2,'^[A-Z]{3,}[-/ ][0-9]{1,2},?[-/ ]([0-9]{2}){1,2}','i') then 'MON-DD-RRRR'
when regexp_like(install_date2,'^(19|20)[0-9]{6}') then 'RRRRMMDD'
when regexp_like(install_date2,'^[23][0-9]{5}') then 'DDMMRR'
when regexp_like(install_date2,'^[0-9]{6}') then 'MMDDRR'
when regexp_like(install_date2,'^[01][0-9]{7}') then 'MMDDRRRR'
when regexp_like(install_date2,'^[23][0-9]{7}') then 'DDMMRRRR'
ELSE NULL
end
||case
when regexp_like(install_date2, '[0-9]{1,2}(:[0-9]{2}){1,2}$') then ' HH24:MI:SS'
when regexp_like(install_date2, '[0-9]{1,2}(:[0-9]{2}){1,2} ?(am|pm)$','i') then ' HH:MI:SS AM'
else null
end
)
Install_Time_Stamp
from dta;
I had issues with the time zone abbreviations so I added a step to replace them with time zone regions first.
The function can be simplified a little bit as to_date tolerates minor deviations (different separators, missing separators, missing time components, 2/4-digit year). For instance to_date(:str,'rrrr-mm-dd hh24:mi:ss') will cover
2020/09/18 01.02
2020.09.18 01
20200918010203
2020-0901
202009-01
20/09/18
To_timestamp_tz will also tolerate missing milliseconds and time zone (including missing TZ elements TZM and TZD).
So we basically need to take care of major variations only like hh24/hh, mm/mon, elements order, "T" separator in ISO 8601 (2020-01-01T01:02:03), TZ designators (UTC offset TZH:TZM / region name TZR), and day of week (DY).
In DB, date is stored in number format (Mon Jul 07 14:41:40 IST 2014
is stored as 1404724300383), I need a query to convert number to date to compare with the sysdate, or from sysdate to number format. How can we convert the date to number or vice versa?
Assume the number is a sequencial one based on specific rule. You need to know the rule first.
Get the rule
a) 07 July 2014 = 1404724300383; 07 July 2013 = ? (assume 1404700000000)
b) Assume value 0 mapping to one day, Day1
c) two formulas 1404724300383 = (07 July 2014 - Day1) * RULE; 1404700000000 = (07 July 2013 - Day1)*Rule;
Then, Rule = 24300383/365 and Day 1 = 1 Jan 1900 + 41285/(1404724300383/1404700000000*41460/((1404724300383/1404700000000)-1))
where 41825 is the days between 07 July 2014 and 1 Jan 1900)
41460 is the days between 07 July 2013 and 1 Jan 1900)
Use the Rule and Day1 to get what you need
select Day1 + [query column]/Rule from Your_Table;
I have a field containing 201402, 201404, here I want to convert 02 to Feb and 04 to April. Is it possible to do that? This field contains entries of all months. Please help.
There is a lot that you can do in terms of datetime format models within Oracle. A simple example below (replace the string literal within the TO_DATE(...) with your field if it is a string or replace the entire TO_DATE with your field if it is already of data type DATE):
SELECT TO_CHAR(TO_DATE('201402','YYYYMM'),'YYYY-MONTH') FROM DUAL;
SELECT TO_CHAR(TO_DATE('201404','YYYYMM'),'YYYY-MONTH') FROM DUAL;