Bash Substring multiple parameters - bash

Question

I need to extract two parameters from each line of a svn log but I am not able to do it with grep.
My Svn log command, such as
svn log http://svn.apache.org/repos/asf/xerces/java/trunk/ | grep "^r[0-9]\+ | " | cut -c2-
Outputs the result in this format:
318150 | lehors | 2002-01-28 20:48:11 +0100 (Mon, 28 Jan 2002) | 2 lines
318149 | elena | 2002-01-28 20:46:33 +0100 (Mon, 28 Jan 2002) | 12 lines
318148 | lehors | 2002-01-28 20:33:36 +0100 (Mon, 28 Jan 2002) | 2 lines
318147 | lehors | 2002-01-28 20:22:51 +0100 (Mon, 28 Jan 2002) | 2 lines
How can I grep the release number (first parameter) and the date in this format?
318150 2002-01-28
318149 2002-01-28
318148 2002-01-28
318147 2002-01-28

Answer 1

Use a more robust Awk for this to pattern-match/extract from individual columns.
.. | awk 'BEGIN{FS="|"}{split($3,temp, " "); print $1,temp[1]}'
318150 2002-01-28
318149 2002-01-28
318148 2002-01-28
318147 2002-01-28
The .. | part represents the command to be included that produces the required output which is pipe-lined to Awk
The logic is pretty straight-forward, split input lines with de-limiter as | which is done by FS="|". Now $1 represents the first field you want, and for the second part, split the part $3 and use the split() function to split on delimiter, a white-space character and store it in array temp, so that it can be accessed as temp[1], the other space fields are present in the array from the next index on wards.
So ideally I guess it should be,
svn log http://svn.apache.org/repos/asf/xerces/java/trunk/ | \
awk 'BEGIN{FS="|"}{split($3,temp, " "); print $1,temp[2]}'
Alternatively you could use GNU grep with its -E extended regular expression capabilities, but it is just not good enough to show the matching entries on same line like,
grep -oE '[[:digit:]]{4}-[[:digit:]]{2}-[[:digit:]]{2}' file
(and)
grep -oE '^[[:digit:]]{6}' file
but not together as I have used the -o flag to print the match only part.

Answer 2

As your file is separated by a single space and you want to have the first and 5th columns, this is another solution by using cut:
cut -d' ' -f1,5 < svn_log_output_file
(or piping cut -d' ' -f1,5 to your command)

Answer 3

A much simpler approach with multiple delimiters-
awk -F '[| ]' '{print $1, $7}' file
Where file contains the output you showed in your question.
Output-
318150 2002-01-28
318149 2002-01-28
318148 2002-01-28
318147 2002-01-28
Of course, you don't need to store in an intermediate file. You can do-
svn log http://svn.apache.org/repos/asf/xerces/java/trunk/ \
| grep "^r[0-9]\+ | " | cut -c2- | \
awk -F '[| ]' '{print $1, $7}'

Answer 4

awk '{print $1,$5}' file
318150 2002-01-28
318149 2002-01-28
318148 2002-01-28
318147 2002-01-28