I'm working on a maven project using Spring framework.
Instead of writing raw text in JSPs I prefer to use <spring:message .../> tag and register my messages in a .properties file.
I get this warning when requesting a page :
ResourceBundle [messages] not found for MessageSource: Can't
find bundle for base name messages, locale fr
Which then brings an exception about the message not being found (obviously).
Here's my project's hierarchy :
my project's hierarchy
Here's my springapp-servlet.xml :
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.3.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-2.5.xsd">
<context:component-scan base-package="app.core" />
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/">
</property>
<property name="suffix" value=".jsp">
</property>
</bean>
<bean id="localeResolver" class="org.springframework.web.servlet.i18n.SessionLocaleResolver">
<property name="defaultLocale" value="fr" />
</bean>
<bean id="messageSource"
class="org.springframework.context.support.ResourceBundleMessageSource">
<property name="basenames">
<list>
<value>messages</value>
</list>
</property>
</bean>
<mvc:resources mapping="/public/**" location="/WEB-INF/resources/"
cache-period="31556926"/>
<mvc:annotation-driven />
</beans>
From the documentation:
The basenames follow ResourceBundle conventions: essentially, a fully-qualified classpath location. If it doesn't contain a package qualifier (such as org.mypackage), it will be resolved from the classpath root.
(emphasis mine)
So it should be under src/main/resources.
Related
I have a spring mvc application that works on oracle server, I am currently using the spring JPA to store and retrieve data. can i move from oracle sql to couchbase server just by changing the data source, If so how do I configure my datasource to work with couchbase
The bean definition is as follows
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jdbc="http://www.springframework.org/schema/jdbc"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc-3.1.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/tx/ http://www.springframework.org/schema/tx/spring-tx-3.2.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa-1.2.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<context:component-scan base-package="org.test.project"></context:component-scan>
<context:property-placeholder location="classpath:application.properties" ></context:property-placeholder>
<jpa:repositories base-package="org.test.project"
entity-manager-factory-ref="entityManagerFactoryBean"></jpa:repositories>
<bean id="dbClassImpl" class="org.test.project.DbClassImpl" />
<!--EntityManagerFactory -->
<bean id="entityManagerFactoryBean"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="org.test.project" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" >
<property name="showSql" value="true"/>
</bean>
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.hbm2ddl.auto">update</prop>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
</props>
</property>
</bean>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
<property name="url" value="someurl" />
<property name="username" value="username" />
<property name="password" value="password" />
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactoryBean" />
</bean>
<tx:annotation-driven proxy-target-class="true" />
Here is the official documentation about it https://docs.spring.io/spring-data/couchbase/docs/current/reference/html/#configuration-xml
However, you will need to change a few extra things to make it work:
1 - One of the main advantages of Document Databases is to avoid unnecessary joins. If you simply transition from relational to Document without changing your model, you won't get the most of it. (https://blog.couchbase.com/json-data-modeling-rdbms-users/)
2 - Couchbase don't support LocaDateTime/ZonnedDateTime yet, you will need to write a converter.
3 - Your repositories should have a few extra annotations
(https://blog.couchbase.com/couchbase-spring-boot-spring-data/)
4 - If you are using JPQL, you will need to slightly modify it to use the N1QL syntax (https://docs.spring.io/spring-data/couchbase/docs/current/reference/html/#couchbase.repository.n1ql)
I am developing an utility in Spring batch will read data from Mysql/Oracle and write it to the Redis database.
Currently we still using Spring Batch XML based configurations (we still like the XML based - gives little control to us :))
When I configured the following I see most of the methods are deprecated.
<bean id="redisDataSource" class="org.springframework.data.redis.connection.jedis.JedisConnectionFactory">
<property name=""></property>
</bean>
using following versions of dependencies:
<properties>
<maven.compiler.source>1.8</maven.compiler.source>
<maven.compiler.target>1.8</maven.compiler.target>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<spring-batch-vesion>4.0.1.RELEASE</spring-batch-vesion>
<mysql.version>8.0.11</mysql.version>
<logback.version>1.2.3</logback.version>
<jcl.slf4j.version>1.7.25</jcl.slf4j.version>
<quartz.version>2.2.1</quartz.version>
<spring.version>5.0.0.RELEASE</spring.version>
<lombok.version>1.18.0</lombok.version>
<jedis.version>2.9.0</jedis.version>
</properties>
Could anyone please suggest XML based configurations which I should used to configured the dataSource ?
I've taken a reference from the link: https://docs.spring.io/spring-data/redis/docs/2.0.8.RELEASE/reference/html/, but its not clear to me.
STS snippet:
After lot of research and googling found the below useful links :
Weird redis key with spring data Jedis
Spring Data RedisTemplate: Serializing the Value and HashValue
https://github.com/hantsy/spring-sandbox/blob/master/spring-cache/src/main/java/com/hantsylabs/example/spring/config/applicationContext-jpa-redis.xml
Get Set value from Redis using RedisTemplate
Here is the code snippet:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:p="http://www.springframework.org/schema/p" xmlns:task="http://www.springframework.org/schema/task"
xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/task http://www.springframework.org/schema/task/spring-task.xsd">
<bean id="jedisPoolConfig" class="redis.clients.jedis.JedisPoolConfig">
<property name="maxTotal" value="200" />
<property name="maxIdle" value="50" />
<property name="maxWaitMillis" value="3000" />
<property name="testOnBorrow" value="true" />
</bean>
<bean id="jedisFactory" class="org.springframework.data.redis.connection.jedis.JedisConnectionFactory">
<property name="hostName" value="${redis_ip}" />
<property name="port" value="${redis_port}" />
<property name="poolConfig" ref="jedisPoolConfig" />
<property name="usePool" value="true" />
</bean>
<bean id="stringRedisSerializer" class="org.springframework.data.redis.serializer.StringRedisSerializer" />
<bean id="redisTemplate" class="org.springframework.data.redis.core.RedisTemplate" p:connection-factory-ref="jedisFactory" p:valueSerializer-ref="stringRedisSerializer"
p:keySerializer-ref="stringRedisSerializer" />
</beans>
Or Simply used https://docs.spring.io/spring-integration/reference/html/redis.html
I'm working on a spring and JPA project. I had configured my JPA Persistence Unit in the Persistence.xml and here's my spring configuration file.
My application works fine, but I didn't understand how does spring framework detects the Persistence Unit defined in my Persistence.xml file and injects it without being defined in my spring bean configuration file .
Can anybody answer me please ?
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd">
<context:annotation-config/>
<context:component-scan base-package="ma.professionalpartners.fireAppBusiness.dao"/>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="fireApp-Domain" />
</bean>
<bean id="jpaTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<tx:annotation-driven transaction-manager="jpaTransactionManager" />
</beans>
You have provided the name for the persistence unit, when configuring the entityManagerFactory bean:
<property name="persistenceUnitName" value="fireApp-Domain" />
The persistence.xml file MUST be on certain paths, so that Spring simply searched in those locations. After finding the file, it parses the XML content, and if there is a single PersistenceUnit, that is made the default one. Of course, if you specify a name (as you did), then it looks exactly for that PersistenceUnit.
I'm facing a very weird issue. I'm tring to configure the properties of my datasource declared in my spring applicationcontext.xml file via a PropertyPlaceholderConfigurer class. The application context file looks like this:-
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:ws="http://jax-ws.dev.java.net/spring/core" xmlns:wss="http://jax-ws.dev.java.net/spring/servlet"
xmlns:jms="http://www.springframework.org/schema/jms"
xsi:schemaLocation="http://jax-ws.dev.java.net/spring/servlet http://jax-ws.dev.java.net/spring/servlet.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://jax-ws.dev.java.net/spring/core http://jax-ws.dev.java.net/spring/core.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/jms http://www.springframework.org/schema/jms/spring-jms-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.4.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- Spring configurations used by LCM Impl classes -->
<bean id="lcmPropertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:/activemq.properties</value>
<value>classpath:/jdbc.properties</value>
</list>
</property>
</bean>
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy- method="close">
<property name="driverClassName" value="${db.driverClassName}" />
<property name="url" value="${db.url}"/>
<property name="username" value="${db.username}"/>
<property name="password" value="${db.password}"/>
</bean>
<bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate">
<property name="dataSource" ref="dataSource"/>
</bean>
</beans>
I have tried using the context:property-placeholder tag as well but it doesn't seem to have any effect. The above mentioned properties files are deployed successfully under the WEB-INF/classes directory as well.
For some reason, the spring container is able to load the properties files(checked with an invalide properties file and it throws a FNF exception) but not able to substitute the property placeholders with their values.
I'm using a tomcat 7 WS with the CATALINA.BASE pointing to my runtime. Has anybody faced this issue before? Any solutions?
Take that leading slash out of the values:
<value>classpath:activemq.properties</value>
<value>classpath:jdbc.properties</value>
Try the following configuration.
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:activemq.properties</value>
<value>classpath:jdbc.properties</value>
</list>
</property>
</bean>
The issue is likely the fact that you even named the PropertyPlaceholderConfigurer bean. Most Spring internal beans are not given an id, as the framework is configured to look for certain bean names, and often the default bean name is the auto-generated name based on the object type.
Fairly new to Spring, so I'm having some trouble with this. I'm trying to use LDAP security with Spring. I can use a properties file I created inside the webapp itself. But what I would like to do is load and read the context.xml file of the server (it has all the values I need for this and other applications).
This is what I have:
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="ignoreUnresolvablePlaceholders" value="true"/>
</bean>
<bean class="org.springframework.web.context.support.ServletContextPropertyPlaceholderConfigurer">
<property name="systemPropertiesModeName" value="SYSTEM_PROPERTIES_MODE_OVERRIDE"/>
<property name="searchContextAttributes" value="true"/>
<property name="contextOverride" value="true"/>
<property name="ignoreResourceNotFound" value="true"/>
<property name="locations">
<list>
<value>/WEB-INF/properties/dataUploadProperties.properties</value>
<value>/WEB-INF/properties/globalProperties.properties</value>
<value>context.xml</value>
</list>
</property>
</bean>
I'm able to load and read the 2 properties files, but the context.xml is not found. Does it need to be the absolute path on the server?
Thanks
Chris
So the first thing I would recommend is to use Spring Security. It has an already build in LDAP support.
but the context.xml is not found
Normally this (reading the context.xml directly) is not the way you should go.
Instead, define some properties and or JNDI resources in the context.xml and then use them in the spring configuration.
For example:
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/jee
http://www.springframework.org/schema/jee/spring-jee-3.0.xsd">
<!-- access via jndi -->
<jee:jndi-lookup id="jndiEmailSession"
jndi-name="java:comp/env/email/session/myEmailSession" />
<!-- direct access for properties required the SERVLET contect property
place older configurer, then it works like properties from normal
property files -->
<bean class="org.springframework.web.context.support.ServletContextPropertyPlaceholderConfigurer"> <property name="locations" value="classpath*:META-INF/spring/*.properties" /> </bean>
<bean class=Demo>
<property name="someString" value="${simpleValue}" />
</bean>
</beans>
context.xml:
<Resource name="email/session/myEmailSession"
type="javax.mail.Session"
auth="Container"
password="secret"
mail.debug="false"
mail.transport.protocol="smtp"
mail.smtp.auth="true"
mail.smtp.user="test#example.com"
mail.smtp.host="mail.example.com"
mail.smtp.from="test#example.com"/>
<Parameter name="simpleValue" value="any" override="false" />