laravel about inner join and subquery - laravel

ok, now ,I want get sql just like:
select field1,field2,field3 from orders
inner join
(select id from orders where field4=3 limit 1000, 20)
as temp using(id)
how can I get this by laravel 5.1?
er, sorry I poor in english. What I mean is I want get the native sql like that , and now I don't know what can I do with laravel DB or ORM. I create a model Order corresponding to the table orders.
thank you ~

Although it is not a good way to do it because laravel supports inner joins in query builder. You can do it like this:
DB::select(DB::raw(" select field1,field2,field3 from orders
inner join
(select id from orders where field4=3 limit 1000, 20)
as temp using(id)
"))->get();

Use the following code
DB::select(DB::raw(" select field1,field2,field3 from orders
inner join
(select id from orders where field4=3 limit 1000, 20)
as temp using(id)
"))->get();

Related

Oracle Performance issues on using subquery in an "In" orperator

I have two query that looks close to the same but Oracle have very different performance.
Query A
Create Table T1 as Select * from FinalView1 where CustomerID in ('A0000001','A000002')
Query B
Create Table T1 as Select * from FinalView1 where CustomerID in (select distinct CustomerID from CriteriaTable)
The CriteriaTable have 800 rows but all belongs to Customer ID 'A0000001' and 'A000002'.
This means the subquery: "select distinct CustomerID from CriteriaTable" also only returns the same two elements('A0000001','A000002') as manually entered in query A
Following is the query under the FinalView1
create or replace view FinalView1_20200716 as
select
Customer_ID,
<Some columns>
from
Table1_20200716 T1
INNER join Table2_20200716 T2 on
T1.Invoice_number = T2.Invoice_number
and
T1.line_id = T2.line_id
left join Table3_20200716 T3 on
T3.id = T1.Customer_ID
left join Table4_20200716 T4 on
T4.Shipping_ID = T1.Shipping_ID
left join Table5_20200716 Table5 on
Table5.Invoice_ID = T1.Invoice_ID
left join Table6_20200716 T6 on
T6.Shipping_ID = T4.Shipping_ID
left join First_Order first on
first.Shipping_ID = T1.Shipping_ID
;
Table1_20200716,Table2_20200716,Table3_20200716,Table4_20200716,Table5_20200716,Table6_20200716 are views to the corresponding table with temporal validity feature. For example
The query under Table1_20200716
Create or replace view Table1_20200716 as
select
*
from Table1 as for period of to_date('20200716,'yyyymmdd')
However table "First_Order" is just a normal table as
Following is the performance for both queries (According to explain plan):
Query A:
Cardinality: 102
Cost : 204
Total Runtime: 5 secs max
Query B:
Cardinality:27921981
Cost: 14846
Total Runtime:20 mins until user cancelled
All tables are indexed using those columns that used to join against other tables in the FinalView1. According to the explain plan, they have all been used except for the FirstOrder table.
Query A used uniquue index on the FirstOrder Table while Query B performed a full scan.
For query B, I was expecting the Oracle will firstly query the sub-query get the result into the in operator, before executing the main query and therefore should only have minor impact to the performance.
Thanks in advance!
As mentioned from my comment 2 days ago. Someone have actually posted the solution and then have it removed while the answer actually work. After waiting for 2 days the So I designed to post that solution.
That solution suggested that the performance was slow down by the "in" operator. and suggested me to replace it with an inner join
Create Table T1 as
Select
FV.*
from
FinalView1 FV
inner join (
select distinct
CustomerID
from
CriteriaTable
) CT on CT.customerid = FV.customerID;
Result from explain plan was worse then before:
Cardinality:28364465 (from 27921981)
Cost: 15060 (from 14846)
However, it only takes 17 secs. Which is very good!

Using an alias in a select statement in a join query

I am very new at using Oracle (in the class now). I have a problem with the query I am trying to run. I have researched a lot of other answers on this site and none of them seem to apply directly to my problem so the solutions aren't working.
I need to find the total amount spent on lunches by each employee.
Show first_name, last_name, credit_limit, and total_price_spent in your results.
Order the answer by total_price_spent in descending order. Only show the employees who spent more than their credit limit.
I figured out how to do everything but the part about showing only the employees who spent more than their credit limit. I tried to use a select statement at the end but discovered that I can't use an alias in a select statement so I don't really know where to go from here. Any help would be appreciated. This is what I have so far.
select a.first_name, a.last_name, credit_limit, sum(c.quantity * d.price) as total_price_spent
from l_employees a join l_lunches b on a.employee_id = b.employee_id join l_lunch_items c on b.lunch_id = c.lunch_id join l_foods d on c.supplier_id = d.supplier_id and c.product_code = d.product_code
group by a.first_name, a.last_name, a.credit_limit
order by total_price_spent desc;
As Mike said : Add HAVING
select a.first_name, a.last_name, credit_limit, sum(c.quantity * d.price) as total_price_spent
from l_employees a join l_lunches b on a.employee_id = b.employee_id join l_lunch_items c on b.lunch_id = c.lunch_id join l_foods d on c.supplier_id = d.supplier_id and c.product_code = d.product_code
group by a.first_name, a.last_name, a.credit_limit
having sum(c.quantity * d.price) > credit_limit
order by total_price_spent desc;
I think what you're looking for is a HAVING clause. It's like a WHERE, but is used when you're using group by. You want to drop it in between the group by and order by. Something like 'HAVING total > a.credit_limit' should work. If using the alias 'total' doesn't work (haven't tested this), you might have to do 'sum(c.quantity * d.price)' again in the HAVING clause instead of using total, so HAVING sum(c.quantity * d.price) > a.credit_limit.

Why is "group by" giving only one column as output?

I have a table something like this:
ID|Value
01|1
02|4
03|12
01|5
02|14
03|22
01|9
02|32
02|62
01|13
03|92
I want to know how much progress have each id made (from initial or minimal value)
so in sybase I can type:
select ID, (value-min(value)) from table group by id;
ID|Value
01|0
01|4
01|8
01|12
02|0
02|10
02|28
02|58
03|0
03|10
03|80
But monetdb does not support this (I am not sure may be cz it uses SQL'99).
Group by only gives one column or may be average of other values but not the desired result.
Are there any alternative to group by in monetdb?
You can achieve this with a self join. The idea is that you build a subselect that gives you the minimum value for each id, and then join that to the original table by id.
SELECT a.id, a.value-b.min_value
FROM "table" a INNER JOIN
(SELECT id, MIN(value) AS min_value FROM "table" GROUP BY id) AS b
ON a.id = b.id;

Oracle : How to use if then in a select statement

select ma.TITLE,ma.ID as aid,ur.USER_ID
from LEO_MENU_ACTIVITY_RELATION mr
inner join LEO_MENU_MASTER mm on mm.ID=mr.MENU_ID
INNER join LEO_MENUACTIVITY ma on mr.ACTIVITY_ID=ma.ID
LEFT OUTER JOIN LEO_USER_RIGHTS ur on ma.ID=ur.MENU_RELATION_ID and ur.MENU_ID=mm.ID and ur.USER_ID='141'
where mm.ID='1'
UNION (SELECT
'List' as TITLE,
1 as ID,
case (WHEN ur.MENU_RELATION_ID=1 THEN NULL ELSE USER_ID END)as USER_ID
from
LEO_USER_RIGHTS)
In the UNION i want perform a conditional select like if ur.MENU_RELATION_ID=1 then the USER_ID should be selected as NULL otherwise the the original value from the 'LEO_USER_RIGHTS' table must be retrieved.
How can i do this ? Please help
Krishnik
If you want to combine in a UNION something based on the first table I think you can only do it by repeating the whole thing like this:
select ma.TITLE,ma.ID as aid,ur.USER_ID
from LEO_MENU_ACTIVITY_RELATION mr
inner join LEO_MENU_MASTER mm on mm.ID=mr.MENU_ID
INNER join LEO_MENUACTIVITY ma on mr.ACTIVITY_ID=ma.ID
LEFT OUTER JOIN LEO_USER_RIGHTS ur on ma.ID=ur.MENU_RELATION_ID and ur.MENU_ID=mm.ID and ur.USER_ID='141'
where mm.ID='1'
UNION (SELECT
'List' as TITLE,
1 as ID,
case (WHEN ur.MENU_RELATION_ID=1 THEN NULL ELSE USER_ID END)as USER_ID
from
LEO_MENU_ACTIVITY_RELATION mr
inner join LEO_MENU_MASTER mm on mm.ID=mr.MENU_ID
INNER join LEO_MENUACTIVITY ma on mr.ACTIVITY_ID=ma.ID
LEFT OUTER JOIN LEO_USER_RIGHTS ur on ma.ID=ur.MENU_RELATION_ID and ur.MENU_ID=mm.ID and ur.USER_ID='141'
where mm.ID='1'
)
If this is used often I would create a view to avoid duplicate code. In ORACLE (I do not know for other SQL dialects) there is a WITH statement enables you to make a sort of "temporary view".

How can i perform this query in NHibernate for getting child count

select name,
(select count(*) from products where products.category_Id=categories.Id) as productCount
from categories
session.CreateCriteria<Category>()
but whats next?
i don't even know how to search it in Google?
think of your query like
SELECT categories.Id, count(categories.Id)
FROM categories inner join products on products.category_Id=categories.Id
group by categories.Id
I think they will produce the same result.
search google for
nhibernate criteria join
and
CreateAlias

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