here is a little example:
02-09-17 1:01 PM - Some User (Add comments)
Hello,
How are you?
Regards,
02-09-17 3:29 PM - Another User (Add comments)
Hey,
Thanks, all is fine.
Some another text here.
02-09-17 4:30 AM - Just a User (Add comments)
some text
with
multiline
I want to parse and process this three comments. What is the best way for this?
Tried regex like this - http://www.rubular.com/r/k1CHJ1STTD but have problems with /m flag. Without multiline flag for regex - can`t catch "body" of comment.
Also tried to split by regex:
text_above.split(/^(\d{1,2}-\d{1,2}-\d{2} \d{1,2}:\d{1,2} [AP]M - .+ \(Add comments\))/)
=> ["",
"02-09-17 1:01 PM - Some User (Add comments)",
"\n" + "Hello,\n" + "\n" + "How are you?\n" + "\n" + "Regards,\n" + "\n",
"02-09-17 3:29 PM - Another User (Add comments)",
"\n" + "Hey,\n" + "\n" + "Thanks, all is fine.\n" + "\n" + "Some another text here.\n" + "\n",
"02-09-17 4:30 AM - Just a User (Add comments)",
"\n" + "some text\n" + "with\n" + "multiline\n" + "\n",
"02-09-17 5:29 PM - Another User (Add comments)",
"\n" + "Hey,\n" + "\n" + "Thanks, all is fine.\n" + "\n" + "Some another text here.\n" + "\n",
"02-09-17 6:30 AM - Just a User (Add comments)",
"\n" + "some text\n" + "with\n" + "multiline\n"]
But this is not comfortable solution.
Ideally I want to get regex captures with three or two group matches, for example:
1. 02-09-17 1:01 PM
2. Some User (Add comments)
3. Hello,
How are you?
Regards,
for each comment, or, Array of comments:
[['02-09-17 1:01 PM - Some User (Add comments) Hello,
How are you?
Regards,'],[...]]
Any ideas? Thanks.
You can keep it simple using two splits (one for the whole string and one for each block):
text.split(/\n\n(?=\d\d-)/).map { |m| m.split(/ - |\n/, 3) }
You can also use the scan method, but it's a little more fastidious:
text.scan(/([\d-]+[^-]+) - (.*)\n(.*(?>\n.*)*?(?=\n\n\d\d-|\z))/)
slice_before might be easier to understand than a huge scan, and it has the advantage of keeping the pattern (split removes it)
data = text.each_line.slice_before(/^\d\d\-\d\d\-\d\d/).map do |block|
time, user = block.shift.strip.split(' - ')
[time, user, block.join.strip]
end
p data
# [["02-09-17 1:01 PM",
# "Some User (Add comments)",
# "Hello,\n\nHow are you?\n\nRegards,"],
# ["02-09-17 3:29 PM",
# "Another User (Add comments)",
# "Hey,\n\nThanks, all is fine.\n\nSome another text here."],
# ["02-09-17 4:30 AM",
# "Just a User (Add comments)",
# "some text\nwith\nmultiline"]]
You can use this regular expression:
(\d{2}-\d{2}-\d{2} \d{1,2}:\d{2} (?:AM|PM)) - (.*?)\r?\n((?:.|\r?\n)+?)(?=\r?\n\d{2}-\d{2}-\d{2} \d{1,2}:\d{2} (?:AM|PM) - |$)
(\d{2}-\d{2}-\d{2} \d{1,2}:\d{2} (?:AM|PM)) matches the first group, the date and time. The date must consist of three numbers, separated by a dash, followed by the time with AM/PM
(.*?)\r?\n((?:.|\r?\n)+?) matches the username up to the first line break (\r?\n) as the second group. Afterwards, anything including linebreaks is matching and building the third group, the comment.
This won't work, because it would handle everything from the beginning of the comment up to the end of the file as a comment. Therefore, you need to select the next date/time format, so that it stops there. You can do this just by repeating the date/time format after the comment and matching non-greedy, but this will include the next datetime already in the current match and therefore exclude it in the next match (which will lead to a skip of every second match). To circumvent this, you can use a positive lookahead: (?=\r?\n\d{2}-\d{2}-\d{2} \d{1,2}:\d{2} (?:AM|PM) - |$). This matches a number afterwards, but does not include it in the match. The last comment must then end at the end of the string $.
You need to use the global flag /g but mustn't use the multi-line flag /g, because the matching of the comment goes over multiple lines.
Here is a live example: https://regex101.com/r/o63GQE/2
Related
I would like to compare two of my log files generated before and after an implementation to see if it has impacted anything. However, the order of the logs I get is not the same all the time. Since, the log file also has multiple indented lines, when I tried to sort, everything is sorted. But, I would like to keep the child intact with the parent. Indented lines are spaces and not tab.
Any help would be greatly appreciated. I am fine with any windows solution or Linux one.
Eg of the file:
#This is a sample code
Parent1 to be verified
Child1 to be verified
Child2 to be verified
Child21 to be verified
Child23 to be verified
Child22 to be verified
Child221 to be verified
Child4 to be verified
Child5 to be verified
Child53 to be verified
Child52 to be verified
Child522 to be verified
Child521 to be verified
Child3 to be verified
I am posting another answer here to sort it hierarchically, using python.
The idea is to attach the parents to the children to make sure that the children under the same parent are sorted together.
See the python script below:
"""Attach parent to children in an indentation-structured text"""
from typing import Tuple, List
import sys
# A unique separator to separate the parent and child in each line
SEPARATOR = '#'
# The indentation
INDENT = ' '
def parse_line(line: str) -> Tuple[int, str]:
"""Parse a line into indentation level and its content
with indentation stripped
Args:
line (str): One of the lines from the input file, with newline ending
Returns:
Tuple[int, str]: The indentation level and the content with
indentation stripped.
Raises:
ValueError: If the line is incorrectly indented.
"""
# strip the leading white spaces
lstripped_line = line.lstrip()
# get the indentation
indent = line[:-len(lstripped_line)]
# Let's check if the indentation is correct
# meaning it should be N * INDENT
n = len(indent) // len(INDENT)
if INDENT * n != indent:
raise ValueError(f"Wrong indentation of line: {line}")
return n, lstripped_line.rstrip('\r\n')
def format_text(txtfile: str) -> List[str]:
"""Format the text file by attaching the parent to it children
Args:
txtfile (str): The text file
Returns:
List[str]: A list of formatted lines
"""
formatted = []
par_indent = par_line = None
with open(txtfile) as ftxt:
for line in ftxt:
# get the indentation level and line without indentation
indent, line_noindent = parse_line(line)
# level 1 parents
if indent == 0:
par_indent = indent
par_line = line_noindent
formatted.append(line_noindent)
# children
elif indent > par_indent:
formatted.append(par_line +
SEPARATOR * (indent - par_indent) +
line_noindent)
par_indent = indent
par_line = par_line + SEPARATOR + line_noindent
# siblings or dedentation
else:
# We just need first `indent` parts of parent line as our prefix
prefix = SEPARATOR.join(par_line.split(SEPARATOR)[:indent])
formatted.append(prefix + SEPARATOR + line_noindent)
par_indent = indent
par_line = prefix + SEPARATOR + line_noindent
return formatted
def sort_and_revert(lines: List[str]):
"""Sort the formatted lines and revert the leading parents
into indentations
Args:
lines (List[str]): list of formatted lines
Prints:
The sorted and reverted lines
"""
sorted_lines = sorted(lines)
for line in sorted_lines:
if SEPARATOR not in line:
print(line)
else:
leading, _, orig_line = line.rpartition(SEPARATOR)
print(INDENT * (leading.count(SEPARATOR) + 1) + orig_line)
def main():
"""Main entry"""
if len(sys.argv) < 2:
print(f"Usage: {sys.argv[0]} <file>")
sys.exit(1)
formatted = format_text(sys.argv[1])
sort_and_revert(formatted)
if __name__ == "__main__":
main()
Let's save it as format.py, and we have a test file, say test.txt:
parent2
child2-1
child2-1-1
child2-2
parent1
child1-2
child1-2-2
child1-2-1
child1-1
Let's test it:
$ python format.py test.txt
parent1
child1-1
child1-2
child1-2-1
child1-2-2
parent2
child2-1
child2-1-1
child2-2
If you wonder how the format_text function formats the text, here is the intermediate results, which also explains why we could make file sorted as we wanted:
parent2
parent2#child2-1
parent2#child2-1#child2-1-1
parent2#child2-2
parent1
parent1#child1-2
parent1#child1-2#child1-2-2
parent1#child1-2#child1-2-1
parent1#child1-1
You may see that each child has its parents attached, all the way along to the root. So that the children under the same parent are sorted together.
Short answer (Linux solution):
sed ':a;N;$!ba;s/\n /#/g' test.txt | sort | sed ':a;N;$!ba;s/#/\n /g'
Test it out:
test.txt
parent2
child2-1
child2-1-1
child2-2
parent1
child1-1
child1-2
child1-2-1
$ sed ':a;N;$!ba;s/\n /#/g' test.txt | sort | sed ':a;N;$!ba;s/#/\n /g'
parent1
child1-1
child1-2
child1-2-1
parent2
child2-1
child2-1-1
child2-2
Explanation:
The idea is to replace the newline followed by an indentation/space with a non newline character, which has to be unique in your file (here I used # for example, if it is not unique in your file, use other characters or even a string), because we need to turn it back the newline and indentation/space later.
About sed command:
:a create a label 'a'
N append the next line to the pattern space
$! if not the last line, ba branch (go to) label 'a'
s substitute, /\n / regex for newline followed by a space
/#/ a unique character to replace the newline and space
if it is not unique in your file, use other characters or even a string
/g global match (as many times as it can)
I'm moving my bookmarks from kippt.com to pinboard.in.
I exported my bookmarks from Kippt and for some reason, they were storing tags (preceded by #) and description within the same field. Pinboard keeps tags and description separated.
This is what a Kippt bookmark looks like after export:
<DT>This is a title
<DD>#tag1 #tag2 This is a description
This is what it should look like before importing into Pinboard:
<DT>This is a title
<DD>This is a description
So basically, I need to replace #tag1 #tag2 by TAGS="tag1,tag2" and move it on the first line within <A>.
I've been reading about moving chunks of data here: sed or awk to move one chunk of text betwen first pattern pair into second pair?
I haven't been to come up with a good recipe so far. Any insight?
Edit:
Here's an actual example of what the input file looks like (3 entries out of 3500):
<DT>Phabricator
<DD>#bug #tracking
<DT>The hidden commands for diagnosing and improving your Netflix streaming quality – Quartz
<DT>Icelandic Farm Holidays | Local experts in Iceland vacations
<DD>#iceland #tour #car #drive #self Self-driving tour of Iceland
This might not be the most beautiful solution, but since it seems to be a one-time-thing it should be sufficient.
import re
dt = re.compile('^<DT>')
dd = re.compile('^<DD>')
with open('bookmarks.xml', 'r') as f:
for line in f:
if re.match(dt, line):
current_dt = line.strip()
elif re.match(dd, line):
current_dd = line
tags = [w for w in line[4:].split(' ') if w.startswith('#')]
current_dt = re.sub('(<A[^>]+)>', '\\1 TAGS="' + ','.join([t[1:] for t in tags]) + '">', current_dt)
for t in tags:
current_dd = current_dd.replace(t + ' ', '')
if current_dd.strip() == '<DD>':
current_dd = ""
else:
print current_dt
print current_dd
current_dt = ""
current_dd = ""
print current_dt
print current_dd
If some parts of the code are not clear, just tell me. You can of course use python to write the lines to a file instead of printing them, or even modify the original file.
Edit: Added if-clause so that empty <DD> lines won't show up in the result.
script.awk
BEGIN{FS="#"}
/^<DT>/{
if(d==1) print "<DT>"s # for printing lines with no tags
s=substr($0,5);tags="" # Copying the line after "<DT>". You'll know why
d=1
}
/^<DD>/{
d=0
m=match(s,/>/) # Find the end of the HREF descritor first match of ">"
for(i=2;i<=NF;i++){sub(/ $/,"",$i);tags=tags","$i} # Concatenate tags
td=match(tags,/ /) # Parse for tag description (marked by a preceding space).
if(td==0){ # No description exists
tags=substr(tags,2)
tagdes=""
}
else{ # Description exists
tagdes=substr(tags,td)
tags=substr(tags,2,td-2)
}
print "<DT>" substr(s,1,m-1) ", TAGS=\"" tags "\"" substr(s,m)
print "<DD>" tagdes
}
awk -f script.awk kippt > pinboard
INPUT
<DT>Phabricator
<DD>#bug #tracking
<DT>The hidden commands for diagnosing and improving your Netflix streaming quality – Quartz
<DT>Icelandic Farm Holidays | Local experts in Iceland vacations
<DD>#iceland #tour #car #drive #self Self-driving tour of Iceland
OUTPUT:
<DT>Phabricator
<DD>
<DT>The hidden commands for diagnosing and improving your Netflix streaming quality – Quartz
<DT>Icelandic Farm Holidays | Local experts in Iceland vacations
<DD> Self-driving tour of Iceland
Let's say I have an array of Twitter account names:
string = %w[example1 example2 example3 example4 example5 example6 example7 example8 example9 example10 example11 example12 example13 example14 example15 example16 example17 example18 example19 example20]
And a prepend and append variable:
prepend = 'Check out these cool people: '
append = ' #FollowFriday'
How can I turn this into an array of as few strings as possible each with a maximum length of 140 characters, starting with the prepend text, ending with the append text, and in between the Twitter account names all starting with an #-sign and separated with a space. Like this:
tweets = ['Check out these cool people: #example1 #example2 #example3 #example4 #example5 #example6 #example7 #example8 #example9 #FollowFriday', 'Check out these cool people: #example10 #example11 #example12 #example13 #example14 #example15 #example16 #example17 #FollowFriday', 'Check out these cool people: #example18 #example19 #example20 #FollowFriday']
(The order of the accounts isn't important so theoretically you could try and find the best order to make the most use of the available space, but that's not required.)
Any suggestions? I'm thinking I should use the scan method, but haven't figured out the right way yet.
It's pretty easy using a bunch of loops, but I'm guessing that won't be necessary when using the right Ruby methods. Here's what I came up with so far:
# Create one long string of #usernames separated by a space
tmp = twitter_accounts.map!{|a| a.insert(0, '#')}.join(' ')
# alternative: tmp = '#' + twitter_accounts.join(' #')
# Number of characters left for mentioning the Twitter accounts
length = 140 - (prepend + append).length
# This method would split a string into multiple strings
# each with a maximum length of 'length' and it will only split on empty spaces (' ')
# ideally strip that space as well (although .map(&:strip) could be use too)
tweets = tmp.some_method(' ', length)
# Prepend and append
tweets.map!{|t| prepend + t + append}
P.S.
If anyone has a suggestion for a better title let me know. I had a difficult time summarizing my question.
The String rindex method has an optional parameter where you can specify where to start searching backwards in a string:
arr = %w[example1 example2 example3 example4 example5 example6 example7 example8 example9 example10 example11 example12 example13 example14 example15 example16 example17 example18 example19 example20]
str = arr.map{|name|"##{name}"}.join(' ')
prepend = 'Check out these cool people: '
append = ' #FollowFriday'
max_chars = 140 - prepend.size - append.size
until str.size <= max_chars do
p str.slice!(0, str.rindex(" ", max_chars))
str.lstrip! #get rid of the leading space
end
p str unless str.empty?
I'd make use of reduce for this:
string = %w[example1 example2 example3 example4 example5 example6 example7 example8 example9 example10 example11 example12 example13 example14 example15 example16 example17 example18 example19 example20]
prepend = 'Check out these cool people:'
append = '#FollowFriday'
# Extra -1 is for the space before `append`
max_content_length = 140 - prepend.length - append.length - 1
content_strings = string.reduce([""]) { |result, target|
result.push("") if result[-1].length + target.length + 2 > max_content_length
result[-1] += " ##{target}"
result
}
tweets = content_strings.map { |s| "#{prepend}#{s} #{append}" }
Which would yield:
"Check out these cool people: #example1 #example2 #example3 #example4 #example5 #example6 #example7 #example8 #example9 #FollowFriday"
"Check out these cool people: #example10 #example11 #example12 #example13 #example14 #example15 #example16 #example17 #FollowFriday"
"Check out these cool people: #example18 #example19 #example20 #FollowFriday"
I seem to see double-spaced output when parsing/dumping a simple YAML file with a pipe-text field.
The test is:
public void yamlTest()
{
DumperOptions printOptions = new DumperOptions();
printOptions.setLineBreak(DumperOptions.LineBreak.UNIX);
Yaml y = new Yaml(printOptions);
String input = "foo: |\n" +
" line 1\n" +
" line 2\n";
Object parsedObject = y.load(new StringReader(input));
String output = y.dump(parsedObject);
System.out.println(output);
}
and the output is:
{foo: 'line 1
line 2
'}
Note the extra space between line 1 and line 2, and after line 2 before the end of the string.
This test was run on Mac OS X 10.6, java version "1.6.0_29".
Thanks!
Mark
In the original string you use literal style - it is indicating by the '|' character. When you dump your text, you use single-quoted style which ignores the '\n' characters at the end. That is why they are repeated with the empty lines.
Try to set different styles in DumperOptions:
// and others - FOLDED, DOUBLE_QUOTED
DumperOptions.setDefaultScalarStyle(ScalarStyle.LITERAL)
I am trying to handle an array with Ruby v1.9.2 but it has some strange behavior.
The best explanation may be done with examples:
CASE 1 TEST
#test1 = "image/bmp, image/gif, image/jpg".split(',')
Debug #test1:
---
- image/bmp # why this?!
- " image/gif"
- " image/jpg"
CASE 2 TEST
#test2 = ", image/bmp, image/gif, image/jpg".split(',')
Debug #test2:
---
- "" # why this?!
- " image/bmp"
- " image/gif"
- " image/jpg"
WHAT I NEED
Notice: I can use the CASE 2 TEST, but I would like to do things right and better.
Debug that I would like to have:
---
- " image/bmp"
- " image/gif"
- " image/jpg"
In the test case 1 there is no space before "image/bmp" in the result because there is no space before "image/bmp" in the original string.
In the test case 2 there is an empty string at the beginning because the string starts with a comma, and for every separator in the string there is a string in the resulting array, containing what comes before that separator (which in this case means the empty string).
If you want the result you've shown, you could just add a space (but no comma) before "image/bmp" in the source string. Alternatively you could split by /, */ and then add one space before each string with map. Though frankly I don't get why you want a space before each string.
>> ", image/bmp, image/gif, image/jpg".split(/\s*,\s*/).select{|x| x!=""}
=> ["image/bmp", "image/gif", "image/jpg"]