Virtualenvwrapper mkvirtualenv command not found via ansible shell - ansible

Question

I want to create a virtualenv with virtualenvwrapper via ansible.
My default vars:
wrapper_bin: '/usr/local/bin/virtualenvwrapper.sh'
virtualenv_dir: '/home/user/.envs'
{{ project_name }} comes from extra variable
My task:
---
- name: Make a virtualenv
shell: "{{ wrapper_bin }} && mkvirtualenv {{ project_name }}"
args:
executable: /bin/bash
creates: "{{ virtualenv_dir}}/{{ project_name }}"
On a remote machine all works well.
which virtualenvwrapper.sh returns correct way /usr/local/bin/virtualenvwrapper.sh
But Ansible throw an error /bin/bash: mkvirtualenv: command not found

Answer 1

Add PATH to the environment, for example:
---
- name: Make a virtualenv
shell: "{{ wrapper_bin }} && mkvirtualenv {{ project_name }}"
args:
executable: /bin/bash
creates: "{{ virtualenv_dir}}/{{ project_name }}"
environment:
path: /usr/local/bin:/usr/bin:/bin
It is one of the most common problems with Ansible - it runs shell non-interactive, non-logon session which by shell design does not source all the rc-files. In result the PATH you have when logged on interactively and the PATH Ansible gets in its environment differ.

Answer 2

- name: Make a virtualenv
shell: export PATH=$PYENV_ROOT/bin:$PATH mkvirtualenv {{ project_name }}
If you use pyenv.

Answer 3

This works for me
- name: Create the required virtualenv
shell: |
export WORKON_HOME="{{ virtualenv_dir }}"
export VIRTUALENVWRAPPER_PYTHON=/usr/bin/python3
. /usr/local/bin/virtualenvwrapper.sh
mkvirtualenv "{{project_name}}" -p python3.6
args:
executable: /bin/bash
creates: "{{ virtualenv_dir}}/{{ project_name }}"
register: appServer_virtualenv
become_user: "{{sudo_user}}"