I have a menu partial, that includes a input search bar. But i don't want the search bar to be visibel on all pages, only for two specific uri´s. Is there a way to remove that include in blade?
Currently it looks like this:
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#include('partials._search')
I was thinking something like
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#if($url)
#include('partials._search')
#endif
Use is() method:
#if (request()->is($url))
#include('partials._search')
#endif
Or if you know route name:
#if (request()->route()->getName() === $routeName)
#include('partials._search')
#endif
To retrieve URL from the blade template, use {{ Request::url() }}.
This will output something like http://example.dev/articles
To retrieve path, use {{ Request::path() }}
Using the above example, this will output articles.
Related
I'm trying to show some content depending on the url on ablade template but it's not working.
#if(Request::url() === 'myurl')
// code
#endif
I cannot see Request::url() content I tried wir dd, #dd, {{Request::url() }}, but always I get the literal text.
what I have to do?
Instead of matching urls, use request pattern matching. In blade you can do.
#if(request()->is('user/yourroute'))
// code
#endif
#if(Request::is(''))
// code
#endif
Theres any Solution to hide an Code in Laravel for one Page?
With this i can display only one requested page ,Example:
#if (Request::path() == 'message/send')
#endif
Theres an opposite to hide an code for an path?
I have an URL also with after send an Username:
message/send/username
I have try: #if (Request::path() == 'message/send/') and #if (Request::path() == 'message/send/{{$username}}') but dont work.
Thanks
Use request()->is() for this:
#if (request()->is('message/send*'))
you can use segment method in laravel
#php $member = Request::segment(1);#endphp
#if($member =='member')
<style type="text/css"> .test{color: #1a393a !important;</style>
#endif
#endif
Here my first segment is member
The controller is the proper place to handle request specifics. However, if you still wish to do this in your blade view:
#if (Request::path() == 'message/send/' . $username)
You do not use template syntax {{ }} inside expressions. When the blade template is compiled, #if (expr) is converted to <?php if (expr): ?>, so standard PHP applies within the expression.
Route path comparison doesn't work that way. For example:
message/send/jwz104 will never be equal to message/send/{{$username}}
You could compare the route name:
#if(\Request::route()->getName() == 'message.send')
#endif
This also isn't a nice solution. You should handle this in your controller or by view composers.
with core php-
#if (strpos($_SERVER['REQUEST_URI'], "message/send") !== false)
#endif
I have a simple problem, basically I am getting name of the website from database and create a link according to it's name. it looks like:
#foreach ($websites as $website)
<a class="websites" href=" {{ asset ($website->name )}}"> {{ asset ($website->name )}}
</a>
#endforeach
Which gives for example: http://localhost/name
Howver links needs to be like this:
http://localhost/website/name how can I add /website into my URL using blade template in laravel?
Try this:
{{ url('website/' . $website->name) }}
This have some improvement on #Laran answer regarding best practices.
You would better use url parameters instead of concatenating the $name parameter
{{ url('website', [$name]) }}
And using named routes will be better to decouple the routing from the views.
// routes/web.php
Route::get('website')->name('website');
and write inside your {{ route('website', [$name]) }}
I want to check for $house->category.
Depending on the category i want to send parameters with the #extends() functions.
I can't get it to work. When I use something like:
#if($house->category == 1)
#extends('templates.main')
#else
#extends('templates.main', ['logo' => 'img/logo/logo_red_white_text.png', 'favicon' => 'img/favicon/favicon_red.ico'])
#endif
The template is injected twice.
use "#include" instead of extends, and if it's being injected two times you can prevent that by handling that logic on the controller, make a method "checkHouseCategory" or something like that, to check if $house->category == 1, then just send a boolean to the template.
The problem is that you cannot pass parameters in #extends function.
What you can do is to move the view partial to separated file and then #include it in i.e. main file with the above condition. So this will looks like:
Partial view with #extends I will name: example.blade.php
Then in the main view partial:
#if($house->category == 1)
#include('example')
#else
#extends('example', ['logo' => 'img/logo/logo_red_white_text.png', 'favicon' => 'img/favicon/favicon_red.ico'])
#endif
I have database, with columns image and alttag. I want to use them in laravel blade view. I try something like this:
{{ HTML::image('images/{{ $item->image }}', $alt="{{ $item->alttag }}") }}
But syntax isn't correct. If i just echo image and alttag like this:
<h1>{{ $item->alttag }}</h1>
then they are correct. I wonder what is wrong in my code.
You used blade syntax in a PHP string. Watch the compiled blade templates to see where you did go wrong.
In short. Try this:
{{ HTML::image('images/'. $item->image, $alt = $item->alttag) }}
or equally short:
{{ HTML::image("images/{$item->image}", $alt = $item->alttag) }}