i have a bunch files with data from a company and i need to count, let's say, how many people from a certain cities there are. Initially i was doing it manually with
grep -c 'Chicago' file.csv
But now i have to look for a lot cities and it would be time consuming to do this manually every time. So i did some reaserch and found this:
#!/bin/sh
for p in 'Chicago' 'Washington' 'New York'; do
grep -c '$p' 'file.csv'
done
But it doenst work. It keeps giving me 0s as output and im not sure what is wrong. Anyways, basically what i need is for an output with every result (just the values) given by grep in a column so i can copy directly to a spreadsheet. Ex.:
132
407
523
Thanks in advance.
You should use sort + uniq for that:
$ awk '{print $<N>}' file.csv | sort | uniq -c
where N is the column number of cities (I assume it structured, as it's CSV file).
For example, which shell how often used on my system:
$ awk -F: '{print $7}' /etc/passwd | sort | uniq -c
1 /bin/bash
1 /bin/sync
1 /bin/zsh
1 /sbin/halt
41 /sbin/nologin
1 /sbin/shutdown
$
From the title, it sounds like you want to count the number of occurrences of the string rather than the number of lines on which the string appears, but since you accept the grep -c answer I'll assume you actually only care about the latter. Do not use grep and read the file multiple times. Count everything in one pass:
awk '/Chicago/ {c++} /Washington/ {w++} /New York/ {n++}
END { print c; print w; print n }' input-file
Note that this will print a blank line instead of "0" for any string that does not appear, so you migt want to initialize. There are several ways to do that. I like:
awk '/Chicago/ {c++} /Washington/ {w++} /New York/ {n++}
END { print c; print w; print n }' c=0 w=0 n=0 input-file
Related
I have a text file with a large amount of data which is tab delimited. I want to have a look at the data such that I can see the unique values in a column. For example,
Red Ball 1 Sold
Blue Bat 5 OnSale
...............
So, its like the first column has colors, so I want to know how many different unique values are there in that column and I want to be able to do that for each column.
I need to do this in a Linux command line, so probably using some bash script, sed, awk or something.
What if I wanted a count of these unique values as well?
Update: I guess I didn't put the second part clearly enough. What I wanted to do is to have a count of "each" of these unique values not know how many unique values are there. For instance, in the first column I want to know how many Red, Blue, Green etc coloured objects are there.
You can make use of cut, sort and uniq commands as follows:
cat input_file | cut -f 1 | sort | uniq
gets unique values in field 1, replacing 1 by 2 will give you unique values in field 2.
Avoiding UUOC :)
cut -f 1 input_file | sort | uniq
EDIT:
To count the number of unique occurences you can make use of wc command in the chain as:
cut -f 1 input_file | sort | uniq | wc -l
awk -F '\t' '{ a[$1]++ } END { for (n in a) print n, a[n] } ' test.csv
You can use awk, sort & uniq to do this, for example to list all the unique values in the first column
awk < test.txt '{print $1}' | sort | uniq
As posted elsewhere, if you want to count the number of instances of something you can pipe the unique list into wc -l
Assuming the data file is actually Tab separated, not space aligned:
<test.tsv awk '{print $4}' | sort | uniq
Where $4 will be:
$1 - Red
$2 - Ball
$3 - 1
$4 - Sold
# COLUMN is integer column number
# INPUT_FILE is input file name
cut -f ${COLUMN} < ${INPUT_FILE} | sort -u | wc -l
Here is a bash script that fully answers the (revised) original question. That is, given any .tsv file, it provides the synopsis for each of the columns in turn. Apart from bash itself, it only uses standard *ix/Mac tools: sed tr wc cut sort uniq.
#!/bin/bash
# Syntax: $0 filename
# The input is assumed to be a .tsv file
FILE="$1"
cols=$(sed -n 1p $FILE | tr -cd '\t' | wc -c)
cols=$((cols + 2 ))
i=0
for ((i=1; i < $cols; i++))
do
echo Column $i ::
cut -f $i < "$FILE" | sort | uniq -c
echo
done
This script outputs the number of unique values in each column of a given file. It assumes that first line of given file is header line. There is no need for defining number of fields. Simply save the script in a bash file (.sh) and provide the tab delimited file as a parameter to this script.
Code
#!/bin/bash
awk '
(NR==1){
for(fi=1; fi<=NF; fi++)
fname[fi]=$fi;
}
(NR!=1){
for(fi=1; fi<=NF; fi++)
arr[fname[fi]][$fi]++;
}
END{
for(fi=1; fi<=NF; fi++){
out=fname[fi];
for (item in arr[fname[fi]])
out=out"\t"item"_"arr[fname[fi]][item];
print(out);
}
}
' $1
Execution Example:
bash> ./script.sh <path to tab-delimited file>
Output Example
isRef A_15 C_42 G_24 T_18
isCar YEA_10 NO_40 NA_50
isTv FALSE_33 TRUE_66
this is a file that i have named people.txt
10001:Larry Simpson:65:NewYork:555666777
10002:Jonh Fin:91:Rome:333444555
10003:George Jas:86:Amsterdam:777888999
10004:Larry Simpson:65:NewYork:555666777
10005:Jonh Fin:91:Rome:333444555
I was trying to count how many people there was on a specific city that is given as argument of the script.
First thing i thought was:
grep "$1:" people.txt | wc -l
The ":" was because we can have a city named Amster and another named Amsterdam.
But then I realized that we can have people named Amsterdam, so I tried this to search in cities column:
k=$(awk -F ":" -v loc=$1 -v max=0 ' {if ($4==loc) max++; print max}' people.txt)
echo $k
But now the output is like 0 0 1 1 1 and how can I have just the last digit of this output?
I also tried with cut but when doing -f we don´t know how long that output is.
Desired output is just
1
Regards
Assuming $1 is equal to "NewYork":
awk -F: -v loc="$1" '$4==loc { cnt++ } END { print cnt}' people.txt
You need to use the END block to print the final count.
You can just do it with a single grep command:
grep -Ec "^([^:]*:){3}$1:" people.txt
I have this csv file and I am trying to write shell script to calculate sum of column after doing group by on it. Column number is 11th (STATUS)
My script is
awk -F, 'NR>1{arr[$11]++}END{for (a in arr) print a, arr[a]}' $f > $parentdir/outputfile.csv;
File output expected is
COMMITTED 2
but actual output is just 2.
It prints only count and not group by sum. If I delete any other columns and run same query then it works fine but not with below sample data.
FILE NAME;SEQUENCE NR;TRANSACTION ID;RUN NUMBER;START EDITCREATION;END EDITCREATION;END COMMIT;EDIT DURATION;COMMIT DURATION;HAS DEPENDENCY;STATUS;DETAILS
Buldhana_Refinesource_FG_IW_ETS_000001.xml;1;4a032127-b20d-4fa8-9f4d-7f2999c0c08f;1;20180831130210345;20180831130429638;20180831130722406;140;173;false;COMMITTED;
Buldhana_Refinesource_FG_IW_ETS_000001.xml;2;e4043fc0-3b0a-46ec-b409-748f98ce98ad;1;20180831130722724;20180831130947144;20180831131216693;145;150;false;COMMITTED;
change the FS to ; in your script
awk -F';' 'NR>1{arr[$11]++}END{for (a in arr) print a, arr[a]}' file
COMMITTED 2
You're using wrong field separator. Use
awk -F\;
; must be escaped to use it as a literal. Except this, your approach seems OK.
Besides awk, you may also use
tail -n +2 $f | cut -f11 -d\; | sort | uniq -c
or
datamash --header-in -t \; -g 11 count 11 < $f
to do the same thing.
I would like to count the number of students in a .csv file depending on the category
Category 1 is the name, Category 2 is the country, Category 3 is the city
The .csv file is displayed as such :
michael_s;jpa;NYC
john_d;chn;TXS
jim_h;usa;POP
I have tried in my .sh script but it didn't work
sort -k3 -t; students.csv
edit:
I am trying to make a bash script that counts students by city and something that can also count one city just by executing the script such as
cat students.csv | ./script.sh NYC
The terminal will only display the students from NYC
If I've understood you correctly, something like this?
cut -d";" -f3 mike.txt | sort | uniq -c
(Sorry, incorrect solution first time - updated now)
To count only one city:
cut -d";" -f3 mike.txt | grep "NYC" | wc -l
Depending on the size of the file, how often you'll be doing this etc. it may be sensible to look at other solutions, eg. awk. But this solution will work just fine.
The reason for the error message "sort: multi-character tab 'students.csv'" is you haven't given the -t option the separator character. If you add a semicolon after -t, the sort will work as expected:
sort -k3 -t';' students.csv
There is always awk:
$ awk -F\; 'a[$1]++==0{c++}END{print c}' file
3
Once you describe your requirements more throughly, (count the names but sort -k3. Update the OP, please) we can help you better.
Edited to match your update:
$ awk -F\; -v col=3 -v val=NYC '
(length(val) && $col==val) || length(val)==0 && a[$col]++==0 {
c++
}
END { print c }
' file
1
If you set -v val= with the value you are looking for and -v col= with the column number, it counts the occurrences of val in col. You you set col but not val ot counts different values in col.
Is there any way to extract the unique characters of each line?
I know I can find the unique lines of a file using
sort -u file
I would like to determine the unique characters of each line (something like sort -u for each line).
To clarify: given this input:
111223234213
111111111111
123123123213
121212122212
I would like to get this output:
1234
1
123
12
Using sed
sed ':;s/\(.\)\(.*\)\1/\1\2/;t' file
Basically what it does is capture a character and check if it appears anywhere else on the line. It also captures all the characters between these.
Then it replaces all of that including the second occurence with just first occurence and then what was inbetween.
t is test and jumps to the : label if the previous command was successful. Then this repeats until the s/// command fails meaning only unique characters remain.
; just separates commands.
1234
1
123
12
Keeps order as well.
It doesn't get things in the original order, but this awk one-liner seems to work:
awk '{for(i=1;i<=length($0);i++){a[substr($0,i,1)]=1} for(i in a){printf("%s",i)} print "";delete a}' input.txt
Split apart for easier reading, it could be stand-alone like this:
#!/usr/bin/awk -f
{
# Step through the line, assigning each character as a key.
# Repeated keys overwrite each other.
for(i=1;i<=length($0);i++) {
a[substr($0,i,1)]=1;
}
# Print items in the array.
for(i in a) {
printf("%s",i);
}
# Print a newline after we've gone through our items.
print "";
# Get ready for the next line.
delete a;
}
Of course, the same concept can be implemented pretty easily in pure bash as well:
#!/usr/bin/env bash
while read s; do
declare -A a
while [ -n "$s" ]; do
a[${s:0:1}]=1
s=${s:1}
done
printf "%s" "${!a[#]}"
echo ""
unset a
done < input.txt
Note that this depends on bash 4, due to the associative array. And this one does get things in the original order, because bash does a better job of keeping array keys in order than awk.
And I think you've got a solution using sed from Jose, though it has a bunch of extra pipe-fitting involved. :)
The last tool you mentioned was grep. I'm pretty sure you can't do this in traditional grep, but perhaps some brave soul might be able to construct a perl-regexp variant (i.e. grep -P) using -o and lookarounds. They'd need more coffee than is in me right now though.
One way using perl:
perl -F -lane 'print do { my %seen; grep { !$seen{$_}++ } #F }' file
Results:
1234
1
123
12
Another solution,
while read line; do
grep -o . <<< $line | sort -u | paste -s -d '\0' -;
done < file
grep -o . convert 'row line' to 'column line'
sort -u sort letters and remove repetead letters
paste -s -d '\0' - convert 'column line' to 'row line'
- as a filename argument to paste to tell it to use standard input.
This awk should work:
awk -F '' '{delete a; for(i=1; i<=NF; i++) a[$i]; for (j in a) printf "%s", j; print ""}' file
1234
1
123
12
Here:
-F '' will break the record char by char giving us single character in $1, $2 etc.
Note: For non-gnu awk use:
awk 'BEGIN{FS=""} {delete a; for(i=1; i<=NF; i++) a[$i];
for (j in a) printf "%s", j; print ""}' file
This might work for you (GNU sed):
sed 's/\B/\n/g;s/.*/echo "&"|sort -u/e;s/\n//g' file
Split each line into a series of lines. Unique sort those lines. Combine the result back into a single line.
Unique and sorted alternative to the others, using sed and gnu tools:
sed 's/\(.\)/\1\n/g' file | sort | uniq
which produces one character per line; If you want those on one line, just do:
sed 's/\(.\)/\1\n/g' file | sort | uniq | sed ':a;N;$!ba;s/\n//g;'
This has the advantage of showing the characters in sorted order, rather than order of appearance.