Would love to know how other people are achieving the following?
Tables:
teams
teams_users (pivot many teams, many users)
users
What i am trying to achieve
$teams->user->where('user_id', $id)->get();
however i am having to run a loop, and create another method on the team model to pluck(id, name)
// foreach ($teams as $team) {
// # code...
// dump($team->getUserIdsAttribute());
// }
Do you know a better way?
If you are trying to get all teams with a specific a user id. Try
$teams = Team::with(['users' => function ($query) use ($id) {
$query->where('id', '=', $id);
}])->get();
Or through the user
$user = User::with('teams')->find($id);
This is assuming you already defined the belongsToMany() relationship in each model.
Maybe you will like to do it in the more traditional way
use Illuminate\Database\Eloquent\Builder;
$team = Team::whereHas('user',function(Builder $query) use ($id){
$query->where( 'user_id' , $id );
})->get();
Related
I have two tables with belongsToMany relation: message_topics and users
The pivot table is message_topics_users and contains 2 columns: message_id and user_id.
In table message_topics, I have a field called sender_id
I'm trying to write the correct eloquent syntax to get all the records:
where message_topics.sender_id = $user_id
OR Message_topics_users.receiver_id = $user_id
I tried many things, like for instance:
$topics = MessageTopic::where('sender_id', $user_id)
->wherePivot('receiver_id', $user_id)->orderBy('sent_at','desc')->get();
Any idea?
You can use the whereHas method (or in this case the orWhereHas method):
$topics = MessageTopic::where('sender_id', $user_id)
->orWhereHas('users', function ($query) use ($user_id) {
$query->where('id', $user_id);
})
->orderBy('sent_at', 'desc')
->get();
I'm assuming you have two relationships from the topics? Since it's too arbitrary to use both columns and the same relationship... Like this
//On your MessageTopic model
public function sender(){
return $this->belongsToMany('App\User', 'message_topics_users', 'message_id', 'sender_id');
}
public function receiver(){
return $this->belongsToMany('App\User', 'message_topics_users', 'message_id', 'receiver_id'));
}
Then you can use whereHas and orWhereHas like this:
//Again assuming you have your User model loaded as $user
$topics = App\Topic::whereHas('sender', function($q) use($user){
$q->where('sender_id', '=', $user->id);
})
->orWhereHas('receiver', function($q) use($user){
$q->where('receiver_id', '=', $user->id
})
->orderByDesc('sent_at')
->get();
whereHas and orWhereHas both query the model (MessageTopic in this case) checking for the existence of the specified relationship (App\Topic::whereHas('sender')...). They also allow you to pass the constraint that you're looking for (function($q) use($user){ $q->... })
So it is basically saying "Give me ONLY the MessageTopics that have a Sender or Receiver with the id $user->id"
Hi all,
I'm building an application in Laravel, I want to get all item in an article category without using this Eloquent.
My code is
$info = Article::find($article_id);
$cate_info = $info->article_categories()->first();
if($cate_info){
$same = Article::with(['article_categories' => function ($query) use ($cate_info){
$query->where('articles_category.ID' ,$cate_info->ID);
}])->where('ID' ,'!=' ,$article_id)->get();
}
And I get all articles. How to solve.
Article and Article_Category is in many to many relationship.
Thanks.
If you want to have all the articles of a particular article_categories you can use whereHas method, now suppose you have name as a field column in categories table, so you can have something like this:
public function getData(Request $request)
{
$category = $request->categoryName;
// $category = 'ABC Category';
$articles = Article::whereHas('article_categories', function($query) use($category) {
$query->where('name', 'like', '%'.$category.'%');
})->get();
return response()->json(['articles' => $articles], 200);
}
Hope this helps.
I want to sort users based on the specific value. For example I have Users table and has relation with Profiles Table. In the Profiles table I have saved Country (string) of the user.
Now I want to sort specific country users first and then the other country Users.
Please guide me how can I do this in Laravel.
Thanks
You can play with that code.
$users = Users::with(['profiles' => function ($query) {
$query->where('country', 'USA');
$query->orWhere('country', 'Poland')
}])->get();
I have not check this but You may try this solution. It will help you.
$users = Users::with(['profiles' => function ($query) {
$query->orderBy("country='your country name'", 'DESC')
$query->orderBy('country', 'ASC')
}])->get();
You can use this
$users = Users::with(['profiles' => function ($query) use($country) {
$query->orderBy(DB::raw('case when country="'.$country.'" then 1 else 2 end'))->orderBy('country', 'ASC');
}])->get();
here is link to my database schema:
How can I get all topics from the blogs to which the user is subscribed using his id? I use Eloquent ORM.
I have added the following lines to my User model:
public function blogs()
{
return $this->belongsToMany('Blog', 'blog_subscriptions');
}
And then requested in the controller
User::find(1)->blogs; // User id is hardcoded
With that I got all blogs to which the user is subscribed.
And now I am stuck on how to get the topics of those blogs.
Assuming relations:
// User
belongsToMany('Blog', 'user_subscriptions')
// Blog
belongsToMany('User', 'user_subscriptions')
hasMany('Topic')
// Topic
belongsTo('Blog')
1 My way, that will work with any relation, no matter how deeply nested:
User::with(['blogs.topics' => function ($q) use (&$topics) {
$topics = $q->get()->unique();
}])->find($userId);
2 Eloquent standard methods:
$topics = Topic::whereHas('blog', function ($q) use ($userId) {
$q->whereHas('users', function ($q) use ($userId) {
$q->where('users.id', $userId);
});
})->get();
// or
$user = User::find($userId);
foreach ($user->blogs as $blog)
{
$blog->topics; // collection of topics for every single blog
}
3 Joins:
$topics = Topic::join('blogs', 'topics.blog_id', '=', 'blogs.id')
->join('user_subscriptions as us', function ($j) use ($userId) {
$j->on('us.blog_id', '=', 'blogs.id')
->where('us.user_id', '=', $userId);
})->get(['topics.*']);
Mind that last solution will rely on your pivot data consistency. That said, if you can't be sure, that there are no redundant entries in user_subscriptions (eg. blog or user has been deleted but the pivot entry remains), then you need to further join users as well.
I am new to laravel and I don't have the possibility of test this, but I had a similar need and solved it with something like this:
DB::Query('topics')->join('blogs', 'blogs.id', '=', 'topics.blog_id')
->join('blog_subscriptions', 'blogs.id', '=', 'blog_subscriptions.blog_id')
->select('name.id','table.email')
->where('blog_subscriptions.user_id', '=', $user_id);
In Laravel we can setup relationships like so:
class User {
public function items()
{
return $this->belongsToMany('Item');
}
}
Allowing us to to get all items in a pivot table for a user:
Auth::user()->items();
However what if I want to get the opposite of that. And get all items the user DOES NOT have yet. So NOT in the pivot table.
Is there a simple way to do this?
Looking at the source code of the class Illuminate\Database\Eloquent\Builder, we have two methods in Laravel that does this: whereDoesntHave (opposite of whereHas) and doesntHave (opposite of has)
// SELECT * FROM users WHERE ((SELECT count(*) FROM roles WHERE user.role_id = roles.id AND id = 1) < 1) AND ...
User::whereDoesntHave('Role', function ($query) use($id) {
$query->whereId($id);
})
->get();
this works correctly for me!
For simple "Where not exists relationship", use this:
User::doesntHave('Role')->get();
Sorry, do not understand English. I used the google translator.
For simplicity and symmetry you could create a new method in the User model:
// User model
public function availableItems()
{
$ids = \DB::table('item_user')->where('user_id', '=', $this->id)->lists('user_id');
return \Item::whereNotIn('id', $ids)->get();
}
To use call:
Auth::user()->availableItems();
It's not that simple but usually the most efficient way is to use a subquery.
$items = Item::whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
})
->get();
If this was something I did often I would add it as a scope method to the Item model.
class Item extends Eloquent {
public function scopeWhereNotRelatedToUser($query, $user_id)
{
$query->whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
});
}
}
Then use that later like this.
$items = Item::whereNotRelatedToUser($user_id)->get();
How about left join?
Assuming the tables are users, items and item_user find all items not associated with the user 123:
DB::table('items')->leftJoin(
'item_user', function ($join) {
$join->on('items.id', '=', 'item_user.item_id')
->where('item_user.user_id', '=', 123);
})
->whereNull('item_user.item_id')
->get();
this should work for you
$someuser = Auth::user();
$someusers_items = $someuser->related()->lists('item_id');
$all_items = Item::all()->lists('id');
$someuser_doesnt_have_items = array_diff($all_items, $someusers_items);
Ended up writing a scope for this like so:
public function scopeAvail($query)
{
return $query->join('item_user', 'items.id', '<>', 'item_user.item_id')->where('item_user.user_id', Auth::user()->id);
}
And then call:
Items::avail()->get();
Works for now, but a bit messy. Would like to see something with a keyword like not:
Auth::user()->itemsNot();
Basically Eloquent is running the above query anyway, except with a = instead of a <>.
Maybe you can use:
DB::table('users')
->whereExists(function($query)
{
$query->select(DB::raw(1))
->from('orders')
->whereRaw('orders.user_id = users.id');
})
->get();
Source: http://laravel.com/docs/4.2/queries#advanced-wheres
This code brings the items that have no relationship with the user.
$items = $this->item->whereDoesntHave('users')->get();