I want to setup some configuration when my container starts, for this I am using shell scripts. But my container will exits as soon as my scripts ends, I have tried with -d flag / detached mode but It will never run in detached mode.
Below is my Dockerfile
FROM ubuntu:14.04
ADD shell.sh /usr/local/bin/shell.sh
RUN chmod 777 /usr/local/bin/shell.sh
CMD /usr/local/bin/shell.sh
Below is my shell script
#!/bin/bash
echo Hello-docker
Run without any flag
docker run hello-docker
This will print 'Hello-docker' on my console and exits
Run with -itd flags
docker run -itd hello-docker
and as below my console output, This time also will exits soon. :(
The difference I saw is in COMMAND section when I run other images command section will shows "/bin/bash" and will continue in detached mode.
And when I run my image in container with shell script COMMAND section will show "/bin/sh -c /usr/loca", and Exit.
I want to run container till I not stop it manually.
EDIT:
After adding ENTRYPOINT instruction in Dockerfile, this will not execute my shell script :(
FROM ubuntu:14.04
ADD shell.sh /usr/local/bin/shell.sh
RUN chmod 777 /usr/local/bin/shell.sh
CMD /usr/local/bin/shell.sh
ENTRYPOINT /bin/bash
As per docker documentation here
CMD will be overridden when running the container with alternative arguments, so If I run docker image with some arguments as below, will not execute CMD instructions. :(
sudo docker run -it --entrypoint=/bin/bash <imagename>
A docker container will run as long as the CMD from your Dockerfile takes.
In your case your CMD consists of a shell script containing a single echo. So the container will exit after completing the echo.
You can override CMD, for example:
sudo docker run -it --entrypoint=/bin/bash <imagename>
This will start an interactive shell in your container instead of executing your CMD. Your container will exit as soon as you exit that shell.
If you want your container to remain active, you have to ensure that your CMD keeps running. For instance, by adding the line while true; do sleep 1; done to your shell.sh file, your container will print your hello message and then do nothing any more until you stop it (using docker stop in another terminal).
You can open a shell in the running container using docker exec -it <containername> bash. If you then execute command ps ax, it will show you that your shell.sh is still running inside the container.
Finally with some experiments I got my best result as below
There is nothing wrong with my Dockerfile as below it's correct.
FROM ubuntu:14.04
ADD shell.sh /usr/local/bin/shell.sh
RUN chmod 777 /usr/local/bin/shell.sh
CMD /usr/local/bin/shell.sh
What I do to get expected result is, I just add one more command(/bin/bash) in my shell script file as below and vola everything works in my best way.
#!/bin/bash
echo “Hello-docker” > /usr/hello.txt
/bin/bash
You can also modify your first Dockerfile, replacing
CMD /usr/local/bin/shell.sh
by
CMD /usr/local/bin/shell.sh ; sleep infinity
That way, your script does not terminate, and your container stays running.
CMD bash -C '/path/to/start.sh';'bash'
Try
CMD /bin/bash -c 'MY_COMMAND_OR_SHELL_SCRIPT; /bin/bash'
Trying an explanation here to the answer of #lanni654321. sh shell is standard in Dockerfile. You must call bash shell to start bash with .bashrc, many commands also need RUN /bin/bash -c '...' in the same way as in CMD above, since sh shell is often not enough. If you add 'bash' in the end of CMD, the container will not exit because the image was committed with something that is still open.
See “/bin/sh: 1: MY_COMMAND: not found” for an error caused by sh and solved by bash.
I think that you will usually not need this. You can just use RUN /bin/bash -c '...', in my case, this could do anything that can be done in a base image before you go into varying details in docker-compose to start the containers.
But that is all not needed if you need to just have a container running without exiting. Just
docker run -dit --name MY_CONTAINER MY_IMAGE:latest
and then
docker exec -it MY_CONTAINER /bin/bash
and you should be in the bash of the container, and it should not exit.
Or if the exit happens during docker-compose, use
command: bash -c "MY_COMMAND --wait"
At your start shell append a line code:
tail -f /dev/null or /bin/bash
to make sure you shell done and suspend a process in system so that docker container not shutdown.Don't forget to give "chmod +x" access to start.sh.
there is demo:
#!/bin/bash
cp /root/supervisor/${RUN_SERVICE}.ini /etc/supervisor/conf.d/
sleep 1
service supervisor start
/bin/bash
Related
I would like to run a docker entrypoint that creates a new user, switches to that user and destroys root shell so it cannot be exited back into
In the command line this works
$ useradd -s /bin/bash toby
$ exec su toby
If I exit from it the container stops which is as expected.
But, when I put this in a script the root shell is still there and can be exited into
--- NOTE ---
Sorry, I got things mixed up.
This actually works as intended when I use the script as ENTRYPOINT
I didn't put username in the dockerfile as I want it be assigned on docker run as in
docker run -e USER=$USER myimage
When I do:
docker exec -ti myContainer /bin/bash
I have a new bash terminal on running container myContainer.
Now when I write
docker exec -ti lescompanions /bin/bash -c "echo youpi"
docker only outputs youpi and returns with no interactive terminal created. I was actually expecting docker to create the terminal and run echo youpi within the newly created terminal.
Where am I wrong?
---- EDIT ----
Now how shall I run echo youpi in the new terminal on the existing container and not have the terminal return to the host after the execution of echo youpi?
docker exec takes a command to run a process inside the container while the -it flag attaches an interactive session against that process.
Your session will only live as long as the command given to exec
As others have mentioned the command /bin/bash -c "echo youpi" simply uses bash to run the command echo "echo youpi" and terminates, hence your terminal session terminates also.
You are not doing anything wrong, it's just how bash works. I've checked it on my Ubuntu (without Docker):
$ /bin/bash
(no output, bash instance running)
$ /bin/bash -c "echo youpi"
youpi
(bash finished)
echo youpi is a command that is run inside the container. The echo command prints the arguments given to it, which is youpi in this case, and that is also what you see.
New to dockers, so please bear with me.
My Dockerfile contains an ENTRYPOINT:
ENV MONGOD_START "mongod --fork --logpath /var/log/mongodb.log --logappend --smallfiles"
ENTRYPOINT ["/bin/sh", "-c", "$MONGOD_START"]
I have a shell script add an entry to database through python script, and starts the server.
The script startApp.sh
chmod +x /addAddress.py
python /addAddress.py $1
cd /myapp/webapp
grunt serve --force
Now, all the below RUN commands are unsuccessful in executing this script.
sudo docker run -it --privileged myApp -C /bin/bash && /myApp/webapp/startApp.sh loc
sudo docker run -it --privileged myApp /myApp/webapp/startApp.sh loc
The docker log of container is
"about to fork child process, waiting until server is ready for connections. forked process: 7 child process started successfully, parent exiting "
Also, the startApp.sh executes fine when I open a bash prompt in docker and run it.
I am unable to figure out what wrong I am doing, help please.
I would suggest you to create an entrypoint.sh file:
#!/bin/sh
# Initialize start DB command
# Pick from env variable MONGOD_START if it exists
# else use the default value provided in quotes
START_DB=${MONGOD_START:-"mongod --fork --logpath /var/log/mongodb.log --logappend --smallfiles"}
# This will start your DB in background
${START_DB} &
# Go to startApp directory and execute commands
`chmod +x /addAddress.py;python /addAddress.py $1; \
cd /myapp/webapp ;grunt serve --force`
Then modify your Dockerfile by removing the last line and replacing it with following 3 lines:
COPY entrypoint.sh /
RUN chmod +x /entrypoint.sh
ENTRYPOINT ["/entrypoint.sh"]
Then rebuild your container image using
docker build -t NAME:TAG .
Now you run following command to verify if ENTRYPOINT is /entrypoint.sh
docker inspect NAME:TAG | less
I guess (and I might be wrong, since I'm neither a MongoDB nor a Docker expert) that your combination of mongod --fork and /bin/sh -c is the culprit.
What you're essentially executing is this:
/bin/sh -c mongod --fork ...
which
executes a shell
this shell executes a single command and waits for it to finish
this command launches MongoDB in daemon mode
MongoDB forks and immediately exits
The easiest fix is probably to just use
CMD ["mongod"]
like the official MongoDB Docker does.
I have a bash script that is supposed to execute other bash scripts using "docker exec" which are installed in different docker containers. Although each command works correctly when started manually, the script stops after the execution of first docker exec command.
Example:
#!/bin/bash
...
docker exec -it mysql_container /scripts/import_database.sh ## Scripts stops here...
docker exec -it web_container /scripts/copy_doc_root.sh
...
What am I missing? ;)
Thanks for your help!
David
Use docker exec -d since you neither want a terminal nor an interactive session.
I am trying to create a shell script for setting up a docker container. My script file looks like:
#!bin/bash
docker run -t -i -p 5902:5902 --name "mycontainer" --privileged myImage:new /bin/bash
Running this script file will run the container in a newly invoked bash.
Now I need to run a script file (test.sh)which is already inside container from the above given shell script.(eg: cd /path/to/test.sh && ./test.sh)
How to do that?
You can run a command in a running container using docker exec [OPTIONS] CONTAINER COMMAND [ARG...]:
docker exec mycontainer /path/to/test.sh
And to run from a bash session:
docker exec -it mycontainer /bin/bash
From there you can run your script.
Assuming that your docker container is up and running, you can run commands as:
docker exec mycontainer /bin/sh -c "cmd1;cmd2;...;cmdn"
I was searching an answer for this same question and found ENTRYPOINT in Dockerfile solution for me.
Dockerfile
...
ENTRYPOINT /my-script.sh ; /my-script2.sh ; /bin/bash
Now the scripts are executed when I start the container and I get the bash prompt after the scripts has been executed.
In case you don't want (or have) a running container, you can call your script directly with the run command.
Remove the iterative tty -i -t arguments and use this:
$ docker run ubuntu:bionic /bin/bash /path/to/script.sh
This will (didn't test) also work for other scripts:
$ docker run ubuntu:bionic /usr/bin/python /path/to/script.py
This command worked for me
cat local_file.sh | docker exec -i container_name bash
You could also mount a local directory into your docker image and source the script in your .bashrc. Don't forget the script has to consist of functions unless you want it to execute on every new shell. (This is outdated see the update notice.)
I'm using this solution to be able to update the script outside of the docker instance. This way I don't have to rerun the image if changes occur, I just open a new shell. (Got rid of reopening a shell - see the update notice)
Here is how you bind your current directory:
docker run -it -v $PWD:/scripts $my_docker_build /bin/bash
Now your current directory is bound to /scripts of your docker instance.
(Outdated)
To save your .bashrc changes commit your working image with this command:
docker commit $container_id $my_docker_build
Update
To solve the issue to open up a new shell for every change I now do the following:
In the dockerfile itself I add RUN echo "/scripts/bashrc" > /root/.bashrc". Inside zshrc I export the scripts directory to the path. The scripts directory now contains multiple files instead of one. Now I can directly call all scripts without having open a sub shell on every change.
BTW you can define the history file outside of your container too. This way it's not necessary to commit on a bash change anymore.
Thomio's answer is helpful but it expects the script to exist inside the image. If you have a one-of script that you want to run/test inside a container (from command-line or to be useful in a script), then you can use
$ docker run ubuntu:bionic /bin/bash -c '
echo "Hello there"
echo "this could be a long script"
'
Have a look at entry points too. You will be able to use multiple CMD
https://docs.docker.com/engine/reference/builder/#/entrypoint
If you want to run the same command on multiple instances you can do this :
for i in c1 dm1 dm2 ds1 ds2 gtm_m gtm_sl; do docker exec -it $i /bin/bash -c "service sshd start"; done
This is old, and I don't have enough reputation points to comment. Still, I guess it is worth sharing how one can generalize Marvin's idea to allow parameters.
docker exec -i mycontainer bash -s arg1 arg2 arg3 < mylocal.sh