Dear Users,
<note>
<to>ToText</to>
<from>Jani</from>
<heading>Reminder</heading>
<body>Don't forget me this weekend!</body>
</note>
I am in need to get the string length of XML tag using Xpath. I am using string-lenth(), but not able to render exact result.
Is there a way to get string-lenght(/to) or string-lenght(/from)?
Try to use below XPath:
//from/string-length(text())
or
//to/string-length(text())
Mathias Muller is correct, this should work:
string-length(/note/to) or string-length(/note/from)
please check your spelling of length as well.....
Related
I am trying to get the following information extracted out of a link using XPath, for example:
I have LINK TEXT HERE
I would like to select the href value of the link but only anything following ag_num=
So I would end up with 470 for the link above. Any ideas are truly appreciated, thank you!!
You can use below XPath expression to get required value:
substring-after(//a/#href, "ag_num=")
Is it possible to remove or replace text on XPath string?
Using XPath I get url with http://www and I want to remove http://www, so the same XPath query would return me only a link without http://www. I can't find anything about removing or replacing Xpath string.
Is it possible?
If so, how to do this?
Have you tried substring-after?
substring-after('http://www.stackoverflow.com', 'http://www.')
Example:
<demo>http://www.stackoverflow.com</demo>
XPath:
//demo/substring-after(., 'http://www.')
Yields:
stackoverflow.com
Check online demo here.
I am new to using XPath and I am trying to retrieve a node via its attribute but the problem is that the attribute is case insensitive meaning I won't exactly know how the string is cased in the document.
So for example:
Given the document:
<Document xmlns:my="http://www.MyDomain.com/MySchemaInstance">
<Machines>
<Machine FQDN="machine1.mydomain.com">
<...>
</Machine>
<Machine FQDN="Machine2.MyDomain.Com">
<...>
</Machine>
</Machines>
</Document>
If I want to retrieve the machine1 I would use the XPath:
//my:Machines/my:Machine/*[#FQDN='machine1.mydomain.com']
But a similar XPath to get machine2 would fail becuase the case does not match:
//my:Machines/my:Machine/*[#FQDN='machine2.mydomain.com'] //Fails
I have seen various posts mention using something like (I am not sure how to apply Namespaces to this):
translate(#FQDN, 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', 'abcdefghijklmnopqrstuvwxyz')
But even if I got it to work it would be really cumbersome considering the number of times I would be using it.
Finally I have read that XPath 2.0 supports matches() and lower-case() but being new to XPath I don't understand how to apply them:
For example if I try the following I get an "Invalid Qualified name":
//my:Machines/my:Machine/[matches(#FQDN, '(?i)machine1.mydomain.com')]
//my:Machines/my:Machine/[lower-case(#FQDN, 'machine1.mydomain.com')]
Can someone provide a sample XPath that includes handling of Namespaces that would work?
Thanks
Your example XML and XPath statements don't match.
The sample XML elements are not bound to a namespace. The "my" namespace-prefix is declared, but not used for those elements, so they are in the "no namespace".
Your sample XPath is using predicate filters on the children of Machine rather than on the Machine element that has the #FQDN.
You could use either of these methods to look for the value case-insensitive:
matches() function, with a flag for case-insensitive matching:
//Machines/Machine[matches(#FQDN,'machine2.mydomain.com','i')]
upper-case() function to evaluate the upper-case strings:
//Machines/Machine[upper-case(#FQDN)=upper-case('machine2.mydomain.com')]
lower-case() function to evaluate the lower-case strings:
//Machines/Machine[lower-case(#FQDN)=lower-case('machine2.mydomain.com')]
Can someone provide a sample XPath that includes handling of
Namespaces that would work?
Not sure what you meant by the handling of namespaces, but if you wanted to match on those elements regardless of their namespace then you can use the wildcard operator for the namespace:
//*:Machines/*:Machine[matches(#FQDN,'machine2.mydomain.com','i')]
I have a string of images' URLs and I need to convert it into an array.
http://rubular.com/r/E2a5v2hYnJ
How do I do this?
URI.extract(your_string)
That's all you need if you already have it in a string. I can't remember, but you may have to put require 'uri' in there first. Gotta love that standard library!
Here's the link to the docs URI#extract
Scan returns an array
myarray = mystring.scan(/regex/)
See here on regular-expressions.info
The best answer will depend very much on exactly what input string you expect.
If your test string is accurate then I would not use a regex, do this instead (as suggested by Marnen Laibow-Koser):
mystring.split('?v=3')
If you really don't have constant fluff between your useful strings then regex might be better. Your regex is greedy. This will get you part way:
mystring.scan(/https?:\/\/[\w.-\/]*?\.(jpe?g|gif|png)/)
Note the '?' after the '*' in the part capturing the server and path pieces of the URL, this makes the regex non-greedy.
The problem with this is that if your server name or path contains any of .jpg, .jpeg, .gif or .png then the result will be wrong in that instance.
Figuring out what is best needs more information about your input string. You might for example find it better to pattern match the fluff between your desired URLs.
Use String#split (see the docs for details).
Part of the problem is in rubular you are using https instead of http.. this gets you closer to what you want if the other answers don't work for you:
http://rubular.com/r/cIjmjxIfz5
I have a string like this.
<p class='link'>try</p>bla bla</p>
I want to get only <p class='link'>try</p>
I have tried this.
/<p class='link'>[^<\/p>]+<\/p>/
But it doesn't work.
How can I can do this?
Thanks,
If that is your string, and you want the text between those p tags, then this should work...
/<p\sclass='link'>(.*?)<\/p>/
The reason yours is not working is because you are adding <\/p> to your not character range. It is not matching it literally, but checking for not each character individually.
Of course, it is mandatory I mention that there are better tools for parsing HTML fragments (such as a HTML parser.)
'/<p[^>]+>([^<]+)<\/p>/'
will get you "try"
It looks like you used this block: [^<\/p>]+ intending to match anything except for </p>. Unfortunately, that's not what it does. A [] block matches any of the characters inside. In your case, the /<p class='link'>[^<\/p>]+ part matched <p class='link'>try</, but it was not immediately followed by the expected </p>, so there was no match.
Alex's solution, to use a non-greedy qualifier is how I tend to approach this sort of problem.
I tried to make one less specific to any particular tag.
(<[^/]+?\s+[^>]*>[^>]*>)
this returns:
<p class='link'>try</p>