I want to handle all the non available routes and redirect them to my 503.blade view. i.e whenever user enters URL like //localhost:8000/adbkjabd or //localhost:8000/anything-they-like i want to handle them and show them 503 view. In my render() function. It is not redirecting me to the 503 page and still says in the same page with errors.
public function render($request, Exception $e)
{
if ($e instanceof NotFoundHttpException) {
// normal 503 view page feedback
return response()->view('errors.503', [], 404);
}
return parent::render($request, $e);
}
Am i having a wrong understanding of this or am i making any logical errors ?
Related
Since I started logging exceptions on a production site I'm noticing a lot of them, especially 404s, more than I would expect for a site with barely any traffic, and I'd like to get to the bottom of whether they're genuine users or just bots. To help with this, I want to capture the URL that the user was trying to visit before being redirected to the 404 route, so I can keep track of which non-existent routes are being mistakenly hit. I think I'm correct in assuming this URL should be available in the request, and that I just need to store the request and pass it through to the exception.
What's the best way to do this in Laravel 8 onwards?
Catch 404 exceptions in Handler(App\Exceptions\Handler).
If you see Rendering Exceptions
By default, the Laravel exception handler will convert exceptions into
an HTTP response for you. However, you are free to register a custom
rendering closure for exceptions of a given type. You may accomplish
this via the renderable method of your exception handler.
The closure passed to the renderable method should return an instance
of Illuminate\Http\Response, which may be generated via the response
helper. Laravel will deduce what type of exception the closure renders
by examining the type-hint of the closure:
so in the register method,call renderable
public function register()
{
$this->renderable(function (NotFoundHttpException $e, $request) {
Log::alert("404",[
"fullUrl"=>$request->fullUrl(),
"path"=>$request->path(),
"message" =>$e->getMessage()
]);
return response()->view('errors.404', [], $e->getStatusCode());
});
}
Also, don't forget to import and use
Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
EDIT: just a few hours of using this solution in production, with the benefit of the newly-added request URLs, has confirmed for me just how many of these HTTP 4xx errors are junk - mostly automated bots and maybe a few script kiddies trying common routes. For this reason I've added some logic to ignore 404 and 405 errors, and may still add others that mostly contribute noise to the logfile.
This was harder than it should have been, but this is the solution I'm currently using to log the request with all exceptions. It's probably not the cleanest way to do it, but it works perfectly for my needs. Thanks to John Lobo's answer for pointing me in the right direction.
It works by inspecting each instance of the Exception class and using PHP's instanceof to check whether it's a HTTP exception or not. If it is, it gets logged with the request URL and returns a view with a status code. If it's a generic non-HTTP exception, it gets logged with the request URL and returns another view with no status code (or you can keep the default exception behaviour by removing the return block, which renders a blank screen in production).
public function register()
{
$this->renderable(function (Exception $exception, $request) {
$url = $request->fullUrl();
if ($exception instanceof HttpException) {
$status = $exception->getStatusCode();
// Do not log HTTP 404 and 405s errors for reasons that will
// become apparent after a few hours of logging 404s and 405s
if(($status !== 404) && ($status !== 405)) {
Log::warning("Error $status occurred when trying to visit $url. Received the following message: " . $exception->getMessage());
}
return response()->view("errors.error", [
"exception" => $exception,
"status" => $status
],
$status
);
} else {
$status = $exception->getCode();
Log::warning("Exception $status occurred when trying to visit $url. Received the following message: " . $exception->getMessage());
return response()->view("errors.exception", [
"exception" => $exception,
"status" => $status
]);
}
});
// Optionally suppress all Laravel's default logging for exceptions, so only your own logs go to the logfile
$this->reportable(function (Exception $e) {
})->stop();
}
I'm looking for a way to catch all possible errors and redirect all types of errors to 1 page.
My current code in /Exceptions/Handler.php:
if ($this->isHttpException($exception)) {
$statusCode = $exception->getStatusCode();
switch ($statusCode) {
case '404':
return response()->view('layouts/404');
}
}
Problem is that ErrorException (E_NOTICE) types (which are caused by possible bugs in the code) aren't redirected to the 404 page. These errors end up on the 'Woops something went wrong' page.
I basically am trying to make every type of error end up on my custom error page.
All attempts end up on white pages.
What am I not seeing?
Well, to do what you're asking for you should go to App\Exceptions\Handler.php and there, you need to modify the render method:
public function render($request, Exception $exception)
{
abort(404);
}
But I insist, this is a terrible idea, you should catch the Exceptions that your app may get and show the error message to the user in a clean way, for example:
try{
//... your fancy code here
}catch(Exception $e){
// return with the message error $e->getMessage()
}
My question is whenever there is a 403 error I should redirect to my own custom page or show the flash message(on the same page) something like that.How can I achieve this in Laravel?.
You can use app/Exceptions/Handler.php for this
public function render($request, Exception $e)
{
if ($e->getStatusCode() == 403) {
return redirect('yourpage'); // this will be on a 403 exception
}
return parent::render($request, $e); // all the other exceptions
}
You can create a view for specific HTTP error codes. If you set up a Blade template at resources/views/errors/403.blade.php, it will get used for all 403 error responses.
Source
Alternatively you can set up a custom exception handler for 403 responses if you need something more involved. I found a good example of this here.
you can make you own page in inside the view .resources/views/errors/yourblade.blade.php
after that just return your page to that page.
You can use app/Exceptions/Handler.php for this as Thomas Moors stated above or you can use a try catch for basic error handling.
try {
do Something //
}
catch (Exception $e) {
//log error in log file or dv
return redirect->('home');
}
I have a Route defined as:
$app->post('api/v1/Subject','SubjectController#createSubject');
And in the Controller I have the following code:
public function createSubject(Request $request){
$Subject = Subject::create($request->all());
return response()->json($Subject);
}
Now, when someone sends incorrect data, it triggers a Query Exception - "SQLSTATE[23000]: Integrity constraint violation:" which is understood.
However, what I want is: I want do not want Lumen to send its own default Error Page in API Response. I want to capture this error event and send my own customized response. How can I do that?
Since I could not find a solution, I tried to add my own view at: /resources/views/errors/500.blade.php but Lumen is even ignoring this template. Please help. Ideally, I would want to capture this error event and send my own customized response.
EDIT:
Lumen was reporting two exceptions - PDOException and QueryException at the 500 error response. So, to get a custom error message, I put the following code in side function render() in app\Exceptions\Handler:
public function render($request, Exception $e)
{
if($e instanceof PDOException){
return response('It is my Custom response for PDOException that caused 500 error response.');
}
if($e instanceof QueryException){
return response('It is my Custom response for QueryException that cuased 500 error response.');
}
return parent::render($request, $e);
}
How do I create custom view for errors on Lumen? I tried to create resources/views/errors/404.blade.php, like what we can do in Laravel 5, but it doesn't work.
Errors are handled within App\Exceptions\Handler. To display a 404 page change the render() method to this:
public function render($request, Exception $e)
{
if($e instanceof NotFoundHttpException){
return response(view('errors.404'), 404);
}
return parent::render($request, $e);
}
And add this in the top of the Handler.php file:
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
Edit: As #YiJiang points out, the response should not only return the 404 view but also contain the correct status code. Therefore view() should be wrapped in a response() call passing in 404 as status code. Like in the edited code above.
The answer by lukasgeiter is almost correct, but the response made with the view function will always carry the 200 HTTP status code, which is problematic for crawlers or any user agent that relies on it.
The Lumen documentation tries to address this, but the code given does not work because it is copied from Laravel's, and Lumen's stripped down version of the ResponseFactory class is missing the view method.
This is the code which I'm currently using.
use Symfony\Component\HttpKernel\Exception\HttpException;
[...]
public function render($request, Exception $e)
{
if ($e instanceof HttpException) {
$status = $e->getStatusCode();
if (view()->exists("errors.$status")) {
return response(view("errors.$status"), $status);
}
}
if (env('APP_DEBUG')) {
return parent::render($request, $e);
} else {
return response(view("errors.500"), 500);
}
}
This assumes you have your errors stored in the errors directory under your views.
It didn't work for me, but I got it working with:
if($e instanceof \Symfony\Component\HttpKernel\Exception\NotFoundHttpException) {
return view('errors.404');
}
You might also want to add
http_response_code(404)
to tell the search engines about the status of the page.