scenario is crm with tables account, account_contact, contact and account_contact_role. The latter contains roles like 'project lead' or 'account manager' for the combos defined in the junction table.
My challenge is the account view, that is listing also the connected persons with their roles. I want my grid to show: Doe | John | employee.
The problem is now when the contact has 2+ entries in the junction table. How can I print the correct role for the row? As you can see in the code I solved it the static way which shows only 1 out of n times the correct value. Tried it with inner join without success. Is it a problem of the search in the model or with the access in the view?
the relation from the account model to the contacts:
public function getContacts($role = null)
{
// many-to-many
return $this->hasMany(ContactRecord::className(), ['id' => 'contact_id'])
->via('accountContacts')
->innerJoinWith(['accountContacts.role'])
->andWhere(['account_contact.account_id' => $this->id])
->andWhere(['account_contact_role.type' => $role])
;
}
the view
<?= \yii\grid\GridView::widget([
'dataProvider' => new \yii\data\ActiveDataProvider([
'query' => $model->getContacts('internal'),
'pagination' => false
]),
'columns' => [
'lastname',
'firstname',
[
'label' => 'Role',
'attribute' => 'accountContacts.0.role.name',
],
[
'class' => \yii\grid\ActionColumn::className(),
'controller' => 'contacts',
'header' => Html::a('<i class="glyphicon glyphicon-plus"></i> Add New', ['contact-records/create', 'account_id' => $model->id]),
'template' => '{update}{delete}',
]
]
]); ?>
defined relations are:
account has many accountContacts has one contact
accountContacts has one accountContactRole
Many thanks in advance!
You are showing account's contacts, so you have to list from Contact model.
Inside Contact model (or Contact ActiveQuery file):
public static function queryContactsFromAccountAndRole($account, $role = null)
{
// many-to-many
return ContactRecord::find()->innerJoinWith(['accountContacts' => function($q) use($account, $role) {
$q->innerJoinWith(['accountContactsRole'])
->andWhere(['account_contact.account_id' => $account->id])
->andWhere(['account_contact_role.type' => $role]);
}])
->andWhere(['account_contact.account_id' => $account->id]);
}
Now you have one record for each contact and the gridview will show all contacts.
Related
Just new with backpack. I search on official site and googled it, but dit not found an answer
In laravel 7, using Backpack 4.1
My data model is : Customer has many addresses
Relationship is configured in the Customer model :
public function addresses()
{
return $this->hasMany(\App\Models\Address::class, 'user_id');
}
Relationship is configured in the Address model :
public function customer()
{
return $this->belongsTo(\App\Models\Customer::class);
}
public function country()
{
return $this->belongsTo(\App\Models\Country::class);
}
public function address_type()
{
return $this->belongsTo(\App\Models\AddressType::class);
}
In my customer show page, I would like to show all customer addresses in a table, just under the customer details.
So in my CustomerCrudController, I have implemented this method :
protected function setupShowOperation()
{
$this->crud->set('show.setFromDb', false);
$this->crud->addColumn(['name' => 'name', 'type' => 'text', 'label' => __('models/customers.fields.name'), ]);
$this->crud->addColumn(['name' => 'email', 'type' => 'email', 'label' => __('models/customers.fields.email'), ]);
$this->crud->addColumn([
'name' => 'addresses',
'label' => __('models/addresses.plural'),
'type' => 'table',
'columns' => [
'address_type_id' => __('models/addresses.fields.address_type'),
'address_type.name' => __('models/addresses.fields.address_type'),
'address1' => __('models/addresses.fields.address1'),
'address2' => __('models/addresses.fields.address2'),
'city' => __('models/addresses.fields.address2'),
'postal_code' => __('models/addresses.fields.address2'),
'country.name' => __('models/countries.singular'),
],
]);
}
When I go on my page : /admin/customer/3/show,
In my debugbar, I saw the query how load addresses
select * from `addresses` where `addresses`.`user_id` = 3 and `addresses`.`user_id` is not null
I have the table rendered with the corresponding number of lines from data in DB, but rows are blank.
Is this the correct way to do that ? What are the correct parameters ?
Is there a way to show a table with action buttons (show entry, edit) - same as in List view ?
Should it be implemented in another way ?
Hope I'm clear.
Thanks
Don't know if it is a laravel bug, but my solution was to create my own table blade, base on the file :
\vendor\backpack\crud\src\resources\views\crud\columns\table.blade.php
and have created my own :
\resources\views\vendor\backpack\crud\columns\address_table.blade.php
I have juste changed the file:40
#elseif( is_object($tableRow) && property_exists($tableRow, $tableColumnKey) )
to
#elseif( is_object($tableRow) && isset($tableRow->{$tableColumnKey}) )
now, in my CustomerCrudController.php :
protected function setupShowOperation()
{
$this->crud->set('show.setFromDb', false);
$this->crud->addColumn(['name' => 'name', 'type' => 'text', 'label' => __('models/customers.fields.name'),]);
$this->crud->addColumn(['name' => 'email', 'type' => 'email', 'label' => __('models/customers.fields.email'),]);
$this->crud->addColumn([
'name' => 'addresses',
'label' => __('models/addresses.plural'),
'type' => 'address_table', // my custom type
'model' => \App\Models\Address::class,
'entity' => 'addresses',
'columns' => [
'address_type_name' => __('models/addresses.fields.address_type'),
'postal_code' => __('models/addresses.fields.postal_code'),
'city' => __('models/addresses.fields.city'),
'address1' => __('models/addresses.fields.address1'),
'address2' => __('models/addresses.fields.address1'),
],
]);
}
And I've added an accessor in my model (Address.php)
public function getAddressTypeNameAttribute()
{
return "{$this->address_type->name}";
}
Don't know if there is a better way ...
Hope this will help others.
I use Laravel 8,
In addition for the answer above, and based on this answer https://stackoverflow.com/a/65072393 and https://stackoverflow.com/a/43011286/1315632 regarding PHP function property_exists vs Laravel magic methods to create dynamic properties and methods
After creating the overwrite column php artisan backpack:publish crud/columns/table
I change line 40 in file:\resources\views\vendor\backpack\crud\columns\table.blade.php into
#elseif( is_object($tableRow) && ( property_exists($tableRow, $tableColumnKey) || property_exists((object)$tableRow->toArray(), $tableColumnKey) ) )
adding OR checking from answer https://stackoverflow.com/a/65072393
I'm trying to set Role (or permission) to my category in Laravel Backpack (newscrud).
I have added the field of Role in CategoryCrudController class and category_role table in DB and set relations in Category and Role models.
the relation data is now stored in the table, although the checkbox remains unchecked!
$this->crud->addField(
[
'label' => 'Roles',
'type' => 'checklist',
'name' => 'roles',
'entity' => 'roles',
'attribute' => 'name',
'model' => "Backpack\PermissionManager\app\Models\Role",
'pivot' => true,
]
);
Added role field
Now I want to allow the users with the granted role to use crud on the category's articles.
I know I can use hasRole and use denyAccess() in CrudController's setup function but it doesn't what I want.
public function setup(){
if (backpack_user()->hasRole('certainCategoryRole')) {
$this->crud->denyAccess([ 'delete','edit','write']);
}
}
I need to give articles operations access to users by their category's assigned role.
Can anyone help?
Thanx
Using this link.
I tried to add a where clause in addField where the dropdown should load the contents as options only if they match a condition.
Here is the code:
$this->crud->addField([ // select_from_array
'name' => 'manager',
'label' => "Manager Name",
'type' => 'select_callback', // Custom field type of select2
'entity' => 'Manager',
'attribute' => 'name',
'model' => 'App\Models\Manager',
'scope' => 'manager'
// 'allows_multiple' => true, // OPTIONAL; needs you to cast this to array in your model;
], 'update/create/both');
And in Model.php
public function scopeManager($query)
{
return $query->where('gym_code', Auth::user()->gym_code);
}
But it is not working!!
Thanks
I found the answer in the same link that I suggested in Question.
In the link #thplat answered a change in select_callback.blade.php
For the select_callback view I took the select view and changed only one line there.
We go from:
#foreach ($field['model']::all() as $connected_entity_entry) to #foreach ((isset($field['callback']) ? $field['callback']() : $field['model']::all()) as $connected_entity_entry).
I am new in yii2. I don't know much about table relation. I have a 3 tables shops promotions and promotion_details. promotion_details contains promotion id and shop id. promotion has status like active or inactive. i want display in shop view only active promotions. How can i Do that? Thanks in advance
In you promotion_detail view add a getter function for relation and a getter function for the field
/* ActiveRelation */
public function getPropomition()
{
return $this->hasOne(Promotion::className(), ['id' => 'promotion_id']);
}
/* Getter for status name */
public function getStatus() {
return $this->prpmotion->status;
}
in view
echo GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'id',
.......
'status',
['class' => 'yii\grid\ActionColumn'],
]
]);
this guide could be useful http://www.yiiframework.com/wiki/621/filter-sort-by-calculated-related-fields-in-gridview-yii-2-0/
Not inserted multi select value in database.
My fields.yaml Code is :
related_recipe:
label: 'Related Recipe'
span: auto
nameFrom: recipe_title
descriptionFrom: description
attributes: {multiple:'multiple'}
type: relation
My model code is :
public $belongsTo = [
'related_recipe' => [
'Qdata\Taeq\Models\Recipe',
'conditions' => 'status = 1'
],
];
Currently only one selected value inserted in database.need add multiple value in database. Can any one have the solution of it ?
You should use a $belongsToMany relation in this case.
$belongsTo means your model is link with a single entity of your Recipe model.
To do so with relation you need to go with "belongsToMany" relation. for example:
In your Model
'related_recipes' => [
'Qdata\Taeq\Models\Recipe',
'table' => 'pivot_table_name',
'key' => 'foreign_key_of_pivot_table',
'otherKey' => 'other_key',
],
In related another Model
'makers' => [
'Qdata\Taeq\Models\AnotherModel',
'table' => 'pivot_table_name',
'key' => 'foreign_key_of_pivot_table',
'otherKey' => 'other_key',
],
this will save your multiselect dropdown data in the related pivot table in your database.