Parameter from URL into shell script - bash

How is it possible to get an URL parameter like /?photo=1.png into a shell script as a variable, running into a cgi-bin container on apache?
Edit
Iam generating a list of all files in a directory.
#!/bin/bash
echo "Content-type: text/html"
echo
for file in /var/www/html/export/tui/*;
do
echo "<a href='/cgi-bin/test.cgi?file="${file: -27}"'>"${file: -27}"</a><br>";
done;
Now, i want to give the file name as a parameter into a second script, who needs this for reading it.

I found a solution who take the URL parameter and give it into my script
#!/bin/bash
echo "Content-type: text/html"
echo
function cgi_decodevar()
{
[ $# -ne 1 ] && return
local v t h
t="${1//+/ }%%"
while [ ${#t} -gt 0 -a "${t}" != "%" ]; do
v="${v}${t%%\%*}" # digest up to the first %
t="${t#*%}" # remove digested part
if [ ${#t} -gt 0 -a "${t}" != "%" ]; then
h=${t:0:2}
t="${t:2}"
v="${v}"`echo -e \\\\x${h}`
fi
done
echo "${v}"
return
}
function cgi_getvars()
{
[ $# -lt 2 ] && return
local q p k v s
case $1 in
GET)
[ ! -z "${QUERY_STRING}" ] && q="${QUERY_STRING}&"
;;
POST)
cgi_get_POST_vars
[ ! -z "${QUERY_STRING_POST}" ] && q="${QUERY_STRING_POST}&"
;;
BOTH)
[ ! -z "${QUERY_STRING}" ] && q="${QUERY_STRING}&"
cgi_get_POST_vars
[ ! -z "${QUERY_STRING_POST}" ] && q="${q}${QUERY_STRING_POST}&"
;;
esac
shift
s=" $* "
while [ ! -z "$q" ]; do
p="${q%%&*}"
k="${p%%=*}"
v="${p#*=}"
q="${q#$p&*}"
[ "$1" = "ALL" -o "${s/ $k /}" != "$s" ] && \
export "$k"="`cgi_decodevar \"$v\"`"
done
return
}
cgi_getvars BOTH ALL
echo $foo

Related

shell list All Xcode xcworkspace and xcodeproj

I want to list project directory all xcworkspace and xcodeproj file.
And I write code below
#!/bin/bash
workspaceFile="xcworkspace"
projectFile="xcodeproj"
#listFiles
path=$(pwd)
fileList=()
walk_dir () {
for name in "$path"/*; do
if [[ -d "$name" && ("${name##*.}" != ${projectFile} || "${name##*.}" != ${workspaceFile}) ]]; then
path=$name
walk_dir "$name"
else
if [ "${name##*.}"x = ${workspaceFile}x ] || [ "${name##*.}"x = ${projectFile}x ];then
fileList+=($name)
fi
fi
done
}
walk_dir
for name in ${fileList[#]}; do
echo $name
done
It did not work.
But If change the condition, like below
if [[ -d "$name" && ("${name##*.}" != ${workspaceFile}) ]]; then
path=$name
walk_dir "$name"
else
if [ "${name##*.}"x = ${workspaceFile}x ] || [ "${name##*.}"x = ${projectFile}x ];then
fileList+=($name)
fi
fi
or
if [[ -d "$name" && ("${name##*.}" != ${projectFile}) ]]; then
path=$name
walk_dir "$name"
else
if [ "${name##*.}"x = ${workspaceFile}x ] || [ "${name##*.}"x = ${projectFile}x ];then
fileList+=($name)
fi
fi
It works also.
I want to keep filter xcworkspace and xcodeproj.
Someone can help me?
Finaly, I found result by myself.
#!/bin/bash
workspaceFile="xcworkspace"
projectFile="xcodeproj"
path=$1
fileList=()
projectList () {
for name in "$path"/*; do
if [ -d "$name" ] && [ "${name##*.}"x = ${workspaceFile}x ]; then
fileList+=(${name})
elif [ -d "$name" ] && [ "${name##*.}"x = ${projectFile}x ]; then
fileList+=(${name})
elif [ -d "$name" ]; then
path=$name
projectList
fi
done
}
projectList
for name in ${fileList[#]}; do
echo "xcode project: $name"
done

Bash script - Using spaces as string

I'm trying to build a really simple TODO list with a bash script. It should allow user to add and remove a task and also see the entire list.
I've done it with the following script. But I've issues allowing a given task to take a whitespace as a string. For instance, if I'm adding a task with the command: ./programme_stack.sh add 1 start projet n1, it will only add a task with "start".
I've read a couple of things online, I know, I should double quote the variables but after trying this, it doesn't work. I must be missing something on the road.
Here is my script:
#!/bin/bash
TACHES=$HOME/.todo_list
# functions
function remove() {
res_remove=$(sed -n "$1p" $TACHES)
sed -i "$1d" $TACHES
}
function list() {
nl $TACHES
}
function add() {
if [ ""$(($(wc -l $TACHES | cut -d " " -f 1) + 1))"" == "$1" ]
then
echo "- $2" >> $TACHES
else
sed -i "$1i - $2" $TACHES
fi
echo "Task \"$2\" has been add to the index $1"
}
function isNumber() {
re='^[0-9]+$'
if ! [[ $# =~ $re ]] ; then
res_isNumber=true
else
res_isNumber=false
fi
}
# application
case $1 in
list)
list
;;
done)
shift
isNumber $#
if ! [[ "$res_isNumber" = false ]] ; then
echo "done must be followed by an index number"
else
nb_taches=$(wc -l $TACHES | cut -d " " -f 1)
if [ "$1" -ge 1 ] && [ "$1" -le $nb_taches ]; then
remove $1
echo "Well done! Task $i ($res_remove) is completed"
else
echo "this task doesn't exists"
fi
fi
;;
add)
shift
isNumber $1
if ! [[ "$res_isNumber" = false ]] ; then
echo "add must be followed by an index number"
else
index_max=$(($(wc -l $TACHES | cut -d " " -f 1) + 1))
if [ "$1" -ge 1 ] && [ "$1" -le $index_max ]; then
add $1 $2
else
echo "Idex must be between 1 and $index_max"
fi
fi
;;
*)
echo "./programme_stack.sh (list|add|done) [args]"
;;
esac
Can you guys see what I'm missing?
Many thanks!!
To get the script to support embedded spaces, 2 changes are needed
1) Accept embedded space - either
1A) Pass in the task name in quote script add nnn "say hello", OR
1B) Concatenate all the input parameters into single string.
2) Quote the task name to prevent it from being broken into individual words
In the code, implement 1B and 2
add)
...
if [ "$1" -ge 1 ] && [ "$1" -le $index_max ]; then
num=$1
shift
# Combine all remaining arguments
todo="$#"
add "$num" "$todo"
...

How to use elif with && and -o in a bash script properly

Bash version 4.4.20
Ubuntu 16.04
I need to compare time and extensions for a particular project I have. Below is something similar to what I am trying to do but the error is the same. I am not sure where exactly the error is as shellcheck is not producing one.
#!/bin/bash
#
while read -r filename; do
extension="${filename##*.}"
if [ "$extension" == "zip" ] && [ "$filename" == "one.zip" ]; then
echo "Filename is $filename"
elif [ "$extension" == "zip" ] && [ "$filename" == "file_1.zip" ] -o [ "$filename" == "file_2.zip" ] -o [ "$filename" == "file_3.zip" ]; then
echo "Filename is $filename"
elif [ "$extension" == "csv" ] && [ "$filename" == "two.csv" ]; then
echo "Filename is $filename"
else
echo "Filename is $filename"
fi
done<fileList.txt
Error:
Filename is one.zip
check.sh: line 8: [: too many arguments
Filename is file_1.zip
check.sh: line 8: [: too many arguments
Filename is file_2.zip
check.sh: line 8: [: too many arguments
Filename is file_3.zip
Filename is two.csv
Filename is three.sql
Use pattern matching to your advantage:
while IFS= read -r filename; do
if [[ "$filename" = one.zip ]; then
echo "Filename is $filename"
elif [[ "$filename" = file_[123].zip ]; then
echo "Filename is $filename"
elif [[ "$filename" = two.csv ]; then
echo "Filename is $filename"
else
echo "Filename is $filename"
fi
done < fileList.txt
A case statement will work in any POSIX shell, not just a shell that supports a bash-like [[ ... ]] command.
while IFS= read -r filename; do
case $filename in
one.zip) echo "Filename is $filename" ;;
file_[123].zip) echo "..." ;;
two.csv) echo "..." ;;
*) echo "..." ;;
esac
done
To match a range of years(?), you can use
case $value in
200[0-9]|201[0-9]|202[0-1]) echo "Year between 2000 and 2021" ;;
esac
You can't do that as simply with [[ value = ... ]], since the | is part of the case statement's syntax, not an alternation operator in the pattern. Instead, you would need multiple match operators:
if [[ $value = 200[0-9] || $value = 201[0-19] || $value = 202[0-1] ]]; then
Here an explanation for why you get this error, as you get already good answers on how to do it correctly:
Note that the command [ is equivalent to test, hence your line 8 in effect (also removing unnecessary quotes) contains:
elif test "$extension" == zip ] && test "$filename" == file_1.zip ] -o [ "$filename" == file_2.zip ] -o [ "$filename" == file_3.zip ]
From the test man-page, we can see that the closing ] is optional, but if it is present, it terminates the expression to be tested.
The first test, which is just
test "$extension" == "zip" ]
is fine in this respect, but the second one starts with
test "$filename" == file_1.zip ] -o [ ...
Hence, when parsing the arguments, test encounters a ] and knows that this is the terminator for the arguments, but then finds another argument (-o), and doesn't know what to do with it. Hence it complains that it has got too many arguments
I have updated the syntax to what I think is the modern bash idioms. The script now works. Please correct me if I missed something else :
#!/bin/bash
#
while read -r filename
do
extension="${filename##*.}"
if [[ "$extension" = "zip" && "$filename" = "one.zip" ]]
then
echo "Filename is $filename"
elif [[ "$extension" = "zip" && "$filename" = "file_1.zip" ]] \
|| [[ "$filename" = "file_2.zip" ]] \
|| [[ "$filename" = "file_3.zip" ]]
then
echo "Filename is $filename"
elif [[ "$extension" = "csv" && "$filename" = "two.csv" ]]
then
echo "Filename is $filename"
else
echo "Filename is $filename"
fi
done < fileList.txt
Regards!

Chosing "input" in an AND (&&) and OR (||) list of commands

I have to find a way to have my script read from one of these three options:
a file argument
standard input
a previously established environment variable
Here's what I currently have:
#!/bin/bash
key=$1
[ $# -ge 1 -a -f "$2" ] && input="$2" || [ -f "$INPUT" ] && input="$INPUT" || input="-"
echo $input
Only the environment variable refuses to work, the rest works fine.
I've tried using the export INPUT="pathnametofile" before but it doesn't make any difference, I end up with the shell asking me to enter info as if I called on cat.
The problem in your script
Your attemp is not working due to the way the shell processes a Lists of Commands:
‘&&’ and ‘||’ have equal precedence.
AND and OR lists are executed with left associativity.
Your sentence:
[ $# -ge 1 -a -f "$2" ] && input="$2" || [ -f "$INPUT" ] && input="$INPUT" || input="-"
does the same as follows:
[ $# -ge 1 -a -f "$2" ] && input="$2"
[ $? -eq 0 ] || [ -f "$INPUT" ]
[ $? -eq 0 ] && input="$INPUT"
[ $? -eq 0 ] || input="-"
Now yo may see why your unexpected behaviour.
A better attempt grouping commands
{ [ $# -ge 1 -a -f "$2" ] && input="$2"; } || { [ -f "$INPUT" ] && input="$INPUT"; } || input="-"
Now, due to precedence, the first group is not needed at all:
[ $# -ge 1 -a -f "$2" ] && input="$2" || { [ -f "$INPUT" ] && input="$INPUT"; } || input="-"
Furthermore, unless you have set the positional parameters by hand, you can remove the first check (after all, if $2 is emtpy, -f "" fails the same).
[ -f "$2" ] && input="$2" || { [ -f "$INPUT" ] && input="$INPUT"; } || input="-"
An alternative with the if conditional construct
if [ -f "$2" ]; then
input=$2
elif [ -f "$INPUT" ]; then
input=$INPUT
fi
echo "${input:=-}"
untested, but you'll probably have better luck with if commands, and test that the variable is not empty:
if [ $# -ge 1 -a -f "$2" ]; then
input="$2"
elif [ -n "$INPUT" -a -f "$INPUT" ]; then
input="$INPUT"
else
input="-"
fi

Test multiple file conditions in one swoop (BASH)?

Often when writing for the bash shell, one needs to test if a file (or Directory) exists (or doesn't exist) and take appropriate action. Most common amongst these test are...
-e - file exists, -f - file is a regular file (not a directory or device file), -s - file is not zero size, -d - file is a directory, -r - file has read permission, -w - file has write, or -x execute permission (for the user running the test)
This is easily confirmed as demonstrated on this user-writable directory....
#/bin/bash
if [ -f "/Library/Application Support" ]; then
echo 'YES SIR -f is fine'
else echo 'no -f for you'
fi
if [ -w "/Library/Application Support" ]; then
echo 'YES SIR -w is fine'
else echo 'no -w for you'
fi
if [ -d "/Library/Application Support" ]; then
echo 'YES SIR -d is fine'
else echo 'no -d for you'
fi
➝ no -f for you ✓
➝ YES SIR -w is fine ✓
➝ YES SIR -d is fine ✓
My question, although seemingly obvious, and unlikely to be impossible - is how to simply combine these tests, without having to perform them separately for each condition... Unfortunately...
if [ -wd "/Library/Application Support" ]
▶ -wd: unary operator expected
if [ -w | -d "/Library/Application Support" ]
▶ [: missing `]'
▶ -d: command not found
if [ -w [ -d "/Library.... ]] & if [ -w && -d "/Library.... ]
▶ [: missing `]'
➝ no -wd for you ✖
➝ no -w | -d for you ✖
➝ no [ -w [ -d .. ]] for you ✖
➝ no -w && -d for you ✖
What am I missing here?
You can use logical operators to multiple conditions, e.g. -a for AND:
MYFILE=/tmp/data.bin
if [ -f "$MYFILE" -a -r "$MYFILE" -a -w "$MYFILE" ]; then
#do stuff
fi
unset MYFILE
Of course, you need to use AND somehow as Kerrek(+1) and Ben(+1) pointed it out. You can do in in few different ways. Here is an ala-microbenchmark results for few methods:
Most portable and readable way:
$ time for i in $(seq 100000); do [ 1 = 1 ] && [ 2 = 2 ] && [ 3 = 3 ]; done
real 0m2.583s
still portable, less readable, faster:
$ time for i in $(seq 100000); do [ 1 = 1 -a 2 = 2 -a 3 = 3 ]; done
real 0m1.681s
bashism, but readable and faster
$ time for i in $(seq 100000); do [[ 1 = 1 ]] && [[ 2 = 2 ]] && [[ 3 = 3 ]]; done
real 0m1.285s
bashism, but quite readable, and fastest.
$ time for i in $(seq 100000); do [[ 1 = 1 && 2 = 2 && 3 = 3 ]]; done
real 0m0.934s
Note, that in bash, "[" is a builtin, so bash is using internal command not a symlink to /usr/bin/test exacutable. The "[[" is a bash keyword. So the slowest possible way will be:
time for i in $(seq 100000); do /usr/bin/\[ 1 = 1 ] && /usr/bin/\[ 2 = 2 ] && /usr/bin/\[ 3 = 3 ]; done
real 14m8.678s
You want -a as in -f foo -a -d foo (actually that test would be false, but you get the idea).
You were close with & you just needed && as in [ -f foo ] && [ -d foo ] although that runs multiple commands rather than one.
Here is a manual page for test which is the command that [ is a link to. Modern implementations of test have a lot more features (along with the shell-builtin version [[ which is documented in your shell's manpage).
check-file(){
while [[ ${#} -gt 0 ]]; do
case $1 in
fxrsw) [[ -f "$2" && -x "$2" && -r "$2" && -s "$2" && -w "$2" ]] || return 1 ;;
fxrs) [[ -f "$2" && -x "$2" && -r "$2" && -s "$2" ]] || return 1 ;;
fxr) [[ -f "$2" && -x "$2" && -r "$2" ]] || return 1 ;;
fr) [[ -f "$2" && -r "$2" ]] || return 1 ;;
fx) [[ -f "$2" && -x "$2" ]] || return 1 ;;
fe) [[ -f "$2" && -e "$2" ]] || return 1 ;;
hf) [[ -h "$2" && -f "$2" ]] || return 1 ;;
*) [[ -e "$1" ]] || return 1 ;;
esac
shift
done
}
check-file fxr "/path/file" && echo "is valid"
check-file hf "/path/folder/symlink" || { echo "Fatal error cant validate symlink"; exit 1; }
check-file fe "file.txt" || touch "file.txt" && ln -s "${HOME}/file.txt" "/docs/file.txt" && check-file hf "/docs/file.txt" || exit 1
if check-file fxrsw "${HOME}"; then
echo "Your home is your home from the looks of it."
else
echo "You infected your own home."
fi
Why not write a function to do it?
check_file () {
local FLAGS=$1
local PATH=$2
if [ -z "$PATH" ] ; then
if [ -z "$FLAGS" ] ; then
echo "check_file: must specify at least a path" >&2
exit 1
fi
PATH=$FLAGS
FLAGS=-e
fi
FLAGS=${FLAGS#-}
while [ -n "$FLAGS" ] ; do
local FLAG=`printf "%c" "$FLAGS"`
if [ ! -$FLAG $PATH ] ; then false; return; fi
FLAGS=${FLAGS#?}
done
true
}
Then just use it like:
for path in / /etc /etc/passwd /bin/bash
{
if check_file -dx $path ; then
echo "$path is a directory and executable"
else
echo "$path is not a directory or not executable"
fi
}
And you should get:
/ is a directory and executable
/etc is a directory and executable
/etc/passwd is not a directory or not executable
/bin/bash is not a directory or not executable
This seems to work (notice the double brackets):
#!/bin/bash
if [[ -fwd "/Library/Application Support" ]]
then
echo 'YES SIR -f -w -d are fine'
else
echo 'no -f or -w or -d for you'
fi

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