I know you can do an import inside a class like this:
.my-class
{
#import "another-file.scss";
}
Such that a class .foo in another-file.scss will compile to .my-class .foo in the output.
What I want to do is import a file such that all the rules in the file get a certain class added to them, like this:
.my-class
{
&#import "another-file.scss";
}
Such that .foo in another-file.scss will compile to .my-class.foo in the output.
I'm building a set of components that all share a class because they are all part of the same "kit", and I want them all to share a class that denotes them as such, but I don't want to have them all in the same file under one giant nest.
Is this possible?
Thanks!
To accomplish this, you just need to preface the selectors in the file you are importing with &.
For example, if you were to import the following file, it would create rules for .my-class.header, my-class.header.cool and my-class.footer:
&.header {
color: blue;
&.cool {
font-size: 20px;
}
}
&.footer {
color: blue;
}
Related
I'm having a little issue with SASS #extend, placeholder class and interpolation.
I'm trying to keep the HTML as clean as possible and that's I decided to go for the #extend function in pair with placeholder classes. However, I'm mainly extending layout-related classes like grid, list etc - that's why I'm mixing a placeholder with a regular class in the declaration, i.e:
%drawer,
.drawer {
...
}
Everything was going just fine except for a moment when I noticed the interpolation with the variable being the ampersand in the main class causes some issues. Sample code (with most of the CSS rules removed):
%drawer,
.drawer {
$this: &;
position: fixed;
z-index: 10;
&__content {
right: 0;
transform: translate(100%, 0);
}
&__optional-element {
background: red;
}
&--left { // I want this modifier to be applied to the parent element as it may affect more than one children element
#{$this}__content {
left: 0;
transform: translate(-100%, 0);
}
}
}
And the extension code:
.product-drawer {
#extend %drawer;
&__content {
#extend %drawer__content;
}
}
However, the compiled CSS output is the following:
.drawer--left .product-drawer,
.drawer--left .drawer__content {
left: 0;
transform: translate(-100%, 0);
}
You may notice the first line is redundant and actually wrong. In addition, the "&__optional-element" bit is not outputted for the "product-drawer" extension which makes it really strange. It happens only to rules with the $this interpolation.
As soon as I remove the regular ".drawer" class from the original declaration (and just leave %drawer there), the problem is gone but in these layout-related classes (.grid, .list), we want to keep the regular class name as well so in some various, simple cases it can be used as well, without a need to write new CSS and extending it the placeholder class.
I know that this could be resolved by separating the placeholder class (%drawer) from the regular one (.drawer) completely and then extend the placeholder class inside the regular ".drawer" declaration but that would simply duplicate the code... Or maybe my approach is wrong by design?
Thank you!
The problem is not the #extend rule. The thing is that placeholders are a shallow copy of a class. If you extend from a class you are going to inherit all its properties, but if you extend from a placeholder it is only going to copy the first level.
See this example:
%placeholder{
content: 'placeholder';
&__element{
content: 'placeholder__element';
}
}
.a{
#extend %placeholder;
}
.class{
content: 'class';
&__element{
content: 'class__element';
}
}
.b{
#extend .class;
}
.a {
content: 'placeholder';
}
.class, .b {
content: 'class';
}
.class__element {
content: 'class__element';
}
By using both you're forcing placeholder class to use also the properties:
%placeholder,
.class{
content: 'class';
&__element{
content: 'class__element';
}
}
.b{
#extend %placeholder;
}
.b,
.class {
content: 'class';
}
.class__element {
content: 'class__element';
}
Searched but can't find an answer..
I have an element which gets generated (by an external platform) with the following classes: p-button and button.
Now the SCSS is like this:
.p-button {
&.button {
margin: 10px;
}
}
But I want to refactor using mixin includes (this is a big project so there is no other way of making this code better except using mixins). The mixin takes the given selector and applies a . to it. I can't change the mixin, as it is used by many other teams, so I can't pass the ampersand together with the selector. I tried this:
.p-button {
& {
#include button-appearance("button") {
margin: 10px;
}
}
}
But that doesn't work (puts a space between it). You can't do this:
.p-button {
&#include button-appearance("button") {
margin: 10px;
}
}
Anyone have a clue?
EDIT: Here is the mixin
#mixin button-appearance(
$appearance-class,
$show,
$background-color,
$background-image,
$background-position) {
$sel: $button-selector;
#if $appearance-class {
$sel: $sel + '.' + $appearance-class;
}
#{$sel} {
#include normalized-background-image($background-image);
#include show($show);
background-color: $background-color;
background-position: $background-position;
}
#content;
}
EDIT 2: Here is the $button-selector (I can not edit this in the platform, but maybe overwrite it in my own project?)
$button-class: 'p-button';
$button-selector: '.#{$button-class}';
Everyone, finally found the solution. I just removed the &.button from the .p-button mixin include and now it works:
#include button-appearance ("button") { *styles* }
#include button-appearance () { *styles* }
Edited the answer after the original question was edited adding the used and un modifiable mixin
The original mixin does not append the ‘#content’ passed to the mixin to the generated selector. So if you cannot modify the original mixin, the only way is to add your properties outside the mixin. According to the mixin the selector will match a predefined ‘$button-selector’ variable, so it won’t use your class.
So, if you want to use the same class defined in ‘$button-class’, try the following:
#{$button-selector}.button {
margin: 10px;
}
Will output:
.p-button.button {
margin: 10px;
}
I have Bootstrap 3.3.7 and custom scss files.
I want to override $grid-float-breakpoint only once before #extend evaluates. Right now I have 3 classes which extend base bootstrap class (they use default value, so i don't want to mess with them).
In doc when using mixins and include it's possible. Is it possible using .class and #extend?
I'm looking for something like
$foo : 1px;
.normal-class {
font-size: $foo;
}
.extended-normal-class {
#extend .normal-class;
font-color: yellow;
}
-- This is what I'm trying to do: ---------------------
.override-class {
$foo: 3px;
#extend .normal-class;
// font-size in this class after compile should have 3px;
}
To achiev what you need, you must use #mixin instead of #extend, heres follow an example:
#mixin size($size: 1px){
font-size: $size;
}
.extended-normal-class{
#include size();
}
.override-class{
#include size(3px);
}
I am working on a project where there is a main style.scss file for a number of components. I want to restructure the code so as every component has its own folder (index.js, styles.scss). There is a nested class that is using a class from another component and now that I have to separate all the styles, this part is broken. I can't use composition since it is a nested class. What other approaches can I take?
The code looks like this:
// Component A styless.scss
.component-a-class {
}
// Component B styless.scss
.component-b-class{
.component-a-class {
}
}
Use Sass's #import directive to import the external classes. Your code would become something like this:
// ComponentA/styless.scss
.component-a-class {
...
}
// ComponentB/styless.scss
.component-b-class{
#import "../ComponentA/styless.scss"
}
This will inject .component-a-class into the .component-b-class as a nested rule.
Edit: To import a style and also be able to modify one of its properties' values, you have to make use of Sass mixins:
// ComponentA/styless.scss
#mixin component-a-class($width: 100) {
.component-a-class {
width: $width + px;
}
}
#include component-a-class();
// ComponentB/styless.scss
#import "../ComponentA/style.scss";
.component-b-class{
#include component-a-class(500);
}
This will get you what you want, though it isn't ideal. The resulting compiled ComponentB/styless.css file will include everything written in ComponentA/styless.scss because the #import directive is an "all-or-nothing" feature (there is no selective import). The result would look like this:
// ComponentB/styless.css (compiled)
.component-a-class {
width: 100px;
}
.component-b-class .component-a-class {
width: 500px;
}
In addition to application.css.scss, I have multiple partials like homepage.css.scss. At the moment I have to add #import 'bootstrap' to each one of them in order to use bootstrap variables and mixins.
Let's say I want to change my default links colour to red, I'd add that to application.css.scss. But the links in homepage.css.scss will not be red because the bootstrap import will override it with blue.
In LESS, I can do #import (reference) "bootstrap", how can I do that in SASS?
The closest you will get is a silent class / placeholder. These work a little different to how LESS and reference work, you can read more on them here: http://blog.teamtreehouse.com/extending-placeholder-selectors-with-sass
LESS
lib.less
.class {
background: red;
}
main.less
#import (reference) "lib";
.anotherClass {
&:extend(.class);
}
SASS
lib.sass
%class {
background: red;
}
main.sass
#import "lib";
.anotherClass {
#extend %class;
}
CSS Output
.anotherClass {
background: red;
}